How to Remove New Line Characters from a String

How to remove line breaks from a file in Java?

You need to set text to the results of text.replace():

String text = readFileAsString("textfile.txt");
text = text.replace("\n", "").replace("\r", "");

This is necessary because Strings are immutable -- calling replace doesn't change the original String, it returns a new one that's been changed. If you don't assign the result to text, then that new String is lost and garbage collected.

As for getting the newline String for any environment -- that is available by calling System.getProperty("line.separator").

How to remove new line characters from a string?

I like to use regular expressions. In this case you could do:

string replacement = Regex.Replace(s, @"\t|\n|\r", "");

Regular expressions aren't as popular in the .NET world as they are in the dynamic languages, but they provide a lot of power to manipulate strings.

How to remove all line breaks from a string

Line breaks (better: newlines) can be one of Carriage Return (CR, \r, on older Macs), Line Feed (LF, \n, on Unices incl. Linux) or CR followed by LF (\r\n, on WinDOS). (Contrary to another answer, this has nothing to do with character encoding.)

Therefore, the most efficient RegExp literal to match all variants is

/\r?\n|\r/

If you want to match all newlines in a string, use a global match,

/\r?\n|\r/g

respectively. Then proceed with the replace method as suggested in several other answers. (Probably you do not want to remove the newlines, but replace them with other whitespace, for example the space character, so that words remain intact.)

How can I remove a newline character in a string in python

Are you sure it's '\n' character and not '\\n' two character sequence? If it's '\n', x.rstrip() should work. Otherwise, try x.replace('\\n','')

Remove all line breaks from a long string of text

How do you enter line breaks with raw_input? But, once you have a string with some characters in it you want to get rid of, just replace them.

>>> mystr = raw_input('please enter string: ')
please enter string: hello world, how do i enter line breaks?
>>> # pressing enter didn't work...
...
>>> mystr
'hello world, how do i enter line breaks?'
>>> mystr.replace(' ', '')
'helloworld,howdoienterlinebreaks?'
>>>

In the example above, I replaced all spaces. The string '\n' represents newlines. And \r represents carriage returns (if you're on windows, you might be getting these and a second replace will handle them for you!).

basically:

# you probably want to use a space ' ' to replace `\n`
mystring = mystring.replace('\n', ' ').replace('\r', '')

Note also, that it is a bad idea to call your variable string, as this shadows the module string. Another name I'd avoid but would love to use sometimes: file. For the same reason.

Remove all newlines from inside a string

strip only removes characters from the beginning and end of a string. You want to use replace:

str2 = str.replace("\n", "")
re.sub('\s{2,}', ' ', str) # To remove more than one space

Remove New Lines From String Without Removing \n?

you could print it as a real string

this is done with the letter r

example 1:

print(r"You can use \n to print a new line.") 
# You can use \n to print a new line.

this will not remove it, but make it visible as you want in the output

example 2:

text = r"You can use \n to print a new line."

print(text) 
# You can use \n to print a new line.

How to remove a newline from a string in Bash

Under bash, there are some bashisms:

The tr command could be replaced by // bashism:

COMMAND=$'\nREBOOT\r   \n'
echo "|${COMMAND}|"
|
   OOT
|

echo "|${COMMAND//[$'\t\r\n']}|"
|REBOOT   |

echo "|${COMMAND//[$'\t\r\n ']}|"
|REBOOT|

See Parameter Expansion and QUOTING in bash's man page:

man -Pless\ +/\/pattern bash
man -Pless\ +/\\\'string\\\' bash

man -Pless\ +/^\\\ *Parameter\\\ Exp bash
man -Pless\ +/^\\\ *QUOTING bash

Further...

As asked by @AlexJordan, this will suppress all specified characters. So what if $COMMAND do contain spaces...

COMMAND=$'         \n        RE BOOT      \r           \n'
echo "|$COMMAND|"
|
           BOOT      
|

CLEANED=${COMMAND//[$'\t\r\n']}
echo "|$CLEANED|"
|                 RE BOOT                 |

shopt -q extglob || { echo "Set shell option 'extglob' on.";shopt -s extglob;}

CLEANED=${CLEANED%%*( )}
echo "|$CLEANED|"
|                 RE BOOT|

CLEANED=${CLEANED##*( )}
echo "|$CLEANED|"
|RE BOOT|

Shortly:

COMMAND=$'         \n        RE BOOT      \r           \n'
CLEANED=${COMMAND//[$'\t\r\n']} && CLEANED=${CLEANED%%*( )}
echo "|${CLEANED##*( )}|"
|RE BOOT|

Note: bash have extglob option to be enabled (shopt -s extglob) in order to use *(...) syntax.

Is there a way to remove a newline character within a string in an array?

You could for example split, remove all the empty entries, and then trim each item to also remove all the leading and trailing whitespace characters including the newlines.

Note that you don't have to escape the space and the hyphen.

const input = `- foo
- bar`;
const chunks = input.split(/ ?- ?/)
  .filter(Boolean)
  .map(s => s.trim());

console.log(chunks);