Round to 2 Decimal Places

How to round to 2 decimals with Python?

You can use the round function, which takes as its first argument the number and the second argument is the precision after the decimal point.

In your case, it would be:

answer = str(round(answer, 2))

How to round to at most 2 decimal places, if necessary

Use Math.round() :

Math.round(num * 100) / 100

Or to be more specific and to ensure things like 1.005 round correctly, use Number.EPSILON :

Math.round((num + Number.EPSILON) * 100) / 100

Round up double to 2 decimal places

Use a format string to round up to two decimal places and convert the double to a String:

let currentRatio = Double (rxCurrentTextField.text!)! / Double (txCurrentTextField.text!)!
railRatioLabelField.text! = String(format: "%.2f", currentRatio)

Example:

let myDouble = 3.141
let doubleStr = String(format: "%.2f", myDouble) // "3.14"

If you want to round up your last decimal place, you could do something like this (thanks Phoen1xUK):

let myDouble = 3.141
let doubleStr = String(format: "%.2f", ceil(myDouble*100)/100) // "3.15"

round up to 2 decimal places in java?

Well this one works...

double roundOff = Math.round(a * 100.0) / 100.0;

Output is

123.14

Or as @Rufein said

 double roundOff = (double) Math.round(a * 100) / 100;

this will do it for you as well.

Integer division round off to 2 decimal places in SQL Server

When we divide we can use an integer, which will produce an integer result, or a decimal by adding a decimal point (with or without a zero) which will give a decimal result with the number of decimal places determined by the format, or a floating point by adding an e, which will use the number of significant decimal places without trailing zeros. The following test schema demonstrates the difference between them.

I would seem that ROUND(2e/3,2) is the most concise way to arrive at 2 decimal places.

SELECT 
3e/5 FloatingPoint,
3./5 DecimalDivision,
CONVERT(DECIMAL(3,2), 3./5) DecimalDivision,
Round(3e/5,2) RoundedFloat

FloatingPoint | DecimalDivision | DecimalDivision | RoundedFloat
------------: | --------------: | --------------: | -----------:
0.6 | 0.600000 | 0.60 | 0.6
SELECT 
2e/3 FloatingPoint,
2./3 DecimalDivision,
CONVERT(DECIMAL(3,2), 2./3) DecimalDivision,
Round(2e/3,2) RoundedFloat

FloatingPoint | DecimalDivision | DecimalDivision | RoundedFloat
----------------: | --------------: | --------------: | -----------:
0.666666666666667 | 0.666666 | 0.67 | 0.67

db<>fiddle here

How to round down number 2 decimal places?

Use Math.floor to round the decimal places under the current value.

Reference

Example

Math.floor(1.0789 * 100) / 100

Working Fiddle

console.log(Math.floor(1.0789 * 100) / 100);
console.log(Math.floor(10.350 * 100) / 100);
console.log(Math.floor(1.7777 * 100) / 100);
console.log(Math.floor(12.34 * 100) / 100);

How to round to two decimal places in python?

You missplaced the %.2:

tax = (round(subtotal * 0.0475, 2))

And you don't need the %.

Rounding a variable to two decimal places C#

Use Math.Round and specify the number of decimal places.

Math.Round(pay,2);

Math.Round Method (Double, Int32)

Rounds a double-precision floating-point value to a specified number
of fractional digits.

Or Math.Round Method (Decimal, Int32)

Rounds a decimal value to a specified number of fractional digits.



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