Filter Array of Objects with Another Array of Objects

Filter array of objects with another array of objects

var filtered = [];

for(var arr in myArray){
   for(var filter in myFilter){
       if(myArray[arr].userid == myFilter[filter].userid && myArray[arr].projectid == myFilter[filter].projectid){
          filtered.push(myArray[arr].userid);
         }
   }
}
console.log(filtered);

Filter an array of objects by another object of filters

You can achieve this result using filter, Object.keys, and every.

You have to use filter and pass predicate that tell whether it is included in the final result.

In predicate, loop over all properties on the filters object and match if it is present in data or not. Simple

data.filter((o) =>Object.keys(filters).every((k) => filters[k] === o[k]));

const data = [{
    level: "1",
    objectId: "11",
    objectIdNo: "320",
    wpId: "123",
  },
  {
    level: "2",
    objectId: "12",
    objectIdNo: "321",
    wpId: "123",
  },
  {
    level: "2",
    objectId: "13",
    objectIdNo: "322",
    wpId: "120",
  },
];

const filters = {
  level: "2",
  wpId: "123",
};

const result = data.filter((o) =>
  Object.keys(filters).every((k) => filters[k] === o[k])
);
console.log(result);

Filter Array with objects based on another array dynamically

This should work

let codes = [{
    "title": "lore",
    "city": "New York",
    "desc": "lorem lorem",
    "age": "20"
  },
  {
    "title": "lore2 ",
    "city": "Santa Monica",
    "desc": "lorem2",
    "age": "20"
  }
];

let filter = [{
  "city": "New York"
}, {
  "age": "20"
}];

let res = codes.filter(code => {
  return filter.every(f => {
    const [key, value] = Object.entries(f)[0];
    return code[key] == value
  });
});

console.log(res)

How filter array of objects by another array of objects

You could get the entries of the condensed object and use Array#every and check the properties with the values.

var dataset = [{ id: "4", someval1: "10", someval2: "20", someval3: "30", someval4: "40" }, { id: "10", someval1: "10", someval2: "20", someval3: "30", someval4: "40" }, { id: "22", someval1: "102", someval2: "202", someval3: "302", someval4: "40" }],    criterias = [{ someval1: "10" }, { someval3: "30" }, { someval4: "40" }],    filters = Object.entries(Object.assign({}, ...criterias)),    result = dataset.filter(o => filters.every(([k, v]) => o[k] === v));
console.log(result);

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filter array of objects by another array of objects

Like Felix mentioned, Array#filter won't work faster than native for loop, however if you really want it as functional way, here's one possible solution:

const array = [    { id: 1, name: 'a1', sub: { id: 6, name: 'a1 sub' } },    { id: 2, name: 'a2', sub: null },    { id: 3, name: 'a3', sub: { id: 8, name: 'a3 sub' } },    { id: 4, name: 'a4', sub: null },    { id: 5, name: 'a5', sub: { id: 10, name: 'a5 sub' } },];
const anotherArray = [    { id: 1, name: 'a1', sub: { id: 6, name: 'a1 sub' } },    { id: 2, name: 'a2', sub: null },    { id: 5, name: 'a5', sub: { id: 10, name: 'a5 sub' } },];
const r = array.filter((elem) => !anotherArray.find(({ id }) => elem.id === id) && elem.sub);
console.log(r);

How to filter an array from all elements of another array

You can use the this parameter of the filter() function to avoid to store your filter array in a global variable.

var filtered = [1, 2, 3, 4].filter(    function(e) {      return this.indexOf(e) < 0;    },    [2, 4]);console.log(filtered);

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