Regex to Match All Us Phone Number Formats

Regular expression to match standard 10 digit phone number

^(\+\d{1,2}\s)?\(?\d{3}\)?[\s.-]\d{3}[\s.-]\d{4}$

Matches the following

123-456-7890
(123) 456-7890
123 456 7890
123.456.7890
+91 (123) 456-7890

If you do not want a match on non-US numbers use

^(\+0?1\s)?\(?\d{3}\)?[\s.-]\d{3}[\s.-]\d{4}$

Update :
As noticed by user Simon Weaver below, if you are also interested in matching on unformatted numbers just make the separator character class optional as [\s.-]?

^(\+\d{1,2}\s)?\(?\d{3}\)?[\s.-]?\d{3}[\s.-]?\d{4}$

How to validate phone numbers using regex

Better option... just strip all non-digit characters on input (except 'x' and leading '+' signs), taking care because of the British tendency to write numbers in the non-standard form +44 (0) ... when asked to use the international prefix (in that specific case, you should discard the (0) entirely).

Then, you end up with values like:

 12345678901
 12345678901x1234
 345678901x1234
 12344678901
 12345678901
 12345678901
 12345678901
 +4112345678
 +441234567890

Then when you display, reformat to your hearts content. e.g.

  1 (234) 567-8901
  1 (234) 567-8901 x1234

Regex to match all us phone number formats

\(?\d{3}\)?-? *\d{3}-? *-?\d{4}

Regular expression to validate US phone numbers?

The easiest way to match both

^\([0-9]{3}\)[0-9]{3}-[0-9]{4}$

and

^[0-9]{3}-[0-9]{3}-[0-9]{4}$

is to use alternation ((...|...)): specify them as two mostly-separate options:

^(\([0-9]{3}\)|[0-9]{3}-)[0-9]{3}-[0-9]{4}$

By the way, when Americans put the area code in parentheses, we actually put a space after that; for example, I'd write (123) 123-1234, not (123)123-1234. So you might want to write:

^(\([0-9]{3}\) |[0-9]{3}-)[0-9]{3}-[0-9]{4}$

(Though it's probably best to explicitly demonstrate the format that you expect phone numbers to be in.)

What regular expression will match valid international phone numbers?

\+(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{1,14}$

Is the correct format for matching a generic international phone number. I replaced the US land line centric international access code 011 with the standard international access code identifier of '+', making it mandatory. I also changed the minimum for the national number to at least one digit.

Note that if you enter numbers in this format into your mobile phone address book, you may successfully call any number in your address book no matter where you travel. For land lines, replace the plus with the international access code for the country you are dialing from.

Note that this DOES NOT take into account national number plan rules - specifically, it allows zeros and ones in locations that national number plans may not allow and also allows number lengths greater than the national number plan for some countries (e.g., the US).

US phone number format validation with regex

You can match these numbers using the following regex:

String rx = "[\\(]?\\d{3}[\\)]?([-.]?)\\s*\\d{3}\\1\\s*\\d{4}";

See IDEONE demo

The ([-.]?) construct is a capturing group that captures and stores the matched text in some buffer, and then we can access that text using \\1 backreference later.

Note that in case you need a whole string match, use String.matches() method with the regex.

Regular Expression to reformat a US phone number in Javascript

Assuming you want the format "(123) 456-7890":

function formatPhoneNumber(phoneNumberString) {
  var cleaned = ('' + phoneNumberString).replace(/\D/g, '');
  var match = cleaned.match(/^(\d{3})(\d{3})(\d{4})$/);
  if (match) {
    return '(' + match[1] + ') ' + match[2] + '-' + match[3];
  }
  return null;
}

Here's a version that allows the optional +1 international code:

function formatPhoneNumber(phoneNumberString) {
  var cleaned = ('' + phoneNumberString).replace(/\D/g, '');
  var match = cleaned.match(/^(1|)?(\d{3})(\d{3})(\d{4})$/);
  if (match) {
    var intlCode = (match[1] ? '+1 ' : '');
    return [intlCode, '(', match[2], ') ', match[3], '-', match[4]].join('');
  }
  return null;
}
formatPhoneNumber('+12345678900') // => "+1 (234) 567-8900"
formatPhoneNumber('2345678900')   // => "(234) 567-8900"

Validate phone number with JavaScript

First off, your format validator is obviously only appropriate for NANP (country code +1) numbers. Will your application be used by someone with a phone number from outside North America? If so, you don't want to prevent those people from entering a perfectly valid [international] number.

Secondly, your validation is incorrect. NANP numbers take the form NXX NXX XXXX where N is a digit 2-9 and X is a digit 0-9. Additionally, area codes and exchanges may not take the form N11 (end with two ones) to avoid confusion with special services except numbers in a non-geographic area code (800, 888, 877, 866, 855, 900) may have a N11 exchange.

So, your regex will pass the number (123) 123 4566 even though that is not a valid phone number. You can fix that by replacing \d{3} with [2-9]{1}\d{2}.

Finally, I get the feeling you're validating user input in a web browser. Remember that client-side validation is only a convenience you provide to the user; you still need to validate all input (again) on the server.

TL;DR don't use a regular expression to validate complex real-world data like phone numbers or URLs. Use a specialized library.

RegEx for validating US phone number format

You can add an optional match at the end of the regex

( x\d{4})?

Which will match x followed by digits, that is eg x1234 if it is present

( x\d{4})? the quantifier ? matches zero or one occurence of ( x\d{4})

The regex can be

^\(?(\d{3})\)?[-\. ]?(\d{3})[-\. ]?(\d{4})( x\d{4})?$

For example : http://regex101.com/r/sG9qJ6/1