Generate a Random Float Between 0 and 1

How to get a random number between a float range?

Use random.uniform(a, b):

>>> import random
>>> random.uniform(1.5, 1.9)
1.8733202628557872

Random number between 0 and 1?

You can use random.uniform

import random
random.uniform(0, 1)

Generate a random float between 0 and 1

Random value in [0, 1[ (including 0, excluding 1):

double val = ((double)arc4random() / UINT32_MAX);

A bit more details here.

Actual range is [0, 0.999999999767169356], as upper bound is (double)0xFFFFFFFF / 0x100000000.

Random Float between 0 and 1 in PHP

You may use the standard function: lcg_value().

Here's another function given on the rand() docs:

// auxiliary function
// returns random number with flat distribution from 0 to 1
function random_0_1() 
{
    return (float)rand() / (float)getrandmax();
}

Random float number generation

rand() can be used to generate pseudo-random numbers in C++. In combination with RAND_MAX and a little math, you can generate random numbers in any arbitrary interval you choose. This is sufficient for learning purposes and toy programs. If you need truly random numbers with normal distribution, you'll need to employ a more advanced method.

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This will generate a number from 0.0 to 1.0, inclusive.

float r = static_cast  (rand()) / static_cast  (RAND_MAX);

This will generate a number from 0.0 to some arbitrary float, X:

float r2 = static_cast  (rand()) / (static_cast  (RAND_MAX/X));

This will generate a number from some arbitrary LO to some arbitrary HI:

float r3 = LO + static_cast  (rand()) /( static_cast  (RAND_MAX/(HI-LO)));

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Note that the rand() function will often not be sufficient if you need truly random numbers.

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Before calling rand(), you must first "seed" the random number generator by calling srand(). This should be done once during your program's run -- not once every time you call rand(). This is often done like this:

srand (static_cast  (time(0)));

In order to call rand or srand you must #include .

In order to call time, you must #include .

Generate float Random number between [0,1] and restricting decimal

You could just use Java Random class :

Random rand = new Random();
float f = rand.nextFloat()

which returns the random float number between 0.0f (inclusive) and 1.0f(exclusive).

To round the result of the nextFloat() you could just use an helper method like the following :

public static float round(float d, int decimalPlace) {
    BigDecimal bd = new BigDecimal(Float.toString(d));
    bd = bd.setScale(decimalPlace, BigDecimal.ROUND_HALF_UP);
    return bd.floatValue();
}

Swift random float between 0 and 1

Try initializing the divisor as a float as well, a la:

CGFloat(Float(arc4random()) / Float(UINT32_MAX))

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