Getting the Filenames of All Files in a Folder

Getting the filenames of all files in a folder

You could do it like that:

File folder = new File("your/path");
File[] listOfFiles = folder.listFiles();

for (int i = 0; i < listOfFiles.length; i++) {
  if (listOfFiles[i].isFile()) {
    System.out.println("File " + listOfFiles[i].getName());
  } else if (listOfFiles[i].isDirectory()) {
    System.out.println("Directory " + listOfFiles[i].getName());
  }
}

Do you want to only get JPEG files or all files?

Java - how to get all the file names in a folder

 File file = new File("C:\\");  
 File[] files = file.listFiles();  
 for (File f:files)  
 {  
     System.out.println(f.getAbsolutePath());  
 }  

listFiles() has more options. see the documentation here

How can I get the list of files in a directory using C or C++?

UPDATE 2017:

In C++17 there is now an official way to list files of your file system: std::filesystem. There is an excellent answer from Shreevardhan below with this source code:

#include <string>
#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;

int main()
{
    std::string path = "/path/to/directory";
    for (const auto & entry : fs::directory_iterator(path))
        std::cout << entry.path() << std::endl;
}

Old Answer:

In small and simple tasks I do not use boost, I use dirent.h. It is available as a standard header in UNIX, and also available for Windows via a compatibility layer created by Toni Ronkko.

DIR *dir;
struct dirent *ent;
if ((dir = opendir ("c:\\src\\")) != NULL) {
  /* print all the files and directories within directory */
  while ((ent = readdir (dir)) != NULL) {
    printf ("%s\n", ent->d_name);
  }
  closedir (dir);
} else {
  /* could not open directory */
  perror ("");
  return EXIT_FAILURE;
}

It is just a small header file and does most of the simple stuff you need without using a big template-based approach like boost (no offence, I like boost!).

Getting the names of all files in a directory with PHP

Don't bother with open/readdir and use glob instead:

foreach(glob($log_directory.'/*.*') as $file) {
    ...
}

Batch File; List files in directory, only filenames?

The full command is:

dir /b /a-d

Let me break it up;

Basically the /b is what you look for.

/a-d will exclude the directory names.

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For more information see dir /? for other arguments that you can use with the dir command.

Get all files within a folder containing string, push filenames to array and return array using Node FS

You should ditch callback syntax and use fs.promises Api. This looks much cleaner

const fs = require("fs").promises;
const path = require("path");
const dirname = path.resolve("./results/");

async function readDir(dirname) {
  const allResults = [];

  try {
    const files = await fs.readdir(dirname);

    for (const fileName of files) {
      try {
        const content = await fs.readFile(`${dirname}/${fileName}`, {
          encoding: "utf-8"
        });

        if (content.includes("content string")) {
          allResults.push(fileName);
        }
      } catch (error) {
        console.log(error.message);
      }
    }

    return allResults;
  } catch (error) {
    console.log(error);
  }
}

readDir(dirname).then(data => {
  console.log(data);
});

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