How to Show One Layout on Top of the Other Programmatically in My Case

How to show one layout on top of the other programmatically in my case?

Use a FrameLayout with two children. The two children will be overlapped. This is recommended in one of the tutorials from Android actually, it's not a hack...

Here is an example where a TextView is displayed on top of an ImageView:

<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
  android:layout_width="fill_parent"
  android:layout_height="fill_parent">

  <ImageView  
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent" 

    android:scaleType="center"
    android:src="@drawable/golden_gate" />

  <TextView
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:layout_marginBottom="20dip"
    android:layout_gravity="center_horizontal|bottom"

    android:padding="12dip"

    android:background="#AA000000"
    android:textColor="#ffffffff"

    android:text="Golden Gate" />

</FrameLayout>

Is it possible to place one view over another in android?

FrameLayouts let you pile each view on top of the one below. This can also be achieved with a RelativeLayout.

how to put 2 layouts on top of each others

Use Relative layout to place views on top of each other , like this

 <RelativeLayout
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_gravity="bottom|center"
        android:background="#f00"
        android:orientation="vertical"
        android:weightSum="1" >

        <RelativeLayout
            android:layout_width="wrap_content"
            android:layout_height="170dp"
            android:layout_centerInParent="true"
            android:layout_gravity="bottom|center"
            android:background="#fff"
            android:gravity="bottom"
            android:orientation="vertical" >

            <LinearLayout
                android:layout_width="10dp"
                android:layout_height="100sp"
                android:layout_centerInParent="true"
                android:layout_marginLeft="10sp"
                android:background="#37c100" >
            </LinearLayout>

            <LinearLayout
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:layout_marginLeft="6sp"
                android:background="@drawable/arrow_shape" >
            </LinearLayout>
        </RelativeLayout>

        <LinearLayout
            android:layout_width="wrap_content"
            android:layout_height="150dp"
            android:layout_centerInParent="true"
            android:layout_margin="25sp"
            android:layout_weight="0.5"
            android:background="#0000ff"
            android:gravity="center" >

            <TextView
                android:layout_width="wrap_content"
                android:layout_height="wrap_content"
                android:text="40 000 "
                android:textColor="#ffffff"
                android:textSize="25sp" />
        </LinearLayout>
    </RelativeLayout>

How would I display one view as an overlay of another?

Use a RelativeLayout for starters.

You could use the ViewGroup.addView(View child, int index, ViewGroup.LayoutParams params) or a variant along with ViewGroup.removeView(View view) or ViewGroup.removeViewAt(int index).

This would obviously require you to inflate the views manually using LayoutInflater but you could keep a global reference to each after inflating and just flip between the two.

Android ConstraintLayout - Put one view on top of another view

Set an elevation on the ProgressBar; 2dp seems to work.

android:elevation="2dp"

You could also try setting translationZ as suggested in the accepted answer to a similar question.

I also came across this answer as an alternative.

Programmatically add view one below other in relative layout

Important: Remember to set the ID for each view.

RelativeLayout layout = new RelativeLayout(this);
RelativeLayout.LayoutParams layoutParams = new RelativeLayout.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
layout.setLayoutParams(layoutParams);

RelativeLayout.LayoutParams params1 = new RelativeLayout.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
RelativeLayout.LayoutParams params2 = new RelativeLayout.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
RelativeLayout.LayoutParams params3 = new RelativeLayout.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);
RelativeLayout.LayoutParams params4 = new RelativeLayout.LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

TextView tv1 = new TextView(this);
tv1.setId(1);
tv1.setText("textView1");

TextView tv2 = new TextView(this);
params2.addRule(RelativeLayout.RIGHT_OF, tv1.getId());
tv2.setId(2);
tv2.setText("textView2");

TextView tv3 = new TextView(this);
params3.addRule(RelativeLayout.BELOW, tv1.getId());
tv3.setId(3);
tv3.setText("textView3");

TextView tv4 = new TextView(this);
params4.addRule(RelativeLayout.RIGHT_OF, tv3.getId());
params4.addRule(RelativeLayout.ALIGN_BOTTOM, tv3.getId());
tv4.setId(4);
tv4.setText("textView4");

layout.addView(tv1, params1);
layout.addView(tv2, params2);
layout.addView(tv3, params3);
layout.addView(tv4, params4);

How to define a layout with two parts in my case

I am thinking to define two separate layout files, e.g. yellow_area.xml & green_area.xml, and includes them in one main.xml.

If you are wanting to re-use one or both of them then doing this or using fragments is a fine idea...whichever works best in your case.

But how to keep yellow area always visible & have green area scrollable? (That's to make yellow area looks like it is above green area)

You should be able to accomplish this by using a RelativeLayout and using the property

android:layout_below="@id/topLayout"

in the <include> tag for your "greeen layout assuming that topLayout is the id of your "yellow" layout.

Edit

I think my above answer didn't work due to the number of Views inside of the included layout. Using a LinearLayout as the parent layout and using layout_weight inside of each child layout ( and ListView fixes the problem. Something like

    ?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent" 
    android:orientation="vertical"
    android:layout_gravity="center_horizontal"
    android:gravity="center_horizontal"
    >
    <!--included a title_layout-->
   <include
        android:id="@+id/upper_area"  
        android:layout_width="fill_parent"
        android:layout_height="0dp"   
        layout="@layout/title_layout"
        android:layout_weight=".25"/>    // add weight here 

    <!--Listview below title_layout-->
    <ListView
        android:id="@+id/data_list"
        android:layout_width="fill_parent"
        android:layout_height="0dp"
        android:layout_weight=".75"  />      // and here

</LinearLayout> 

Using layout_weight with a vertical orientation the height must be set to 0dp (layout_width="0dp" for horizontal orientation)

How to create a RelativeLayout programmatically with two buttons one on top of the other?

Found the answer in How to lay out Views in RelativeLayout programmatically?

We should explicitly set id's using setId(). Only then, RIGHT_OF rules make sense.

Another mistake I did is, reusing the layoutparams object between the controls. We should create new object for each control

View over another View use RelativeLayout or?

You can use FrameLayout or RelativeLayout. But I recommend RelativeLayout as it is more flexible and easier to use.

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