Typeerror: Console.Log(...) Is Not a Function

TypeError: console.log(...) is not a function

Solution

Simply put a semicolon (;) after console.log(…).

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Explanation

The error is easily reproducible like this:

console.log()
(function(){})

js-xlsx Uncaught TypeError: console.log is not a function

console.log is provided by the environment in which your code runs. Or not. It depends on the environment. Modern browsers provide it (at least if you have devtools open; some versions of IE don't provide it if you don't). NodeJS provides it.

Two possibilities:

1. Your environment doesn't provide it.

2. It does, but then you run this line of code:

   console.log="This will be description: " + descript+" - "+getValue(alphabet[j], i);
   

   which overwrites it with a string. Strings aren't functions, so the attempt to call it on any of your lines that use it correctly (like console.log(address_of_cell);) will now start failing.

   That line should be like the others, a function call:

   console.log("This will be description: " + descript+" - "+getValue(alphabet[j], i));
   

IIFE inside for loop error VM531:3 Uncaught TypeError: console.log(...)

You need to have a semicolon after the console.log - otherwise it's trying to call the returned result of console.log (undefined) which isn't a function, which is calling your error.

Automatic semicolon insertion doesn't take into account whitespace.

for (let i = 0; i < 10; i++) {  console.log("ddd");  (function x() {    console.log("eee")  })();}

Firefox/Firebug: Console.log(...); causes TypeError: Console.log is not a function

You're using C instead of c:

$(function(){
    console.log("Starting");
});

Javascript functions and vars are case sensitive.

How can solve this error Uncaught TypeError: inputArgs[0].match is not a function

1.npm -g firebase-tools and npm firebase-tools or yarn add firebase-tools
2.do not console.log() directly to authState(auth) or useAuthState (auth) user

3.try to put it on condition

  const [signInWithGoogle, googleuser, googleloading, googleerror] =
useSignInWithGoogle(auth) if (googleuser) {
console.log(googleuser)};

or console.dir() instead of console.log()

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