Detect If an Element Is Visible with Jquery

How do I check if an element is hidden in jQuery?

Since the question refers to a single element, this code might be more suitable:

// Checks CSS content for display:[none|block], ignores visibility:[true|false]
$(element).is(":visible");

// The same works with hidden
$(element).is(":hidden");

It is the same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ.

We use jQuery's is() to check the selected element with another element, selector or any jQuery object. This method traverses along the DOM elements to find a match, which satisfies the passed parameter. It will return true if there is a match, otherwise return false.

JQuery: if div is visible

You can use .is(':visible')

Selects all elements that are visible.

For example:

if($('#selectDiv').is(':visible')){

Also, you can get the div which is visible by:

$('div:visible').callYourFunction();

Live example:

console.log($('#selectDiv').is(':visible'));console.log($('#visibleDiv').is(':visible'));

#selectDiv {  display: none;  }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script><div id="selectDiv"></div><div id="visibleDiv"></div>

Detect if an element is visible with jQuery

You're looking for:

.is(':visible')

Although you should probably change your selector to use jQuery considering you're using it in other places anyway:

if($('#testElement').is(':visible')) {
    // Code
}

It is important to note that if any one of a target element's parent elements are hidden, then .is(':visible') on the child will return false (which makes sense).

jQuery 3

:visible has had a reputation for being quite a slow selector as it has to traverse up the DOM tree inspecting a bunch of elements. There's good news for jQuery 3, however, as this post explains (Ctrl + F for :visible):

Thanks to some detective work by Paul Irish at Google, we identified some cases where we could skip a bunch of extra work when custom selectors like :visible are used many times in the same document. That particular case is up to 17 times faster now!

Keep in mind that even with this improvement, selectors like :visible and :hidden can be expensive because they depend on the browser to determine whether elements are actually displaying on the page. That may require, in the worst case, a complete recalculation of CSS styles and page layout! While we don’t discourage their use in most cases, we recommend testing your pages to determine if these selectors are causing performance issues.

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Expanding even further to your specific use case, there is a built in jQuery function called $.fadeToggle():

function toggleTestElement() {
    $('#testElement').fadeToggle('fast');
}

Check, using jQuery, if an element is 'display:none' or block on click

You can use :visible for visible elements and :hidden to find out hidden elements. This hidden elements have display attribute set to none.

hiddenElements = $(':hidden');
visibleElements = $(':visible');

To check particular element.

if($('#yourID:visible').length == 0)
{

}

Elements are considered visible if they consume space in the document.
Visible elements have a width or height that is greater than zero,
Reference

You can also use is() with :visible

if(!$('#yourID').is(':visible'))
{

}

If you want to check value of display then you can use css()

if($('#yourID').css('display') == 'none')
{

}

If you are using display the following values display can have.

display: none

display: inline

display: block

display: list-item

display: inline-block

Check complete list of possible display values here.

To check the display property with JavaScript

var isVisible = document.getElementById("yourID").style.display == "block";
var isHidden = document.getElementById("yourID").style.display == "none"; 

Jquery check if element is visible in viewport

According to the documentation for that plugin, .visible() returns a boolean indicating if the element is visible. So you'd use it like this:

if ($('#element').visible(true)) {
    // The element is visible, do something
} else {
    // The element is NOT visible, do something else
}

How do I check if an element is hidden in jQuery?

Since the question refers to a single element, this code might be more suitable:

// Checks CSS content for display:[none|block], ignores visibility:[true|false]
$(element).is(":visible");

// The same works with hidden
$(element).is(":hidden");

It is the same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ.

We use jQuery's is() to check the selected element with another element, selector or any jQuery object. This method traverses along the DOM elements to find a match, which satisfies the passed parameter. It will return true if there is a match, otherwise return false.

jQuery event to trigger action when a div is made visible

You could always add to the original .show() method so you don't have to trigger events every time you show something or if you need it to work with legacy code:

Jquery extension:

jQuery(function($) {

  var _oldShow = $.fn.show;

  $.fn.show = function(speed, oldCallback) {
    return $(this).each(function() {
      var obj         = $(this),
          newCallback = function() {
            if ($.isFunction(oldCallback)) {
              oldCallback.apply(obj);
            }
            obj.trigger('afterShow');
          };

      // you can trigger a before show if you want
      obj.trigger('beforeShow');

      // now use the old function to show the element passing the new callback
      _oldShow.apply(obj, [speed, newCallback]);
    });
  }
});

Usage example:

jQuery(function($) {
  $('#test')
    .bind('beforeShow', function() {
      alert('beforeShow');
    }) 
    .bind('afterShow', function() {
      alert('afterShow');
    })
    .show(1000, function() {
      alert('in show callback');
    })
    .show();
});

This effectively lets you do something beforeShow and afterShow while still executing the normal behavior of the original .show() method.

^{You could also create another method so you don't have to override the original .show() method.}

Finding if element is visible (JavaScript )

Display is not an attribute, it's a CSS property inside the style attribute.

You may be looking for

var myvar = document.getElementById("mydivID").style.display;

or

var myvar = $("#mydivID").css('display');

Check if element is visible in DOM

According to this MDN documentation, an element's offsetParent property will return null whenever it, or any of its parents, is hidden via the display style property. Just make sure that the element isn't fixed. A script to check this, if you have no position: fixed; elements on your page, might look like:

// Where el is the DOM element you'd like to test for visibility
function isHidden(el) {
    return (el.offsetParent === null)
}

On the other hand, if you do have position fixed elements that might get caught in this search, you will sadly (and slowly) have to use window.getComputedStyle(). The function in that case might be:

// Where el is the DOM element you'd like to test for visibility
function isHidden(el) {
    var style = window.getComputedStyle(el);
    return (style.display === 'none')
}

Option #2 is probably a little more straightforward since it accounts for more edge cases, but I bet its a good deal slower, too, so if you have to repeat this operation many times, best to probably avoid it.

How to check if a div is visible state or not?

is(':visible') checks the display property of an element, you can use css method.

if (!$("#singlechatpanel-1").css('visibility') === 'hidden') {
   // ...
}

If you set the display property of the element to none then your if statement returns true.

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