How to Parse Date String to Date

String string = "January 2, 2010";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMMM d, yyyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse(string, formatter);
System.out.println(date); // 2010-01-02

Symbol	Meaning	Presentation	Examples
G	era	text	AD; Anno Domini; A
u	year	year	2004; 04
y	year-of-era	year	2004; 04
D	day-of-year	number	189
M/L	month-of-year	number/text	7; 07; Jul; July; J
d	day-of-month	number	10
Q/q	quarter-of-year	number/text	3; 03; Q3; 3rd quarter
Y	week-based-year	year	1996; 96
w	week-of-week-based-year	number	27
W	week-of-month	number	4
E	day-of-week	text	Tue; Tuesday; T
e/c	localized day-of-week	number/text	2; 02; Tue; Tuesday; T
F	week-of-month	number	3
a	am-pm-of-day	text	PM
h	clock-hour-of-am-pm (1-12)	number	12
K	hour-of-am-pm (0-11)	number	0
k	clock-hour-of-am-pm (1-24)	number	0
H	hour-of-day (0-23)	number	0
m	minute-of-hour	number	30
s	second-of-minute	number	55
S	fraction-of-second	fraction	978
A	milli-of-day	number	1234
n	nano-of-second	number	987654321
N	nano-of-day	number	1234000000
V	time-zone ID	zone-id	America/Los_Angeles; Z; -08:30
z	time-zone name	zone-name	Pacific Standard Time; PST
O	localized zone-offset	offset-O	GMT+8; GMT+08:00; UTC-08:00;
X	zone-offset 'Z' for zero	offset-X	Z; -08; -0830; -08:30; -083015; -08:30:15;
x	zone-offset	offset-x	+0000; -08; -0830; -08:30; -083015; -08:30:15;
Z	zone-offset	offset-Z	+0000; -0800; -08:00;

Python date string to date object

You can use strptime in the datetime package of Python:

>>> import datetime
>>> datetime.datetime.strptime('24052010', "%d%m%Y").date()
datetime.date(2010, 5, 24)

How to parse a date?

You cannot expect to parse a date with a SimpleDateFormat that is set up with a different format.

To parse your "Thu Jun 18 20:56:02 EDT 2009" date string you need a SimpleDateFormat like this (roughly):

SimpleDateFormat parser=new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy");

Use this to parse the string into a Date, and then your other SimpleDateFormat to turn that Date into the format you want.

        String input = "Thu Jun 18 20:56:02 EDT 2009";
        SimpleDateFormat parser = new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy");
        Date date = parser.parse(input);
        SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
        String formattedDate = formatter.format(date);

        ...

JavaDoc: http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html

How to parse date string to Date?

The pattern is wrong. You have a 3-letter day abbreviation, so it must be EEE. You have a 3-letter month abbreviation, so it must be MMM. As those day and month abbreviations are locale sensitive, you'd like to explicitly specify the SimpleDateFormat locale to English as well, otherwise it will use the platform default locale which may not be English per se.

public static void main(String[] args) throws Exception {
    String target = "Thu Sep 28 20:29:30 JST 2000";
    DateFormat df = new SimpleDateFormat("EEE MMM dd kk:mm:ss z yyyy", Locale.ENGLISH);
    Date result =  df.parse(target);  
    System.out.println(result);
}

This prints here

Thu Sep 28 07:29:30 BOT 2000

which is correct as per my timezone.

I would also reconsider if you wouldn't rather like to use HH instead of kk. Read the javadoc for details about valid patterns.

Parse string to DateTime in C#

DateTime.Parse() will try figure out the format of the given date, and it usually does a good job. If you can guarantee dates will always be in a given format then you can use ParseExact():

string s = "2011-03-21 13:26";

DateTime dt = 
    DateTime.ParseExact(s, "yyyy-MM-dd HH:mm", CultureInfo.InvariantCulture);

(But note that it is usually safer to use one of the TryParse methods in case a date is not in the expected format)

Make sure to check Custom Date and Time Format Strings when constructing format string, especially pay attention to number of letters and case (i.e. "MM" and "mm" mean very different things).

Another useful resource for C# format strings is String Formatting in C#

Convert string to date then format the date

Use SimpleDateFormat#format(Date):

String start_dt = "2011-01-01";
DateFormat formatter = new SimpleDateFormat("yyyy-MM-DD"); 
Date date = (Date)formatter.parse(start_dt);
SimpleDateFormat newFormat = new SimpleDateFormat("MM-dd-yyyy");
String finalString = newFormat.format(date);

Convert datetime object to a String of date only in Python

You can use strftime to help you format your date.

E.g.,

import datetime
t = datetime.datetime(2012, 2, 23, 0, 0)
t.strftime('%m/%d/%Y')

will yield:

'02/23/2012'

More information about formatting see here

Convert String to Date with Milliseconds

The Date class stores the time as milliseconds, and if you look into your date object you will see that it actually has a time of 1598515567413 milliseconds.

You are fooled by the System.out.println() which uses Date's toString() method. This method is using the "EEE MMM dd HH:mm:ss zzz yyyy" format to display the date and simply omits all milliseconds.

If you use your formatter, which has milliseconds in its format string, you will see that the milliseconds are correct:

System.out.println(formatter.format(dateFormatter));

outputs 2020-08-27T10:06:07.413

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