Is there a difference between x++ and ++x in java?
++x is called preincrement while x++ is called postincrement.
int x = 5, y = 5;
System.out.println(++x); // outputs 6
System.out.println(x); // outputs 6
System.out.println(y++); // outputs 5
System.out.println(y); // outputs 6
Diffrence between x++ and ++x?
++x
: increment x
; the value of the overall expression is the value after the increment
x++
: increment x
; the value of the overall expression is the value before the increment
Consider these two sections:
int x = 0;
System.out.println(x++); // Prints 0
// x is now 1
int y = 0;
System.out.println(++y); // Prints 1
// y is now 1
I personally try to avoid using them as expressions within a larger statement - I prefer standalone code, like this:
int x = 0;
System.out.println(x); // Prints 0
x++;
// x is now 1
int y = 0;
y++;
System.out.println(y); // Prints 1
// y is now 1
Here I believe everyone would be able to work out what's printed and the final values of x
and y
without scratching their heads too much.
There are definitely times when it's useful to have pre/post-increment available within an expression, but think of readability first.
difference between X x = new X(); and x = new X();
Assuming that X
is a class with a no-arg constructor (for example a default constructor), the following works:
// Declare and initialize x
X x = new X();
// Assign new value to x
x = new X();
The first code line declares a variable x
and assigns a reference to the new instance of X
to it (a new X
object). The second line assigns a new X
instance to the already declared variable x
(thus discarding the reference to the first object). We declare a variable by putting the type name (or the word var
) before them. So since in the first line, we have X x
, this is a declaration.
In Java, variables need to be declared before they are first used. So the first code line would not work without the type name X
at the front. Java would complain that the variable x
had not been declared.
On the other hand, we are only allowed to declare each variable once. So putting type name X
before the second line would be an error too. My Eclipse says Duplicate local variable x because it “thinks” that I am trying to declare a second variable also named x
, which is not allowed (for good reasons).
Difference in implementation of x = x + 1 and x++
My professor recently said that although x = x + 1 and x++ will obviously give the same result
I guess your professor perhaps meant - the value of x
after x = x + 1
and x++
will be same. Just to re-phrase, as it seems to be creating confusion in interpreting the question.
Well, although the value of x
will be same, they are different operators, and use different JVM instructions in bytecode. x + 1
uses iadd
instruction, whereas x++
uses iinc
instruction. Although this is compiler dependent. A compiler is free to use a different set of instructions for a particular operation. I've checked this against javac
compiler.
For eclipse compiler, from one of the comment below from @Holger:
I just tested it with my eclipse and it produced
iinc
for both expressions. So I found one compiler producing the same instructions
You can check the byte code using javap
command. Let's consider the following class:
class Demo {
public static void main(String[] args) {
int x = 5;
x = x + 1;
System.out.println(x);
x++;
System.out.println(x);
}
}
Compile the above source file, and run the following command:
javap -c Demo
The code will be compiled to the following bytecode (just showing the main
method):
public static void main(java.lang.String[]);
Code:
0: iconst_5
1: istore_1
2: iload_1
3: iconst_1
4: iadd
5: istore_1
6: getstatic #2 // Field java/lang/System.out:Ljava/io/PrintStream;
9: iload_1
10: invokevirtual #3 // Method java/io/PrintStream.println:(I)V
13: iinc 1, 1
16: getstatic #2 // Field java/lang/System.out:Ljava/io/PrintStream;
19: iload_1
20: invokevirtual #3 // Method java/io/PrintStream.println:(I)V
23: return
Any difference between `var x` and `int x`?
There is no run-time difference. var
is compile-time syntactical sugar. If you replace var
with the inferred type (int
) you get identical results.
Is there any difference between (null != x) and (x != null)
You're going to want to use the second one.
Both do the same exact thing...compare A to B, or compare B to A - both mean the same thing.
It just makes more sense to use x != null
because that is more like how we would say this.
You could ask me "Is x not null?" That seems more natural than "Is null not x?" It makes more sense to us.
What is the difference between int[] x; and int x[];?
There is no difference in semantics. Both syntaxes mean the same. Some extract from the JLS §10.2:
The [] may appear as part of the type at the beginning of the
declaration, or as part of the declarator for a particular variable,
or both, as in this example:byte[] rowvector, colvector, matrix[];
This declaration is equivalent to:
byte rowvector[], colvector[], matrix[][];
However, as Voo states in the below comments, there can be some tricky confusion about these declarations when declaring several arrays in a single statement.
What is the difference between int x = (int) x and x = (int) x in java if I assign double x = 2.3?
You're re-declaring x
, so in the line
int x = (int)x
The x
on the right is not the same x
you previously declared. So its value defaults to 0 so (int)x
is 0. You normally wouldn't be able to have two x
variables. That's a thing jshell
lets you do, but in normal Java you couldn't do.
See this:
jshell> double x = 2.3
x ==> 2.3
jshell> int y = (int)x
y ==> 2
Is there any difference between Object[] x and Object x[]?
Both are legal and both work. But placing [] before the array's name is recommended.
From Javadocs:
You can also place the square brackets after the array's name:
float anArrayOfFloats[]; // this form is discouraged
However, convention discourages this form; the brackets identify the array type and should appear with the type designation.
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