How to Perform Case-Insensitive Sorting Array of String in JavaScript

How to perform case-insensitive sorting array of string in JavaScript?

In (almost :) a one-liner

["Foo", "bar"].sort(function (a, b) {
    return a.toLowerCase().localeCompare(b.toLowerCase());
});

Which results in

[ 'bar', 'Foo' ]

While

["Foo", "bar"].sort();

results in

[ 'Foo', 'bar' ]

JavaScript case insensitive sorting for HTML table

This function works to sort strings alphabetically and places uppercase before lowercase.

function (a, b) {
   var x = String(a).toLowerCase(); 
   var y = String(b).toLowerCase(); 
     
   if (x > y) 
     return -1;
   if (x < y) 
     return 1; 
}

Performing a case sensitive string sorting in TypeScript

Try this:

var arr = [{'Id':'1','Value':'Desk'},{'Id':'2','Value':'skool'},{'Id':'3','Value':'OT'},{'Id':'4','Value':'sector'},{'Id':'5','Value':'Security'},{'Id':'6','Value':'Zebra'}];var sort = (a, b) => a > b ? 1 : (a < b ? -1 : 0);var sorted = arr.sort((a,b) =>   sort(a.Value[0].toLowerCase(), b.Value[0].toLowerCase()) ||   -sort(a.Value[0], b.Value[0]) ||  sort(a.Value, b.Value));console.log(sorted);

stop case sensitive sorting array

You can use the String.localeCompare with numeric: true and caseFirst: "upper" options for the alpha-numeric. For the symbols case you can match on a regular expression and use charCodeAt for the sorting:

let data = ['/', '2', '$', '3', 'B', 'a', 'A']let regEx = new RegExp(/[^a-zA-Z\d\s:]/)
let result = data.sort((a, b) => {  if (regEx.test(a) && regEx.test(b))    return a.charCodeAt(0) - b.charCodeAt(0)  else    return a.localeCompare(b, 'en', { numeric: true, caseFirst: 'upper'})})
console.log(result)

Javascript Array sort() does not sort array of strings correctly

It is because when there is no callback function supplied the elements are sorted after converted to UTF-16 code units. In your case it may be the reason that the utf converted string for Kelvin is before brandy so it is sorting in that order.

Use localeCompare

const ary = ["Kevin", "brandy", "Andrew"];const nary = ary.sort(function(a, b) {  return a.localeCompare(b)
});console.log(nary);

JavaScript's sort method handling of capital letters

That is correct. The strings are being sorted in a binary fashion, using the ordinal values of the characters themselves.

For a case-insensitive sort, try this:

arr.sort(function(a,b) {
    a = a.toLowerCase();
    b = b.toLowerCase();
    if( a == b) return 0;
    return a < b ? -1 : 1;
});

JavaScript case insensitive generic sorting for arrays

_.sortBy can sort dates - assuming all the values in the column are dates, you only need to test the type and return the date:

const sorted = _.orderBy(this, function(o) {
  if ($.isNumeric(o[column])) {
    return parseFloat(o[column]);
  }

  if (_.isDate(o[column])) {
    return o[column];
  }

  return (o[column]).toLowerCase();
}, direction);

javascript filter an array of strings, matching case insensitive substring

this.employeeDisplayList = this.employeeList.filter(e => {
    const emp = e.employeeName.toLowerCase();
    const str = this.searchStr.toLowerCase();
    return emp.includes(str);
});

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