Regex: C# Extract Text Within Double Quotes

Unable to extract string between double quotes using regex

This regex should work

"(.+?)"

Regex101 demo

It uses the concept of Group capture

Extract the values between the double quotes using regex

You may use a regex that will match quote, New, some chars other than " and :, then :, and then any chars but " up to a ":

var keys = Regex.Matches(emailBody, @"""New[^"":]+:[^""]+""", RegexOptions.Singleline)
       .OfType<Match>()
       .Select(m => m.Value)
       .Distinct()
       .ToArray();

See the regex demo

Sample Image

Pattern details:

" - a literal double quote
New - a literal substring
[^":]+ - 1 or more characters other than " and : (the [^...] is a negated character class)
: - a literal colon
[^"]+ - 1 or more characters other than "
" - a literal double quote

Regex to extract string between quotes

Use positive lookbehind operator:

GroupCollection ids = Regex.Match(nodeValue, "(?<=ID=\")[^\"]*").Groups;

You also used a capturing group (the parenthesis), this is why you get 2 results.

Get numbers between quotes and backslash with regex in C#

If you needed to match a digit sequence between two double quotes, you could use var resultfinal = Regex.Match(input, @"(?<="")[0-9]+(?="")")?.Value;. However, your original string contains escaped quotation marks, so you need to extract a digit sequence in between two \" substrings.

You can use

var input = "\\\"26201\\\",7\\0\\0";
var firstPattern = @"(?<=\\"")[0-9]+(?=\\"")";
var resultfinal = Regex.Match(input, firstPattern)?.Value;
Console.WriteLine($"final result: '{resultfinal}'");
// => final result: '26201'

See the C# demo. The pattern is (?<=\\")[0-9]+(?=\\"), see its online demo. Details:

(?<=\\") - a positive lookbehind that requires a \" substring to occur immediately to the left of the current location
[0-9]+ - one or more ASCII digits (note \d+ matches any one or more Unicode digits including Hindi, Persian etc. digits unless the RegexOptions.ECMAScript option is used)
(?=\\") - a positive lookahead that requires a \" substring to occur immediately to the right of the current location.

Regex - Extract Words within brackets and quotes if it starts with a keyword only

The solution offered by Wiktor is the most logical to use, but for sake of RegEx challenge see this Pattern \[(?!mykey)[^\[]+|([^\s\[=\"]+)(?=[^\"]*\"\]), check group #1 Demo

\[                  # "["
(?!                 # Negative Look-Ahead
  mykey             # "mykey"
)                   # End of Negative Look-Ahead
[^\[]               # Character not in [\[] Character Class
+                   # (one or more)(greedy)
|                   # OR
(                   # Capturing Group (1)
  [^\s\[=\"]        # Character not in [\s\[=\"] Character Class
  +                 # (one or more)(greedy)
)                   # End of Capturing Group (1)
(?=                 # Look-Ahead
  [^\"]             # Character not in [\"] Character Class
  *                 # (zero or more)(greedy)
  \"                # """
  \]                # "]"
)                   # End of Look-Ahead

c# regex to capture everything between 2 double-quotes, escaped double-quote included

This regex should solve your purpose -

str = Regex.Replace(str, @"(""[^""\\]*(?:\\.[^""\\]*)*"")|", "$1");

RegEx: Grabbing values between quotation marks

I've been using the following with great success:

(["'])(?:(?=(\\?))\2.)*?\1

It supports nested quotes as well.

For those who want a deeper explanation of how this works, here's an explanation from user ephemient:

([""']) match a quote; ((?=(\\?))\2.) if backslash exists, gobble it, and whether or not that happens, match a character; *? match many times (non-greedily, as to not eat the closing quote); \1 match the same quote that was use for opening.

How to use Regex to search only inside strings (between double quotations)

Hint: .* means any number of any characters

With regex if you search \"class\" it exactly matches "class".

To match "<anything>class<anything>" add any number of any characters before and after class:

\".*class.*\"

To match '<anything>class<anything>' as well (such as javascript strings) use this:

["'](.*)(class)(.*)["']

Regular expressions: extract all words out of quotes

Try this expression:

(?:^|")([^"]*)(?:$|")

The groups matched by it will exclude the quotation marks, because they are enclosed in non-capturing parentheses (?: and ). Of course you need to escape the double-quotes for use in C# code.

If the target string starts and/or ends in a quoted value, this expression will match empty groups as well (for the initial and for the trailing quote).