Simple function to sort an array of objects
How about this?
var people = [
{
name: 'a75',
item1: false,
item2: false
},
{
name: 'z32',
item1: true,
item2: false
},
{
name: 'e77',
item1: false,
item2: false
}];
function sort_by_key(array, key)
{
return array.sort(function(a, b)
{
var x = a[key]; var y = b[key];
return ((x < y) ? -1 : ((x > y) ? 1 : 0));
});
}
people = sort_by_key(people, 'name');
This allows you to specify the key by which you want to sort the array so that you are not limited to a hard-coded name sort. It will work to sort any array of objects that all share the property which is used as they key. I believe that is what you were looking for?
And here is a jsFiddle: http://jsfiddle.net/6Dgbu/
Sorting an array of objects by property values
Sort homes by price in ascending order:
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});
Or after ES6 version:
homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));
Some documentation can be found here.
For descending order, you may use
homes.sort((a, b) => parseFloat(b.price) - parseFloat(a.price));
Sort array of objects by string property value
It's easy enough to write your own comparison function:
function compare( a, b ) {
if ( a.last_nom < b.last_nom ){
return -1;
}
if ( a.last_nom > b.last_nom ){
return 1;
}
return 0;
}
objs.sort( compare );
Or inline (c/o Marco Demaio):
objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 : ((b.last_nom > a.last_nom) ? -1 : 0))
Or simplified for numeric (c/o Andre Figueiredo):
objs.sort((a,b) => a.last_nom - b.last_nom); // b - a for reverse sort
How to sort an object array by date property?
Simplest Answer
array.sort(function(a,b){
// Turn your strings into dates, and then subtract them
// to get a value that is either negative, positive, or zero.
return new Date(b.date) - new Date(a.date);
});
More Generic Answer
array.sort(function(o1,o2){
if (sort_o1_before_o2) return -1;
else if(sort_o1_after_o2) return 1;
else return 0;
});
Or more tersely:
array.sort(function(o1,o2){
return sort_o1_before_o2 ? -1 : sort_o1_after_o2 ? 1 : 0;
});
Generic, Powerful Answer
Define a custom non-enumerable sortBy
function using a Schwartzian transform on all arrays :
(function(){
if (typeof Object.defineProperty === 'function'){
try{Object.defineProperty(Array.prototype,'sortBy',{value:sb}); }catch(e){}
}
if (!Array.prototype.sortBy) Array.prototype.sortBy = sb;
function sb(f){
for (var i=this.length;i;){
var o = this[--i];
this[i] = [].concat(f.call(o,o,i),o);
}
this.sort(function(a,b){
for (var i=0,len=a.length;i<len;++i){
if (a[i]!=b[i]) return a[i]<b[i]?-1:1;
}
return 0;
});
for (var i=this.length;i;){
this[--i]=this[i][this[i].length-1];
}
return this;
}
})();
Use it like so:
array.sortBy(function(o){ return o.date });
If your date is not directly comparable, make a comparable date out of it, e.g.
array.sortBy(function(o){ return new Date( o.date ) });
You can also use this to sort by multiple criteria if you return an array of values:
// Sort by date, then score (reversed), then name
array.sortBy(function(o){ return [ o.date, -o.score, o.name ] };
See http://phrogz.net/JS/Array.prototype.sortBy.js for more details.
Sort array of objects by single key with date value
You can use Array.sort
.
Here's an example:
var arr = [{
"updated_at": "2012-01-01T06:25:24Z",
"foo": "bar"
},
{
"updated_at": "2012-01-09T11:25:13Z",
"foo": "bar"
},
{
"updated_at": "2012-01-05T04:13:24Z",
"foo": "bar"
}
]
arr.sort(function(a, b) {
var keyA = new Date(a.updated_at),
keyB = new Date(b.updated_at);
// Compare the 2 dates
if (keyA < keyB) return -1;
if (keyA > keyB) return 1;
return 0;
});
console.log(arr);
How to sort an array of objects by multiple fields?
You could use a chained sorting approach by taking the delta of values until it reaches a value not equal to zero.
var data = [{ h_id: "3", city: "Dallas", state: "TX", zip: "75201", price: "162500" }, { h_id: "4", city: "Bevery Hills", state: "CA", zip: "90210", price: "319250" }, { h_id: "6", city: "Dallas", state: "TX", zip: "75000", price: "556699" }, { h_id: "5", city: "New York", state: "NY", zip: "00010", price: "962500" }];
data.sort(function (a, b) { return a.city.localeCompare(b.city) || b.price - a.price;});
console.log(data);
.as-console-wrapper { max-height: 100% !important; top: 0; }
Sort JavaScript array of Objects based on one of the object's properties
There are 2 basic ways:
var arr = [{name:"ABC"},{name:"BAC"},{name:"abc"},{name:"bac"}];
arr.sort(function(a,b){
var alc = a.name.toLowerCase(), blc = b.name.toLowerCase();
return alc > blc ? 1 : alc < blc ? -1 : 0;
});
or
arr.sort(function(a,b){
return a.name.toLowerCase().localeCompare(b.name.toLowerCase());
});
Be aware that the 2nd version ignore diacritics, so a
and à
will be sorted as the same letter.
Now the problem with both these ways is that they will not sort uppercase ABC
before lowercase abc
, since it will treat them as the same.
To fix that, you will have to do it like this:
arr.sort(function(a,b){
var alc = a.name.toLowerCase(), blc = b.name.toLowerCase();
return alc > blc ? 1 : alc < blc ? -1 : a.name > b.name ? 1 : a.name < b.name ? -1 : 0;
});
Again here you could choose to use localeCompare
instead if you don't want diacritics to affect the sorting like this:
arr.sort(function(a,b){
var lccomp = a.name.toLowerCase().localeCompare(b.name.toLowerCase());
return lccomp ? lccomp : a.name > b.name ? 1 : a.name < b.name ? -1 : 0;
});
You can read more about sort here: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort
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