Sort Array of Objects by String Property Value

Sort array of objects by string property value

It's easy enough to write your own comparison function:

function compare( a, b ) {
if ( a.last_nom < b.last_nom ){
return -1;
}
if ( a.last_nom > b.last_nom ){
return 1;
}
return 0;
}

objs.sort( compare );

Or inline (c/o Marco Demaio):

objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 : ((b.last_nom > a.last_nom) ? -1 : 0))

Or simplified for numeric (c/o Andre Figueiredo):

objs.sort((a,b) => a.last_nom - b.last_nom); // b - a for reverse sort

Sorting an array of objects by property values

Sort homes by price in ascending order:

homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});

Or after ES6 version:

homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));

Some documentation can be found here.

For descending order, you may use

homes.sort((a, b) => parseFloat(b.price) - parseFloat(a.price));

Sort array of objects by string property value

It's easy enough to write your own comparison function:

function compare( a, b ) {
if ( a.last_nom < b.last_nom ){
return -1;
}
if ( a.last_nom > b.last_nom ){
return 1;
}
return 0;
}

objs.sort( compare );

Or inline (c/o Marco Demaio):

objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 : ((b.last_nom > a.last_nom) ? -1 : 0))

Or simplified for numeric (c/o Andre Figueiredo):

objs.sort((a,b) => a.last_nom - b.last_nom); // b - a for reverse sort

JS sort array of objets by specific string property (not ascending or descending)

You could take an object with the wanted order and take a large value as default for sorting.

const
data = [{ name: "strawberries", value: 12 }, { name: "bananas", value: 3 }, { name: "pears", value: 8 }, { name: "pears", value: 7 }, { name: "bananas", value: 10 }, { name: "apples", value: 6 }, { name: "bananas", value: 13 }, { name: "bananas", value: 5 }],
order = { bananas: 1, pears: 2 };

data.sort((a, b) => (order[a.name] || Number.MAX_VALUE) - (order[b.name] || Number.MAX_VALUE));

console.log(data);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Sorting object property by values

Move them to an array, sort that array, and then use that array for your purposes. Here's a solution:

let maxSpeed = {
car: 300,
bike: 60,
motorbike: 200,
airplane: 1000,
helicopter: 400,
rocket: 8 * 60 * 60
};
let sortable = [];
for (var vehicle in maxSpeed) {
sortable.push([vehicle, maxSpeed[vehicle]]);
}

sortable.sort(function(a, b) {
return a[1] - b[1];
});

// [["bike", 60], ["motorbike", 200], ["car", 300],
// ["helicopter", 400], ["airplane", 1000], ["rocket", 28800]]

Once you have the array, you could rebuild the object from the array in the order you like, thus achieving exactly what you set out to do. That would work in all the browsers I know of, but it would be dependent on an implementation quirk, and could break at any time. You should never make assumptions about the order of elements in a JavaScript object.

let objSorted = {}
sortable.forEach(function(item){
objSorted[item[0]]=item[1]
})

In ES8, you can use Object.entries() to convert the object into an array: