non-standard syntax; use '&' to create a pointer to member error in Visual Studio 2015
If you use
if (usersList[i]->getUsername() != excludeUser->getUsername)
instead of
if (usersList[i]->getUsername() != excludeUser->getUsername())
your compiler will think you want to use a function pointer instead of the method itself, and if you would have wanted to use a function pointer, you would still have to get the address of it (using &).
So make sure you don't forget your () after a function call!
Visual Studio 2015 “non-standard syntax; use '&' to create a pointer to member”
The problem is with the lines which contain the following (it appears twice in your code):
Board.player1Move;
Player one move is a function which receive an std::string parameter as an input. In order to call it you'll need to create an std::string object and pass it as an argument for the function. You can use the following syntax if you want the string to be given as an input:
std::string move;
cin >> move;
Board.player1Move(move);
Also, notice that player2Turn should call Board.player2Move instead of Board.player1Move.
C++ Visual Studio Non-standard syntax; use '&' to create a pointer to member
You forgot the function call operator ()
. Change your main
code to:
int main(){
BankAccount bankAccount1("testName", 200.0);
cout << bankAccount1.amountOfMoney() << endl;
}
Without the parentheses it tries to print the address of a member function, which it is not able to do unless the function is not a member of a class.
Getting non-standard syntax; use '&' to create a pointer to member for std::sort
custom_sort
is a non-static member function, it can't work with sort
directly because under the hood it expects three arguments, not two - the first one is the object pointer.
In your particular example, custom_sort
doesn't use any data members, so it can be made static
(static
should go into the declaration):
static bool LinearRegression::custom_sort(double a, double b);
Then you could write:
std::sort(error.begin(), error.end(), &custom_sort);
Note that you need &
to form a pointer to a member function, as the error message suggests. However, for static
member function it can be omitted (similar to free functions).
Non-standard syntax; use '&' to create a pointer member. Error on display function c++
GetHeight is not a variable, but a function, add parenthesis:
void Display()
{
cout << "Height: " << GetHeight() << " " << "Width: " << GetWidth() << " " << "Area: " << GetArea() << " " << "Perimeter: " << GetPerimeter() << endl;
};
Visual Studio 'non-standard syntax; use '&' to create a pointer to member'
The type of the expression a->testInA
is a pointer to a non-static
member function.
It does not have the same type as fptr
, so the compiler emits an error, albeit a cryptic one.
Compilation would pass if testInA
were static
.
See C++ function pointer (class member) to non-static member function for more details.
VS2017 non-standard syntax; use '&' to create a pointer to member
On the line
cout << "BySimpson:" << MyInt.BySimpson << endl << endl;
You probably meant to make a call to BySimpson but your forgot the ()
cout << "BySimpson:" << MyInt.BySimpson() << endl << endl;
The reason you get this misleading error is because pre ISO standarization MyInt.BySimpson would actually mean you wanted the address just like for normal function the function name on its own gives the address of the function. Later however the use of & to take the address of a member was put in the standard as a requirement. So Visual Studio thinks you are still using the old syntax and wants you to use the new syntax.
C++ Visual Studio non-standard syntax use '&' to create a pointer to member
You need to call the toInt
method of Integer
:
this->equal(val.toInt());
C++ Visual Studio 2015: non-standard syntax; use '&' to create a pointer to member
This line here is not correct:
string st = deck[2].toString;
The proper way to call a function in C++ (actually Java too I thought) is this:
string st = deck[2].toString();
Visual Studio 2015 “non-standard syntax; use '&' to create pointer for member”
Parameter #2 of the CreateThread must be a pointer to function matching ThreadProc signature. You can not pass result of pSample->Resize() (which is void) or a pointer to Resize function itself (because this is a non-static class member function). Also you may want to use ::std::thread instead of calling WinApi directly.
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