Convert Binary String into Integer

How to convert a Binary String to a base 10 integer in Java

You need to specify the radix. There's an overload of Integer#parseInt() which allows you to.

int foo = Integer.parseInt("1001", 2);

Convert base-2 binary number string to int

You use the built-in int() function, and pass it the base of the input number, i.e. 2 for a binary number:

>>> int('11111111', 2)
255

Here is documentation for Python 2, and for Python 3.

Converting a binary string to integer

char *binaryString[100];

// You are creating an array of pointers in this scenario, use char binaryString[100] instead;

int value = (int)strtol(binaryString, NULL, 2);

// 101010111100110100110001001001000101 Is a 36 bit number, int (in most implementations) is 32 bit. use long long (64 bit in visual c++) as type and strtoll as function instead.

printf("%i \n",value)

Must be printf("%lld \n", value).

In summary:

#include "stdio.h"
#include "stdlib.h" // required for strtoll

int main(void)
{
    char str[100] = "101010111100110100110001001001000101";
    long long val = 0;
    val = strtoll(str, NULL, 2);
    //output string as int
    printf("%lld \n", val);
    return 0;
}

How to convert Binary String to int array?

I know symptomsBit.split(" ") isn't correct. But do not know how to
further improve it.

Yes, you're almost there but must have made a few minor mistakes.

For one, that split() isn't correct because you're trying to split it on " "s but what you need is ""s because it's a continuous string.

That will give you the array that you think you're getting. But you also don't print the elements right. You should index into the array to get the element to print. Like so...

int symptomsM = 867;
String symptomsBit = Integer.toBinaryString(symptomsM);
String[] symptomsBitArr = symptomsBit.split("");
System.out.println("symptomsBit: " + symptomsBit);
System.out.println("symptomsBitArray: " + symptomsBitArr);
int[] symptomsArray = new int[symptomsBitArr.length];
for (int i = 0; i < symptomsBitArr.length; i++) {
    symptomsArray[i] = Integer.parseInt(symptomsBitArr[i]);
    System.out.println("symptomsArray: " + symptomsArray[i]);
}

java: convert binary string to int

From http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Integer.html#toBinaryString(int) : the toBinaryString() method converts its input into the binary representation of the "unsigned integer value is the argument plus 2³² if the argument is negative".

From http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Integer.html#parseInt(java.lang.String,%20int) : the parseInt() method throws NumberFormatException if "The value represented by the string is not a value of type int".

Note that both ~0 and ~1 are negative (-1 and -2 respectively), so will be converted to the binary representations of 2³²-1 and 2³²-2 respectively, neither of which can be represented in a value of type int, so causing the NumberFormatException that you are seeing.