Does Java support default parameter values?
No, the structure you found is how Java handles it (that is, with overloading instead of default parameters).
For constructors, See Effective Java: Programming Language Guide's Item 1 tip (Consider static factory methods instead of constructors) if the overloading is getting complicated. For other methods, renaming some cases or using a parameter object can help. This is when you have enough complexity that differentiating is difficult. A definite case is where you have to differentiate using the order of parameters, not just number and type.
Are default parameter values supported by Java?
It is not possible in Java
,but we can use the Builder Pattern, which is said this Stack Overflow answer.
As described in the answer reference, the Builder Pattern lets you write code like
Student s1 = new StudentBuilder().name("Eli").buildStudent();
Student s2 = new StudentBuilder()
.name("Spicoli")
.age(16)
.motto("Aloha, Mr Hand")
.buildStudent();
in which some fields can have default values or otherwise be optional.
Constructors with default values of parameters
No, Java doesn't support default values for parameters. You can overload constructors instead:
public Shape(int v,int e) {vertices =v; edges = e; }
public Shape() { this(1, 2); }
Is it possible to declare default argument in Java in String?
No, the way you would normally do this is overload the method like so:
public void test()
{
test("exampleText");
}
public void test(String name)
{
}
Is it possible to define method argument with default values in Java?
Java != PHP.
But you can write:
public void delete(String name){
delete(name, 0);
}
public void delete(String name, int user_id){/* ...*/}
Is there a way to set default parameters in Java?
You would have to overload that function with no arguments, and call it internally with 'defaults'
public void sayHello(){
sayHello("Stranger");
}
public void sayHello(String name){
System.out.println("Hello "+name);
}
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