Detect if the device is iPhone X
Based on your question, the answer is no. There are no direct methods. For more information you can get the information here:
- How to get device make and model on iOS?
and
- how to check screen size of iphone 4 and iphone 5 programmatically in swift
The iPhone X height is 2436 px
From Device Screen Sizes and resolutions:
From Device Screen Sizes and Orientations:
Swift 3 and later:
if UIDevice().userInterfaceIdiom == .phone {
switch UIScreen.main.nativeBounds.height {
case 1136:
print("iPhone 5 or 5S or 5C")
case 1334:
print("iPhone 6/6S/7/8")
case 1920, 2208:
print("iPhone 6+/6S+/7+/8+")
case 2436:
print("iPhone X/XS/11 Pro")
case 2688:
print("iPhone XS Max/11 Pro Max")
case 1792:
print("iPhone XR/ 11 ")
default:
print("Unknown")
}
}
Objective-C:
if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
switch ((int)[[UIScreen mainScreen] nativeBounds].size.height) {
case 1136:
printf("iPhone 5 or 5S or 5C");
break;
case 1334:
printf("iPhone 6/6S/7/8");
break;
case 1920:
case 2208:
printf("iPhone 6+/6S+/7+/8+");
break;
case 2436:
printf("iPhone X/XS/11 Pro");
break;
case 2688:
printf("iPhone XS Max/11 Pro Max");
break;
case 1792:
printf("iPhone XR/ 11 ");
break;
default:
printf("Unknown");
break;
}
}
Xamarin.iOS:
if (UIDevice.CurrentDevice.UserInterfaceIdiom == UIUserInterfaceIdiom.Phone) {
if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1136) {
Console.WriteLine("iPhone 5 or 5S or 5C");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1334) {
Console.WriteLine("iPhone 6/6S/7/8");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1920 || (UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2208) {
Console.WriteLine("iPhone 6+/6S+/7+/8+");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2436) {
Console.WriteLine("iPhone X, XS, 11 Pro");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2688) {
Console.WriteLine("iPhone XS Max, 11 Pro Max");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1792) {
Console.WriteLine("iPhone XR, 11");
} else {
Console.WriteLine("Unknown");
}
}
Based on your question as follow:
Or use screenSize.height as float 812.0f not int 812.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
// 812.0 on iPhone X, XS
// 896.0 on iPhone XS Max, XR.
if (screenSize.height >= 812.0f)
NSLog(@"iPhone X");
}
For more information you can refer the following page in iOS Human Interface Guidelines:
- Adaptivity and Layout - Visual Design - iOS - Human Interface Guidelines
Swift:
Detect with topNotch:
If anyone considering using notch to detect iPhoneX, mind that on "landscape" its same for all iPhones.
var hasTopNotch: Bool {
if #available(iOS 13.0, *) {
return UIApplication.shared.windows.filter {$0.isKeyWindow}.first?.safeAreaInsets.top ?? 0 > 20
}else{
return UIApplication.shared.delegate?.window??.safeAreaInsets.top ?? 0 > 20
}
return false
}
Objective-C:
- (BOOL)hasTopNotch {
if (@available(iOS 13.0, *)) {
return [self keyWindow].safeAreaInsets.top > 20.0;
}else{
return [[[UIApplication sharedApplication] delegate] window].safeAreaInsets.top > 20.0;
}
return NO;
}
- (UIWindow*)keyWindow {
UIWindow *foundWindow = nil;
NSArray *windows = [[UIApplication sharedApplication]windows];
for (UIWindow *window in windows) {
if (window.isKeyWindow) {
foundWindow = window;
break;
}
}
return foundWindow;
}
UPDATE:
Do not use the userInterfaceIdiom property to identify the device type, as the documentation for userInterfaceIdiom explains:
For universal applications, you can use this property to tailor the behavior of your application for a specific type of device. For example, iPhone and iPad devices have different screen sizes, so you might want to create different views and controls based on the type of the current device.
That is, this property is just used to identify the running app's view style. However, the iPhone app (not the universal) could be installed in iPad device via App store, in that case, the userInterfaceIdiom will return the UIUserInterfaceIdiomPhone, too.
The right way is to get the machine name via uname. Check the following for details:
- How to get device make and model on iOS?
iOS: Detect if the device is iPhone X family (frameless)
You could "fitler" for the top notch, something like:
var hasTopNotch: Bool {
if #available(iOS 11.0, tvOS 11.0, *) {
return UIApplication.shared.delegate?.window??.safeAreaInsets.top ?? 0 > 20
}
return false
}
How to programmatically detect iPhone XS or iPhone X?
I use DeviceUtil to determine an iOS device's model.
According to this DeviceUtil GitHub post, the returned UIDevice hardwareString values are:
iPhone11,2 = iPhone XS
iPhone11,4 = iPhone XS Max
iPhone11,8 = iPhone XR
Curiously, the Xcode 10 GM Simulator's [UIScreen mainScreen].bounds.size returns 375 x 812 for iPhone X, XS, XS Max, and R devices. I had expected 414 x 896 for the XS Max and XR.
How to determine the current iPhone/device model?
I made this "pure Swift" extension on UIDevice.
If you are looking for a more elegant solution you can use my µ-framework DeviceKit published on GitHub (also available via CocoaPods, Carthage and Swift Package Manager).
Here's the code:
import UIKit
public extension UIDevice {
static let modelName: String = {
var systemInfo = utsname()
uname(&systemInfo)
let machineMirror = Mirror(reflecting: systemInfo.machine)
let identifier = machineMirror.children.reduce("") { identifier, element in
guard let value = element.value as? Int8, value != 0 else { return identifier }
return identifier + String(UnicodeScalar(UInt8(value)))
}
func mapToDevice(identifier: String) -> String { // swiftlint:disable:this cyclomatic_complexity
#if os(iOS)
switch identifier {
case "iPod5,1": return "iPod touch (5th generation)"
case "iPod7,1": return "iPod touch (6th generation)"
case "iPod9,1": return "iPod touch (7th generation)"
case "iPhone3,1", "iPhone3,2", "iPhone3,3": return "iPhone 4"
case "iPhone4,1": return "iPhone 4s"
case "iPhone5,1", "iPhone5,2": return "iPhone 5"
case "iPhone5,3", "iPhone5,4": return "iPhone 5c"
case "iPhone6,1", "iPhone6,2": return "iPhone 5s"
case "iPhone7,2": return "iPhone 6"
case "iPhone7,1": return "iPhone 6 Plus"
case "iPhone8,1": return "iPhone 6s"
case "iPhone8,2": return "iPhone 6s Plus"
case "iPhone9,1", "iPhone9,3": return "iPhone 7"
case "iPhone9,2", "iPhone9,4": return "iPhone 7 Plus"
case "iPhone10,1", "iPhone10,4": return "iPhone 8"
case "iPhone10,2", "iPhone10,5": return "iPhone 8 Plus"
case "iPhone10,3", "iPhone10,6": return "iPhone X"
case "iPhone11,2": return "iPhone XS"
case "iPhone11,4", "iPhone11,6": return "iPhone XS Max"
case "iPhone11,8": return "iPhone XR"
case "iPhone12,1": return "iPhone 11"
case "iPhone12,3": return "iPhone 11 Pro"
case "iPhone12,5": return "iPhone 11 Pro Max"
case "iPhone13,1": return "iPhone 12 mini"
case "iPhone13,2": return "iPhone 12"
case "iPhone13,3": return "iPhone 12 Pro"
case "iPhone13,4": return "iPhone 12 Pro Max"
case "iPhone14,4": return "iPhone 13 mini"
case "iPhone14,5": return "iPhone 13"
case "iPhone14,2": return "iPhone 13 Pro"
case "iPhone14,3": return "iPhone 13 Pro Max"
case "iPhone14,7": return "iPhone 14"
case "iPhone14,8": return "iPhone 14 Plus"
case "iPhone15,2": return "iPhone 14 Pro"
case "iPhone15,3": return "iPhone 14 Pro Max"
case "iPhone8,4": return "iPhone SE"
case "iPhone12,8": return "iPhone SE (2nd generation)"
case "iPhone14,6": return "iPhone SE (3rd generation)"
case "iPad2,1", "iPad2,2", "iPad2,3", "iPad2,4": return "iPad 2"
case "iPad3,1", "iPad3,2", "iPad3,3": return "iPad (3rd generation)"
case "iPad3,4", "iPad3,5", "iPad3,6": return "iPad (4th generation)"
case "iPad6,11", "iPad6,12": return "iPad (5th generation)"
case "iPad7,5", "iPad7,6": return "iPad (6th generation)"
case "iPad7,11", "iPad7,12": return "iPad (7th generation)"
case "iPad11,6", "iPad11,7": return "iPad (8th generation)"
case "iPad12,1", "iPad12,2": return "iPad (9th generation)"
case "iPad13,18", "iPad13,19": return "iPad (10th generation)"
case "iPad4,1", "iPad4,2", "iPad4,3": return "iPad Air"
case "iPad5,3", "iPad5,4": return "iPad Air 2"
case "iPad11,3", "iPad11,4": return "iPad Air (3rd generation)"
case "iPad13,1", "iPad13,2": return "iPad Air (4th generation)"
case "iPad13,16", "iPad13,17": return "iPad Air (5th generation)"
case "iPad2,5", "iPad2,6", "iPad2,7": return "iPad mini"
case "iPad4,4", "iPad4,5", "iPad4,6": return "iPad mini 2"
case "iPad4,7", "iPad4,8", "iPad4,9": return "iPad mini 3"
case "iPad5,1", "iPad5,2": return "iPad mini 4"
case "iPad11,1", "iPad11,2": return "iPad mini (5th generation)"
case "iPad14,1", "iPad14,2": return "iPad mini (6th generation)"
case "iPad6,3", "iPad6,4": return "iPad Pro (9.7-inch)"
case "iPad7,3", "iPad7,4": return "iPad Pro (10.5-inch)"
case "iPad8,1", "iPad8,2", "iPad8,3", "iPad8,4": return "iPad Pro (11-inch) (1st generation)"
case "iPad8,9", "iPad8,10": return "iPad Pro (11-inch) (2nd generation)"
case "iPad13,4", "iPad13,5", "iPad13,6", "iPad13,7": return "iPad Pro (11-inch) (3rd generation)"
case "iPad14,3", "iPad14,4": return "iPad Pro (11-inch) (4th generation)"
case "iPad6,7", "iPad6,8": return "iPad Pro (12.9-inch) (1st generation)"
case "iPad7,1", "iPad7,2": return "iPad Pro (12.9-inch) (2nd generation)"
case "iPad8,5", "iPad8,6", "iPad8,7", "iPad8,8": return "iPad Pro (12.9-inch) (3rd generation)"
case "iPad8,11", "iPad8,12": return "iPad Pro (12.9-inch) (4th generation)"
case "iPad13,8", "iPad13,9", "iPad13,10", "iPad13,11":return "iPad Pro (12.9-inch) (5th generation)"
case "iPad14,5", "iPad14,6": return "iPad Pro (12.9-inch) (6th generation)"
case "AppleTV5,3": return "Apple TV"
case "AppleTV6,2": return "Apple TV 4K"
case "AudioAccessory1,1": return "HomePod"
case "AudioAccessory5,1": return "HomePod mini"
case "i386", "x86_64", "arm64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "iOS"))"
default: return identifier
}
#elseif os(tvOS)
switch identifier {
case "AppleTV5,3": return "Apple TV 4"
case "AppleTV6,2": return "Apple TV 4K"
case "i386", "x86_64": return "Simulator \(mapToDevice(identifier: ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] ?? "tvOS"))"
default: return identifier
}
#endif
}
return mapToDevice(identifier: identifier)
}()
}
You call it like this:
let modelName = UIDevice.modelName
For real devices it returns e.g. "iPad Pro (12.9-inch) (5th generation)", for simulators it returns e.g. "Simulator iPad Pro (12.9-inch) (5th generation)"
Here's the model references:
- https://theiphonewiki.com/wiki/Models
- https://theiphonewiki.com/wiki/BORD
How can I detect if my device is an iPhoneX in Swift 4?
If you need to detect if a device is iPhoneX don't use bounds, it depends on the orientation of the device. So if the user opens your app in portrait mode it will fail. You can use Device property nativeBounds which doesn't change on rotation.
In iOS 8 and later, a screen’s bounds property takes the interface
orientation of the screen into account. This behavior means that the
bounds for a device in a portrait orientation may not be the same as
the bounds for the device in a landscape orientation. Apps that rely
on the screen dimensions can use the object in the
fixedCoordinateSpace property as a fixed point of reference for any
calculations they must make. (Prior to iOS 8, a screen’s bounds
rectangle always reflected the screen dimensions relative to a
portrait-up orientation. Rotating the device to a landscape or
upside-down orientation did not change the bounds.)
extension UIDevice {
var iPhoneX: Bool {
return UIScreen.main.nativeBounds.height == 2436
}
}
usage
if UIDevice.current.iPhoneX {
print("This device is a iPhoneX")
}
Detect if the device is iPhone X
Based on your question, the answer is no. There are no direct methods. For more information you can get the information here:
- How to get device make and model on iOS?
and
- how to check screen size of iphone 4 and iphone 5 programmatically in swift
The iPhone X height is 2436 px
From Device Screen Sizes and resolutions:
From Device Screen Sizes and Orientations:
Swift 3 and later:
if UIDevice().userInterfaceIdiom == .phone {
switch UIScreen.main.nativeBounds.height {
case 1136:
print("iPhone 5 or 5S or 5C")
case 1334:
print("iPhone 6/6S/7/8")
case 1920, 2208:
print("iPhone 6+/6S+/7+/8+")
case 2436:
print("iPhone X/XS/11 Pro")
case 2688:
print("iPhone XS Max/11 Pro Max")
case 1792:
print("iPhone XR/ 11 ")
default:
print("Unknown")
}
}
Objective-C:
if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
switch ((int)[[UIScreen mainScreen] nativeBounds].size.height) {
case 1136:
printf("iPhone 5 or 5S or 5C");
break;
case 1334:
printf("iPhone 6/6S/7/8");
break;
case 1920:
case 2208:
printf("iPhone 6+/6S+/7+/8+");
break;
case 2436:
printf("iPhone X/XS/11 Pro");
break;
case 2688:
printf("iPhone XS Max/11 Pro Max");
break;
case 1792:
printf("iPhone XR/ 11 ");
break;
default:
printf("Unknown");
break;
}
}
Xamarin.iOS:
if (UIDevice.CurrentDevice.UserInterfaceIdiom == UIUserInterfaceIdiom.Phone) {
if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1136) {
Console.WriteLine("iPhone 5 or 5S or 5C");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1334) {
Console.WriteLine("iPhone 6/6S/7/8");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1920 || (UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2208) {
Console.WriteLine("iPhone 6+/6S+/7+/8+");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2436) {
Console.WriteLine("iPhone X, XS, 11 Pro");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2688) {
Console.WriteLine("iPhone XS Max, 11 Pro Max");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1792) {
Console.WriteLine("iPhone XR, 11");
} else {
Console.WriteLine("Unknown");
}
}
Based on your question as follow:
Or use screenSize.height as float 812.0f not int 812.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
// 812.0 on iPhone X, XS
// 896.0 on iPhone XS Max, XR.
if (screenSize.height >= 812.0f)
NSLog(@"iPhone X");
}
For more information you can refer the following page in iOS Human Interface Guidelines:
- Adaptivity and Layout - Visual Design - iOS - Human Interface Guidelines
Swift:
Detect with topNotch:
If anyone considering using notch to detect iPhoneX, mind that on "landscape" its same for all iPhones.
var hasTopNotch: Bool {
if #available(iOS 13.0, *) {
return UIApplication.shared.windows.filter {$0.isKeyWindow}.first?.safeAreaInsets.top ?? 0 > 20
}else{
return UIApplication.shared.delegate?.window??.safeAreaInsets.top ?? 0 > 20
}
return false
}
Objective-C:
- (BOOL)hasTopNotch {
if (@available(iOS 13.0, *)) {
return [self keyWindow].safeAreaInsets.top > 20.0;
}else{
return [[[UIApplication sharedApplication] delegate] window].safeAreaInsets.top > 20.0;
}
return NO;
}
- (UIWindow*)keyWindow {
UIWindow *foundWindow = nil;
NSArray *windows = [[UIApplication sharedApplication]windows];
for (UIWindow *window in windows) {
if (window.isKeyWindow) {
foundWindow = window;
break;
}
}
return foundWindow;
}
UPDATE:
Do not use the userInterfaceIdiom property to identify the device type, as the documentation for userInterfaceIdiom explains:
For universal applications, you can use this property to tailor the behavior of your application for a specific type of device. For example, iPhone and iPad devices have different screen sizes, so you might want to create different views and controls based on the type of the current device.
That is, this property is just used to identify the running app's view style. However, the iPhone app (not the universal) could be installed in iPad device via App store, in that case, the userInterfaceIdiom will return the UIUserInterfaceIdiomPhone, too.
The right way is to get the machine name via uname. Check the following for details:
- How to get device make and model on iOS?
trying to detect iphone x in swift always return false
Use like below to detect iPhone X:
var iphoneX = false
if #available(iOS 11.0, *) {
if ((UIApplication.shared.keyWindow?.safeAreaInsets.top)! > CGFloat(0.0)) {
iphoneX = true
}
}
How to know a device is available to use captureTextFromCamera API?
One simple condition:
UITextField().canPerformAction(#selector(UIResponder.captureTextFromCamera(_:))
Tests both device support and language setting support
Detect if the device is iPhone X
Based on your question, the answer is no. There are no direct methods. For more information you can get the information here:
- How to get device make and model on iOS?
and
- how to check screen size of iphone 4 and iphone 5 programmatically in swift
The iPhone X height is 2436 px
From Device Screen Sizes and resolutions:
From Device Screen Sizes and Orientations:
Swift 3 and later:
if UIDevice().userInterfaceIdiom == .phone {
switch UIScreen.main.nativeBounds.height {
case 1136:
print("iPhone 5 or 5S or 5C")
case 1334:
print("iPhone 6/6S/7/8")
case 1920, 2208:
print("iPhone 6+/6S+/7+/8+")
case 2436:
print("iPhone X/XS/11 Pro")
case 2688:
print("iPhone XS Max/11 Pro Max")
case 1792:
print("iPhone XR/ 11 ")
default:
print("Unknown")
}
}
Objective-C:
if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
switch ((int)[[UIScreen mainScreen] nativeBounds].size.height) {
case 1136:
printf("iPhone 5 or 5S or 5C");
break;
case 1334:
printf("iPhone 6/6S/7/8");
break;
case 1920:
case 2208:
printf("iPhone 6+/6S+/7+/8+");
break;
case 2436:
printf("iPhone X/XS/11 Pro");
break;
case 2688:
printf("iPhone XS Max/11 Pro Max");
break;
case 1792:
printf("iPhone XR/ 11 ");
break;
default:
printf("Unknown");
break;
}
}
Xamarin.iOS:
if (UIDevice.CurrentDevice.UserInterfaceIdiom == UIUserInterfaceIdiom.Phone) {
if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1136) {
Console.WriteLine("iPhone 5 or 5S or 5C");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1334) {
Console.WriteLine("iPhone 6/6S/7/8");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1920 || (UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2208) {
Console.WriteLine("iPhone 6+/6S+/7+/8+");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2436) {
Console.WriteLine("iPhone X, XS, 11 Pro");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2688) {
Console.WriteLine("iPhone XS Max, 11 Pro Max");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1792) {
Console.WriteLine("iPhone XR, 11");
} else {
Console.WriteLine("Unknown");
}
}
Based on your question as follow:
Or use screenSize.height as float 812.0f not int 812.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
// 812.0 on iPhone X, XS
// 896.0 on iPhone XS Max, XR.
if (screenSize.height >= 812.0f)
NSLog(@"iPhone X");
}
For more information you can refer the following page in iOS Human Interface Guidelines:
- Adaptivity and Layout - Visual Design - iOS - Human Interface Guidelines
Swift:
Detect with topNotch:
If anyone considering using notch to detect iPhoneX, mind that on "landscape" its same for all iPhones.
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