Java - Unparseable Date

Java: unparseable date exception

What you're basically doing here is relying on Date#toString() which already has a fixed pattern. To convert a Java Date object into another human readable String pattern, you need SimpleDateFormat#format().

private String modifyDateLayout(String inputDate) throws ParseException{
    Date date = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z").parse(inputDate);
    return new SimpleDateFormat("dd.MM.yyyy HH:mm:ss").format(date);
}

By the way, the "unparseable date" exception can here only be thrown by SimpleDateFormat#parse(). This means that the inputDate isn't in the expected pattern "yyyy-MM-dd HH:mm:ss z". You'll probably need to modify the pattern to match the inputDate's actual pattern.

Update: Okay, I did a test:

public static void main(String[] args) throws Exception {
    String inputDate = "2010-01-04 01:32:27 UTC";
    String newDate = new Test().modifyDateLayout(inputDate);
    System.out.println(newDate);
}

This correctly prints:

03.01.2010 21:32:27

(I'm on GMT-4)

Update 2: as per your edit, you really got a ParseException on that. The most suspicious part would then be the timezone of UTC. Is this actually known at your Java environment? What Java version and what OS version are you using? Check TimeZone.getAvailableIDs(). There must be a UTC in between.

Simpledateformat unparseable date

Use this date formatter method I have created

    public static String dateFormater(String dateFromJSON, String expectedFormat, String oldFormat) {
    SimpleDateFormat dateFormat = new SimpleDateFormat(oldFormat);
    Date date = null;
    String convertedDate = null;
    try {
        date = dateFormat.parse(dateFromJSON);
        SimpleDateFormat simpleDateFormat = new SimpleDateFormat(expectedFormat);
        convertedDate = simpleDateFormat.format(date);
    } catch (Exception e) {
        e.printStackTrace();
    }

    return convertedDate;
}

and call this method like

dateFormater(" 01/04/2018" , "EE dd MMM yyyy" , "dd/MM/yyyy")

and you will get the desired output

Change date format Java getting Unparseable date Error

Change the format to

SimpleDateFormat dt = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
Date lastUpdatedDateFormatted = dt.parse(lastUpdatedDate);

System.out.println(lastUpdatedDateFormatted);

And it should be able to parse the date then.

java.text.ParseException: Unparseable date. dd MMM yyyy HH:mm:ss format

Try with:

String time = "24 Apr 2021 11:56:44";
Date timeOnLine = new SimpleDateFormat("dd MMM yyyy HH:mm:ss", Locale.US).parse(time);

Unparseable date - in java

Your formatter is set up to handle the format "EEE, d MMM yyyy HH:mm:ss Z". "1604328483716" isn't remotely in that format.

The value "1604328483716" looks like the string version of a milliseconds-since-The-Epoch value. If so, convert it to a long (Long.parseLong) and use new Date(theLongValue), which will give you a Date instance for Monday November 2nd 2020 14:48:03 GMT (or whatever that is in your local timezone).

You might also consider using the newer date/time API in the java.time package, rather than java.util.Date.

java.text.ParseException: Unparseable date: 2/9/2016 10:30:00 AM (GMT-05:00) Eastern Time (US & Canada)

You have used m for the month which is wrong. You have to use M for the month and m for the minute.

I also recommend you use DateTimeFormatter instead of using the outdated SimpleDateFormat. Check this to learn more about the modern date/time API.

import java.time.ZonedDateTime;
import java.time.format.DateTimeFormatter;
import java.time.format.DateTimeFormatterBuilder;
import java.util.Locale;

public class Main {
    public static void main(String[] args) {
        DateTimeFormatter formatter = new DateTimeFormatterBuilder()
                .parseCaseInsensitive()
                .appendPattern("d/M/yyyy hh:mm:ss a (zzz)")
                .toFormatter(Locale.ENGLISH);
        ZonedDateTime zdt = ZonedDateTime.parse("2/9/2016 10:30:00 AM (GMT-05:00)", formatter);
        System.out.println(zdt);
    }
}

Output:

2016-09-02T10:30-05:00[GMT-05:00]

Also,

import java.time.ZonedDateTime;
import java.time.format.DateTimeFormatter;
import java.time.format.DateTimeFormatterBuilder;
import java.util.Locale;

public class Main {
    public static void main(String[] args) {
        DateTimeFormatter formatter = new DateTimeFormatterBuilder()
                .parseCaseInsensitive()
                .appendPattern("d/M/yyyy hh:mm:ss a (zzz)")
                .appendLiteral(" Eastern Time (US & Canada)")
                .toFormatter(Locale.ENGLISH);
        ZonedDateTime zdt = ZonedDateTime.parse("2/9/2016 10:30:00 AM (GMT-05:00) Eastern Time (US & Canada)",
                formatter);
        System.out.println(zdt);
        System.out.println(formatter.format(zdt));
    }
}

Output:

2016-09-02T10:30-05:00[GMT-05:00]
2/9/2016 10:30:00 AM (GMT-05:00) Eastern Time (US & Canada)

Unparseable date Exception java date pattern

Use Locale.US so that it considers the month names in US format

SimpleDateFormat("dd-MMM-yyyy",Locale.US)

See this code run live at IdeOne.com.

How to resolve Unparseable date Exception in Java 8 with Date format yyyy-MM-dd hh:mm a

java.time

I recommend that you use java.time, the modern Java date and time API, for your date and time work.

    DateTimeFormatter dateFormatter = DateTimeFormatter.ofPattern("uuuu\u2013MM\u2013dd");
    DateTimeFormatter timeFormatter = DateTimeFormatter.ofPattern("hh:mm a", Locale.ENGLISH);
    
    String dateString = "2020–03–01";
    String timeString = "03:15 PM";
    
    LocalDate date = LocalDate.parse(dateString, dateFormatter);
    LocalTime time = LocalTime.parse(timeString, timeFormatter);
    LocalDateTime dateTime = date.atTime(time);
    
    System.out.println(dateTime);

Output:

2020-03-01T15:15

With java.time it is straightforward to combine date and time after parsing, so I prefer to parse them individually.

What went wrong in your code?

Credits go to Ajeetkumar for noticing and reporting in comments: The hyphen in your date string is not a usual minus sign or hyphen with character value 2D hexadecimal (45 decimal), but a en dash with character value 2013 hexadecimal (8211 decimal). So when you specify a usual hyphen in your format pattern string, they don’t match, and parsing fails. Instead I am using a Unicode escape for putting the en dash into the format pattern string. Simply pasting it in there would have worked too (provided that you save your .java file with a character encoding that supports it), but I wanted to make the reader aware that something special was going on here, so I preferred the Unicode escape with \u.

There is another problem with your code: You are not providing any locale for your formatter. So it uses the default locale of your JVM. As long as that locale expects PM, parsing will work. If one day you change your locale setting or run your code on a computer or JVM with a different default locale, parsing will suddenly fail, at you may have a hard time figuring out why. I have specified English locale for parsing the time. Some would prefer doing it for the date too even though technically it isn’t necessary.

Java - Unparseable Date