Pass a Nsdictionary as Parameter to UItapgesturerecognizer

Pass a NSDictionary as parameter to UITapGestureRecognizer

Is there a reason you can't store the information in the owning view controller? Is it for abstraction?

You can always extend UITapGestureRecognizer to carry more data:

@interface UserDataTapGestureRecognizer : UITapGestureRecognizer
@property (nonatomic, strong) id userData;
@end

@implementation UserDataTapGestureRecognizer
@end

...

UserDataTapGestureRecognizer *downloadOptionPressed =
    [[UserDataTapGestureRecognizer alloc] initWithTarget:self
    action:@selector(timeFrameLabelTapped:)];
downloadOptionPressed.userData = parameters;

...

- (void)downloadOptionPressed:(UserDataTapGestureRecognizer *)recognizer {
    NSArray *parameters = recognizer.userData;
}

pass parameter to UITapGestureRecognizer

You can extend a UITapGestureRecognizer for holding more data:

// MYTapGestureRecognizer.h

@interface MYTapGestureRecognizer : UITapGestureRecognizer

@property (nonatomic, strong) NSString *data;

@end

// MYTapGestureRecognizer.m

@implementation MYTapGestureRecognizer

@end

// =====================

....

MYTapGestureRecognizer *singleTap = [[MYTapGestureRecognizer alloc] initWithTarget:self action:@selector(tapDetected:)];

singleTap.data = @"Hello";

.....

// ====================

-(void)tapDetected:(UITapGestureRecognizer *)tapRecognizer {

MYTapGestureRecognizer *tap = (MYTapGestureRecognizer *)tapRecognizer;

NSLog(@"data : %@", tap.data);

}

How to add a parameter to UITapGestureRecognizer so that the action function can access that parameter

Make your custom View and store the parameter that you want to pass through the Gesture Recognizer inside the view.

class GestureView: UIView{

var myViewValue: String? // Or whichever type of value you want to store and send via the gesture
}

When you initiate your view, add the value as per your requirement:

    let panReceptor = GestureView()
    panReceptor.myViewValue = "Hello World"

Add a simple TapGesture on this custom view and you may pass the value as below:

let tapGesture = UITapGestureRecognizer.init(target: self, action: #selector(viewTapped(sender:)))
    panReceptor.addGestureRecognizer(tapGesture)

@objc func viewTapped(sender: UITapGestureRecognizer){

    guard let unwrappedView = sender.view as? GestureView else { return }
    print("Gesture View value : \(unwrappedView.myViewValue)")
}

In the above example I have in effect passed a String parameter through the sender.view.

You may pass any type in this manner and use the value as per your requirement in the selector method.

Write a method with argument in ios

- (void)setPhoneNumber:(NSString *)phoneNumber; // set a phoneNumber property

- (void)prepareToBeTapped 
{
    UITapGestureRecognizer *tapFirstGuy = [[UITapGestureRecognizer alloc]
        initWithTarget:self action:@selector(makeCallToThisPerson:)];
    [self addGestureRecognizer:tapFirstGuy];
}

- (void)makeCallToThisPerson:(id)sender
{
    NSString *phoneURL = [NSString stringWithFormat:@"tel:%@", phoneNumber];
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneURL]];
}

Pass dictionary of variable bindings to selector

You don't need a dictionary as an array will do:

NSArray *textFields = @[
    self.verificationCodeField,
    self.verificationCodeField1,
    self.verificationCodeField2,
    self.verificationCodeField3,
    self.verificationCodeField4
];

and then your code will work:

for (UITextField *textField in textFields) {
    [textField addTarget:self
                  action:@selector(textFieldDidChange:)
        forControlEvents:UIControlEventEditingChanged];
}

How do I get the values as an NSDictionary in Swift 3?

You need to convert your string to JSON and then get value out. Here is an example to get user level information. Don't forget to handle unwrapping :)

let str = "{\"error\":false,\"user\":{\"id\":3,\"username\":\"anto\",\"email\":\"a@a\",\"nome\":\"Anto\",\"cognome\":\"xxx\",\"telefono\":\"1234567892\"},\"prodotti\":[{\"username\":\"anto\",\"id_prodotto\":57,\"nome_prodotto\":\"milk\",\"categoria\":\"milk\",\"quantita\":\"2\"},{\"username\":\"anto\",\"id_prodotto\":58,\"nome_prodotto\":\"farina\",\"categoria\":\"alimento\",\"quantita\":\"2\"}]}"

let data = str.data(using: .utf8)

do{
    let json = try JSONSerialization.jsonObject(with: data!, options: []) as? [String: Any]

    let userDic = json?["user"] as? [String: Any]
    dump(userDic?["id"])
    dump(userDic?["username"])
}catch let error{

}

Passing data from one view controller to another

Make string variable in your AppDelegate Like

var Model_id = String()

and where you are getting value of username and userid sends its value to AppDelegate. make AppDelgate object like below and same in destinationViewController

let appDelegate = UIApplication.shared.delegate as! AppDelegate

to pass value to app delegate variable

self.appDelegate. Model_id = "your Value"

and get your values wherever you want to fetch like below

let appDelegate = UIApplication.shared.delegate as! AppDelegate
let  string = appDelegate. Model_id as! String

Cannot initialize a parameter of type 'id _NonNull' with an lvalue of type double

The contents of NSArray (and NSDictionary) in Objective-C must be objects. All scalar types int double etc. are not objects.

There is an easy solution:

Wrap all scalar types in the shortcut NSNumber initializer @()

 double var1 = 12.0;
 NSString *var2 = @"Foo";
 NSArray *valArray = [NSArray arrayWithObjects: @(var1), var2, nil];

or still shorter

 NSArray *valArray = @[@(var1), var2];

To get the double type back from the array you have to write

 double var3 = valArray[0].doubleValue;

Side note: Variable names are supposed to start with a lowercase letter.

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