Java 8: Mandatory Checked Exceptions Handling in Lambda Expressions. Why Mandatory, Not Optional

Java 8: Mandatory checked exceptions handling in lambda expressions. Why mandatory, not optional?

Not sure I really answer your question, but couldn't you simply use something like that?

public final class SupplierUtils {
private SupplierUtils() {
}

public static <T> Supplier<T> wrap(Callable<T> callable) {
return () -> {
try {
return callable.call();
}
catch (RuntimeException e) {
throw e;
}
catch (Exception e) {
throw new RuntimeException(e);
}
};
}
}

public class JdbcConnectionPool extends ObjectPool<Connection> {

public JdbcConnectionPool(int maxConnections, String url) {
super(SupplierUtils.wrap(() -> DriverManager.getConnection(url)), maxConnections);
}
}

Java why exception handling needed in lambda when use curly braces

List#forEach expects a Consumer.

Consumer is a (single-abstract-method) interface that looks like this (simplified):

@FunctionalInterface
public interface Consumer<T>{
void accept(T t);
}

As you see, accept does not throw any checked exceptions.

The lambda expression is an implementation of that interface so it cannot throw any exceptions, no matter what the other code does.

Why does a Java Lambda which throws a Runtime Exception require brackets?

The Java Language Specification describes the body of a lambda expression

A lambda body is either a single expression or a block (§14.2).

This, however,

throw new IllegalArgumentException("fail")

is the throw statement, not an expression. The compiler therefore rejects it as the lambda expression's body.

You can go down the rabbit hole and learn what all the types of expressions are, here (follow the grammar).

Java 8 Lambda function that throws exception?

You'll need to do one of the following.

  • If it's your code, then define your own functional interface that declares the checked exception:

    @FunctionalInterface
    public interface CheckedFunction<T, R> {
    R apply(T t) throws IOException;
    }

    and use it:

    void foo (CheckedFunction f) { ... }
  • Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception:

    public Integer myWrappedMethod(String s) {
    try {
    return myMethod(s);
    }
    catch(IOException e) {
    throw new UncheckedIOException(e);
    }
    }

    and then:

    Function<String, Integer> f = (String t) -> myWrappedMethod(t);

    or:

    Function<String, Integer> f =
    (String t) -> {
    try {
    return myMethod(t);
    }
    catch(IOException e) {
    throw new UncheckedIOException(e);
    }
    };

How can I throw CHECKED exceptions from inside Java 8 lambdas/streams?

This LambdaExceptionUtil helper class lets you use any checked exceptions in Java streams, like this:

Stream.of("java.lang.Object", "java.lang.Integer", "java.lang.String")
.map(rethrowFunction(Class::forName))
.collect(Collectors.toList());

Note Class::forName throws ClassNotFoundException, which is checked. The stream itself also throws ClassNotFoundException, and NOT some wrapping unchecked exception.

public final class LambdaExceptionUtil {

@FunctionalInterface
public interface Consumer_WithExceptions<T, E extends Exception> {
void accept(T t) throws E;
}

@FunctionalInterface
public interface BiConsumer_WithExceptions<T, U, E extends Exception> {
void accept(T t, U u) throws E;
}

@FunctionalInterface
public interface Function_WithExceptions<T, R, E extends Exception> {
R apply(T t) throws E;
}

@FunctionalInterface
public interface Supplier_WithExceptions<T, E extends Exception> {
T get() throws E;
}

@FunctionalInterface
public interface Runnable_WithExceptions<E extends Exception> {
void run() throws E;
}

/** .forEach(rethrowConsumer(name -> System.out.println(Class.forName(name)))); or .forEach(rethrowConsumer(ClassNameUtil::println)); */
public static <T, E extends Exception> Consumer<T> rethrowConsumer(Consumer_WithExceptions<T, E> consumer) throws E {
return t -> {
try { consumer.accept(t); }
catch (Exception exception) { throwAsUnchecked(exception); }
};
}

public static <T, U, E extends Exception> BiConsumer<T, U> rethrowBiConsumer(BiConsumer_WithExceptions<T, U, E> biConsumer) throws E {
return (t, u) -> {
try { biConsumer.accept(t, u); }
catch (Exception exception) { throwAsUnchecked(exception); }
};
}

/** .map(rethrowFunction(name -> Class.forName(name))) or .map(rethrowFunction(Class::forName)) */
public static <T, R, E extends Exception> Function<T, R> rethrowFunction(Function_WithExceptions<T, R, E> function) throws E {
return t -> {
try { return function.apply(t); }
catch (Exception exception) { throwAsUnchecked(exception); return null; }
};
}

/** rethrowSupplier(() -> new StringJoiner(new String(new byte[]{77, 97, 114, 107}, "UTF-8"))), */
public static <T, E extends Exception> Supplier<T> rethrowSupplier(Supplier_WithExceptions<T, E> function) throws E {
return () -> {
try { return function.get(); }
catch (Exception exception) { throwAsUnchecked(exception); return null; }
};
}

/** uncheck(() -> Class.forName("xxx")); */
public static void uncheck(Runnable_WithExceptions t)
{
try { t.run(); }
catch (Exception exception) { throwAsUnchecked(exception); }
}

/** uncheck(() -> Class.forName("xxx")); */
public static <R, E extends Exception> R uncheck(Supplier_WithExceptions<R, E> supplier)
{
try { return supplier.get(); }
catch (Exception exception) { throwAsUnchecked(exception); return null; }
}

/** uncheck(Class::forName, "xxx"); */
public static <T, R, E extends Exception> R uncheck(Function_WithExceptions<T, R, E> function, T t) {
try { return function.apply(t); }
catch (Exception exception) { throwAsUnchecked(exception); return null; }
}

@SuppressWarnings ("unchecked")
private static <E extends Throwable> void throwAsUnchecked(Exception exception) throws E { throw (E)exception; }

}

Many other examples on how to use it (after statically importing LambdaExceptionUtil):

@Test
public void test_Consumer_with_checked_exceptions() throws IllegalAccessException {
Stream.of("java.lang.Object", "java.lang.Integer", "java.lang.String")
.forEach(rethrowConsumer(className -> System.out.println(Class.forName(className))));

Stream.of("java.lang.Object", "java.lang.Integer", "java.lang.String")
.forEach(rethrowConsumer(System.out::println));
}

@Test
public void test_Function_with_checked_exceptions() throws ClassNotFoundException {
List<Class> classes1
= Stream.of("Object", "Integer", "String")
.map(rethrowFunction(className -> Class.forName("java.lang." + className)))
.collect(Collectors.toList());

List<Class> classes2
= Stream.of("java.lang.Object", "java.lang.Integer", "java.lang.String")
.map(rethrowFunction(Class::forName))
.collect(Collectors.toList());
}

@Test
public void test_Supplier_with_checked_exceptions() throws ClassNotFoundException {
Collector.of(
rethrowSupplier(() -> new StringJoiner(new String(new byte[]{77, 97, 114, 107}, "UTF-8"))),
StringJoiner::add, StringJoiner::merge, StringJoiner::toString);
}

@Test
public void test_uncheck_exception_thrown_by_method() {
Class clazz1 = uncheck(() -> Class.forName("java.lang.String"));

Class clazz2 = uncheck(Class::forName, "java.lang.String");
}

@Test (expected = ClassNotFoundException.class)
public void test_if_correct_exception_is_still_thrown_by_method() {
Class clazz3 = uncheck(Class::forName, "INVALID");
}

UPDATE as of Nov 2015 The code has been improved with the help of @PaoloC, please check his answer below and upvote it. He helped solve the last problem: Now the compiler will ask you to add throw clauses and everything's as if you could throw checked exceptions natively on Java 8 streams.


NOTE 1 The rethrow methods of the LambdaExceptionUtil class above may be used without fear, and are OK to use in any situation.


NOTE 2: The uncheck methods of the LambdaExceptionUtil class above are bonus methods, and may be safely removed them from the class if you don't want to use them. If you do used them, do it with care, and not before understanding the following use cases, advantages/disadvantages and limitations:

• You may use the uncheck methods if you are calling a method which literally can never throw the exception that it declares. For example: new String(byteArr, "UTF-8") throws UnsupportedEncodingException, but UTF-8 is guaranteed by the Java spec to always be present. Here, the throws declaration is a nuisance and any solution to silence it with minimal boilerplate is welcome: String text = uncheck(() -> new String(byteArr, "UTF-8"));

• You may use the uncheck methods if you are implementing a strict interface where you don't have the option for adding a throws declaration, and yet throwing an exception is entirely appropriate. Wrapping an exception just to gain the privilege of throwing it results in a stacktrace with spurious exceptions which contribute no information about what actually went wrong. A good example is Runnable.run(), which does not throw any checked exceptions.

• In any case, if you decide to use the uncheck methods,
be aware of these 2 consequences of throwing CHECKED exceptions without a throws clause: 1) The calling-code won't be able to catch it by name (if you try, the compiler will say: Exception is never thrown in body of corresponding try statement). It will bubble and probably be caught in the main program loop by some "catch Exception" or "catch Throwable", which may be what you want anyway. 2) It violates the principle of least surprise: it will no longer be enough to catch RuntimeException to be able to guarantee catching all possible exceptions. For this reason, I believe this should not be done in framework code, but only in business code that you completely control.

  • References:
  • http://www.philandstuff.com/2012/04/28/sneakily-throwing-checked-exceptions.html
  • http://www.mail-archive.com/javaposse@googlegroups.com/msg05984.html
  • Project Lombok annotation: @SneakyThrows
  • Brian Goetz opinion (against) here: How can I throw CHECKED exceptions from inside Java 8 streams?
  • https://softwareengineering.stackexchange.com/questions/225931/workaround-for-java-checked-exceptions?newreg=ddf0dd15e8174af8ba52e091cf85688e *

Checked exceptions thrown from within lambda expressions

The issue isn't the lambda expression, it's the interface it's implementing. Remember, a lambda expression is basically just shorthand for an anonymous class that implements a given interface.

In this case, forEach takes a java.util.function.Consumer<T>:

public interface Consumer<T> {
void accept(T t);
...
}

Note that accept is not declared to throw anything. This means that no implementation of it can throw anything; not a named class, not an anonymous class, and not a lambda.

Why Doesn't Java 8 Type Inference Consider Exceptions Thrown by Lambdas in Overload Selection?

If it makes you feel any better, this topic was indeed carefully considered during the JSR-335 design process.

The question is not "why isn't it able", but "why did we choose not to." When we find multiple potentially applicable overloads, we certainly could have chosen to speculatively attribute the lambda body under each set of signatures, and prune those candidates for which the lambda body failed to type-check.

However, we concluded that doing so would likely do more harm than good; it means, for example, that small changes to the method body, under this rule, could cause some method overload selection decisions to silently change without the user intending to do so. In the end, we concluded that using the presence of errors in the method body to discard a potentially applicable candidate would cause more confusion than benefit, especially given that there is a simple and safe workaround -- provide a target-type. We felt that reliability and predictability here outweighed optimal concision.

Java 8 - throw multiple generic checked exceptions in lambda

When you expand your interface to use two type variables, i.e.

private static interface ThrowingMethod<E1 extends Exception,E2 extends Exception> {
void run() throws E1, E2;
}

public <E1 extends Exception,E2 extends Exception>
void wrapMethod(ThrowingMethod<E1,E2> method) throws E1,E2 {
// same as before
}

the rules regarding the type inference do not change and they are the same for both type variables. E.g. you can still use

public void method1() throws ExceptionA {
wrapMethod(super::method1);
}

as before, as the compiler simply infers the same single exception type for both type variables.

For the method declaring two exceptions, it won’t pick up one for the first type variable and the other for the second; there is no rule which could tell the compiler which exception to use for which type variable.

But you can help the compiler out in this case, e.g.

public void method2() throws ExceptionB, ExceptionC {
wrapMethod((ThrowingMethod<ExceptionB, ExceptionC>)super::method2);
}

which is the best you can get with this approach.

When are braces optional in Java 8 lambda syntax?

You may omit the braces when the lambda body is a single expression or a void method invocation. Every expression evaluates to a value, and thus cannot be void.

If the body of the lambda is a block of statements (e.g. a series of calculations followed by a return statement), or the lambda has no value (i.e. has a void return type) and is not a single void method invocation, you must use the block form, which requires brackets.

In a block-style lambda, if a value is returned, then all possible code paths must either return a value or throw a Throwable.



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