Regular Expression to Match Urls in Java

Regular expression to match URLs in Java

Try the following regex string instead. Your test was probably done in a case-sensitive manner. I have added the lowercase alphas as well as a proper string beginning placeholder.

String regex = "^(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]";

This works too:

String regex = "\\b(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]";

Note:

String regex = "<\\b(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]>"; // matches <http://google.com>

String regex = "<^(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]>"; // does not match <http://google.com>

Perfect URL validation regex in Java

Use this version:

"(?i)^(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?$"

You did not have to double the slashes, add regex delimiters, modifiers at the end of the pattern, and turn \u to \x notation.

See IDEONE demo:

String[] URLs = new String[] { "http://foo.com/blah_blah", "http://foo.com/blah_blah/", "http://foo.com/blah_blah_(wikipedia)", "http://foo.bar?q=Spaces should be encoded" };
Pattern REGEX = Pattern.compile("(?i)^(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?$");
for (String url : URLs) {
    Matcher matcher = REGEX.matcher(url);
    if (matcher.find()) {
       System.out.println(matcher.group());
    }
}

Output:

http://foo.com/blah_blah
http://foo.com/blah_blah/
http://foo.com/blah_blah_(wikipedia)

UPDATE

To match URLs in larger texts, you need to replace ^ and $ with \\b:

Pattern REGEX = Pattern.compile("(?i)\\b(?:(?:https?|ftp)://)(?:\\S+(?::\\S*)?@)?(?:(?!(?:10|127)(?:\\.\\d{1,3}){3})(?!(?:169\\.254|192\\.168)(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]-*)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[a-z\\u00a1-\\uffff]{2,}))\\.?)(?::\\d{2,5})?(?:[/?#]\\S*)?\\b");

See another demo

Regular expression for finding URL in Java String

Given your list of websites, the following regex will do the trick:

(https?://)?(www\.)?\w+\.com

Demo

Java regex for URL

You can use the following:

^(http:\/\/|https:\/\/)?(www.)?([a-zA-Z0-9]+).[a-zA-Z0-9]*.[a-z]{3}.?([a-z]+)?(\/[a-z0-9])*(\/?|(\?[a-z0-9]=[a-z0-9](&[a-z0-9]=[a-z0-9]*)?))$

For a specific domain name:

^(http:\/\/|https:\/\/)?(www.)?example\.com(\/?|(\?[a-z0-9]=[a-z0-9](&[a-z0-9]=[a-z0-9]*)?))$

Edit: Validate domain and get Url:

(http:\/\/|https:\/\/)?(www.)?example\.com\S*

Regex to match url patterns

You can use this:

boolean matches = r.getRequestURI().matches(".*?/(javax\.faces\.resource|rfRes)/.*");

Regex Pattern matching for an URL

Try this code:

import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class HelloWorld{

     public static void main(String []args){
        String url = "http://domainName/contentid/controller_hscc.jsp?q=1" ;
        //String url = "baaaaab" ;
        String regex = "^.*?controller(\\w+)?\\.jsp.*?$" ;

        Pattern p = Pattern.compile(regex);
        Matcher m = p.matcher(url);
        boolean retVal = Pattern.matches(regex, url) ;
        System.out.println(m.matches() + "__" + retVal);
     }
}

---

Related Topics