Sort by Two Values Prioritizing on One of Them

sort Javascript array by two numeric fields

grouperArray.sort(function (a, b) {
    var aSize = a.gsize;
    var bSize = b.gsize;
    var aLow = a.glow;
    var bLow = b.glow;
    console.log(aLow + " | " + bLow);

    if(aSize == bSize)
    {
        return (aLow < bLow) ? -1 : (aLow > bLow) ? 1 : 0;
    }
    else
    {
        return (aSize < bSize) ? -1 : 1;
    }
});

How to sort an array of objects by multiple fields?

You could use a chained sorting approach by taking the delta of values until it reaches a value not equal to zero.

var data = [{ h_id: "3", city: "Dallas", state: "TX", zip: "75201", price: "162500" }, { h_id: "4", city: "Bevery Hills", state: "CA", zip: "90210", price: "319250" }, { h_id: "6", city: "Dallas", state: "TX", zip: "75000", price: "556699" }, { h_id: "5", city: "New York", state: "NY", zip: "00010", price: "962500" }];
data.sort(function (a, b) {    return a.city.localeCompare(b.city) || b.price - a.price;});
console.log(data);

.as-console-wrapper { max-height: 100% !important; top: 0; }

How to sort different types of data according to their priority?

Arrange the comparison test to be lexicographical, first on the type (assigning priority indexes such as like number: 0, string: 1), then on the value in case of ties. This is clean and extensible.

To retain the order, you need to use a stable sorting algorithm such as MergeSort.

Alternatively, if you don't plan to add other types, proceed as follows:

scan the list and split (stably) in a sublist with the numbers and another sublist with the strings;
sort the sublists and concatenete them.

Sorting by two values in python. One ascending and one descending

Use:

data = {'david': ['APP', 2], 'ala': ['PROD', 2], 'steven': ['DEV', 4], 'katya': ['SYS', 2]}

res = sorted(data.items(), key=lambda x: (x[1][1] * -1, x[1][0]))
print(res)

Output

[('steven', ['DEV', 4]), ('david', ['APP', 2]), ('ala', ['PROD', 2]), ('katya', ['SYS', 2])]

Multiplying by -1 will make the sorting descending on the second element.

Javascript Sort array of objects by value returned by calling method

I think I figured it out:

function reorder(){
    var pinnedTasksPos = []
    var pinnedTasksNeg = []
    var regularTasksPos = []
    var regularTasksNeg = []
    var finishedTasksPos = []
    var finishedTasksNeg = []
    
    for (e=0; e<tasks.length; e++){
        let i = tasks[e]
        console.log(i)
        if(i.pinned){
            if(i.dueDaysDiff >= 0) {
                pinnedTasksPos.push(i)
            } else{
                pinnedTasksNeg.push(i)
            }
        } else if(i.done){
            if(i.dueDaysDiff >= 0) {
                finishedTasksPos.push(i)
            } else{
                finishedTasksNeg.push(i)
            }
        } else{
            if(i.dueDaysDiff >= 0) {
                regularTasksPos.push(i)
            } else{
                regularTasksNeg.push(i)
            }
        }
    }

    pinnedTasksPos.sort(compare)
    pinnedTasksNeg.sort(compare).reverse()
    regularTasksPos.sort(compare)
    regularTasksNeg.sort(compare).reverse()
    finishedTasksPos.sort(compare)
    finishedTasksNeg.sort(compare).reverse()

    var newarr = [...pinnedTasksPos, ...pinnedTasksNeg, ...regularTasksPos, ...regularTasksNeg, ...finishedTasksPos, ...finishedTasksNeg]
    return(newarr.reverse())
}

function compare(a, b){
    if(a.dueDaysDiff < b.dueDaysDiff){
        return -1
    }
    if(a.dueDaysDiff > b.dueDaysDiff){
        return 1
    }
    return 0
}