How to check if a number is between two values?
Tests whether windowsize
is greater than 500
and lesser than 600
meaning that neither values 500
or 600
itself will result in the condition becoming true.
if (windowsize > 500 && windowsize < 600) {
// ...
}
Check if a variable is between two numbers with Java
I see some errors in your code.
Your probably meant the mathematical term
90 <= angle <= 180, meaning angle in range 90-180.
if (angle >= 90 && angle <= 180) {
// do action
}
Determine whether integer is between two other integers
if 10000 <= number <= 30000:
pass
For details, see the docs.
Check if int is between two numbers
One problem is that a ternary relational construct would introduce serious parser problems:
<expr> ::= <expr> <rel-op> <expr> |
... |
<expr> <rel-op> <expr> <rel-op> <expr>
When you try to express a grammar with those productions using a typical PGS, you'll find that there is a shift-reduce conflict at the point of the first <rel-op>
. The parse needs to lookahead an arbitrary number of symbols to see if there is a second <rel-op>
before it can decide whether the binary or ternary form has been used. In this case, you could not simply ignore the conflict because that would result in incorrect parses.
I'm not saying that this grammar is fatally ambiguous. But I think you'd need a backtracking parser to deal with it correctly. And that is a serious problem for a programming language where fast compilation is a major selling point.
How to elegantly check if a number is within a range?
There are a lot of options:
int x = 30;
if (Enumerable.Range(1,100).Contains(x)) //true
And indeed basic if
more elegantly can be written with reversing order in the first check:
if (1 <= x && x <= 100) //true
Also, check out this SO post for regex options.
Notes:
LINQ solution is strictly for style points - since Contains iterates over all items its complexity is O(range_size) and not O(1) normally expected from a range check.
More generic version for other ranges (notice that second argument is count, not end):if (Enumerable.Range(start, end - start + 1).Contains(x)
There is temptation to write
if
solution without&&
like1 <= x <= 100
- that look really elegant, but in C# leads to a syntax error "Operator '<=' cannot be applied to operands of type 'bool' and 'int'"
How to check if an integer is within a range of numbers in PHP?
The expression:
($min <= $value) && ($value <= $max)
will be true if $value
is between $min
and $max
, inclusively
See the PHP docs for more on comparison operators
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