Updating Value of Multidimensional Array of Object

function update(child, indices, value) {    indices.reduce((o, i) => o.child[i], { child }).text = value;}
var array = [{ text: "something", child: [{ text: "something child", child: [] }] }];
update(array, [0, 0], 'foo');
console.log(array);

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How to update multidimensional array value in PHP

You could use indices :

$cars[0][1] = 20;

Will update the second value ([1]) of the first array ([0]).

Full code :

$cars = array
(
 array("Volvo",10),
 array("BMW",10),
 array("Saab",10),
 array("Land Rover",10)
);
$cars[0][1] = 20;
print_r($cars);

outputs :

Array
(
    [0] => Array
        (
            [0] => Volvo
            [1] => 20
        )

    [1] => Array
        (
            [0] => BMW
            [1] => 10
        )

    [2] => Array
        (
            [0] => Saab
            [1] => 10
        )

    [3] => Array
        (
            [0] => Land Rover
            [1] => 10
        )

)

Updating multi-dimensional array with new key,value object if exists or create new

Use a variable to detect if you found an old item:

var found = false;
for(var x=0; x < mycart.length; x++){
    if(mycart[x].id == newid ){
        var tmpq = mycart[x].quantity;
        mycart[x].quantity = parseInt(tmpq) + parseInt(q);
        found = true;
        break;
    }
}
if (!found) {
    mycart.push ({ id: newid, quantity: newquantity });
}

It would be simpler if you made mycart an object whose keys are the IDs, so you wouldn't have to do a linear search. It would be like this:

var mycart = {
    "1": { quantity: 10 },
    "6": { quantity: 20 },
    ...
};

Then your code would be:

if (mycart.hasOwnProperty(newid)) {
    mycart[newid] += newquantity;
} else {
    mycart[newid] = { quantity: newquantity };
}

Update Value on Multi-dimensional Array?

With arrayFilters works fine, I tested with your object example.

db.getCollection('temp').update({}, {
    $set: {
      "destinos.$[d].origenes.$[o].base_price":450
    },
    }, { 
      arrayFilters: [
        {
           "d.ciudad_id": "1",
        },
        {
           "o.ciudad_id": "122"
        }
      ]
})

And check this: https://www.php.net/manual/es/mongodb-driver-bulkwrite.update.php because arrayFilter is an element in the options.

[
    "_id" => new \MongoDB\BSON\ObjectId($ruta_id)
],
[
    '$set' => [
        "destinos.$[d].origenes.$[o].base_price" => 450
    ]
],
[
    "arrayFilters" => 
    [
        ["d.ciudad_id" => "1"],["o.ciudad_id" => "122"]
    ]
]

Javascript multidimensional array updating specific element

PROBLEM:

I'm betting that you have a one-dimensional array with strings stored in each. So your array actually looks like:

array (
    [0] => '...',
    [1] => '.X.',
    [2] => '...'
)

When this is what you want:

array (
    [0] => array (
        [0] => '.',
        [1] => '.',
        [2] => '.'
    ),
    [1] => array (
        [0] => '.',
        [1] => 'X',
        [2] => '.'
    ),
    [2] => array (
        [0] => '.',
        [1] => '.',
        [2] => '.'
    )
)

SOLUTION:

When constructing your 2D array, make sure you explicitly declare each entry in board as an array. So to construct it, your code might look something like this:

board = new Array();
rows = 3;
for (var i = 0; i < rows; i++)
    board[i] = new Array('.', '.', '.');

Javascript changing value in multidimensional array

The problem reside here :

wocheArray[i] = {x, y, count, id};

If you check your code you would find that this part is overriding.

Consider your case: If a duplicate is found.

Then what your for loop will do:-

1.) Set var count = 0;

2.) [Skipping to If condition where is the procedure to check]

//IF match found (at j = 2 location, and i = 1)
//then what happen is : 

if(2>1 && hoursYy == hoursY && secondsX == secondsXx){
   wocheArray[1].count = wocheArray[1].count + 1;
// from here the count of wocheArray[1] would be increased by 1, Suppose 1.
}

3) In else block it will again set count = 0;

4) Again you are trying to set the values of wocheArray[1] = {x, y, count, id}; //now wocheArray[1] count is set to 0.

So from here, you can see you are updating the values or overriding them which creating the undesired result.

You should not call this outside wocheArray[i] = {x, y, count, id};

You must call it inside else block to make it work correctly.

else{
x = ....
....
....
count = 0;
wocheArray[i] = {x, y, count, id};
}

However, I am curious about the using of count = 0; inside else block as it does nothing here and var count =0; inside the for block which just re-initializes count variable which is wasting memory or not a good practice. According to shown code sample.

Change values of multidimensional array JavaScript

You could use recursion to get/change the values;

function inscribe(arr, path, value){
   if(path.length == 1){
      arr[path[0]] = value;
   }else{
      var next = path.shift();
      inscribe(arr[next], path, value);
   }
}

Updating an element in Javascript 2D array updates entire column

The docs of Array.fill are your friend here:

Note all elements in the array will be this exact value.

This is telling you that each one of the sub-arrays are actually the SAME array. Thus, if you change one, you change them all.

Looking at the code below, you'll see that the first comparison is false, whereas the second comparison is true

console.log([false,false,false,false] ===[false,false,false,false])

const arr = new Array(4).fill([false,false,false,false]);

console.log(arr[0] === arr[1]);