How to Rotate a Bitmap 90 Degrees

C# rotate bitmap 90 degrees

What about this:

private void RotateAndSaveImage(String input, String output)
{
    //create an object that we can use to examine an image file
    using (Image img = Image.FromFile(input))
    {
        //rotate the picture by 90 degrees and re-save the picture as a Jpeg
        img.RotateFlip(RotateFlipType.Rotate90FlipNone);
        img.Save(output, System.Drawing.Imaging.ImageFormat.Jpeg);
    }
}

Rotating a bitmap 90 degrees

v = (v & 0x000000000f0f0f0fUL) << 004 | (v & 0x00000000f0f0f0f0UL) << 040 |
    (v & 0xf0f0f0f000000000UL) >> 004 | (v & 0x0f0f0f0f00000000UL) >> 040;
v = (v & 0x0000333300003333UL) << 002 | (v & 0x0000cccc0000ccccUL) << 020 | 
    (v & 0xcccc0000cccc0000UL) >> 002 | (v & 0x3333000033330000UL) >> 020;
v = (v & 0x0055005500550055UL) << 001 | (v & 0x00aa00aa00aa00aaUL) << 010 | 
    (v & 0xaa00aa00aa00aa00UL) >> 001 | (v & 0x5500550055005500UL) >> 010;

Rotate a saved bitmap in android

void rotate(float x)
    {
        Bitmap bitmapOrg = BitmapFactory.decodeResource(getResources(),R.drawable.tedd);

        int width = bitmapOrg.getWidth();

        int height = bitmapOrg.getHeight();

        int newWidth = 200;

        int newHeight  = 200;

        // calculate the scale - in this case = 0.4f

         float scaleWidth = ((float) newWidth) / width;

         float scaleHeight = ((float) newHeight) / height;

         Matrix matrix = new Matrix();

         matrix.postScale(scaleWidth, scaleHeight);
         matrix.postRotate(x);

         Bitmap resizedBitmap = Bitmap.createBitmap(bitmapOrg, 0, 0,width, height, matrix, true);

         iv.setScaleType(ScaleType.CENTER);
         iv.setImageBitmap(resizedBitmap);
    }

How do you rotate a bitmap an arbitrary number of degrees?

I did some searching for you and found this:

public static Bitmap RotateImage(Bitmap b, float angle)
{
  //create a new empty bitmap to hold rotated image
  Bitmap returnBitmap = new Bitmap(b.Width, b.Height);
  //make a graphics object from the empty bitmap
  using(Graphics g = Graphics.FromImage(returnBitmap)) 
  {
      //move rotation point to center of image
      g.TranslateTransform((float)b.Width / 2, (float)b.Height / 2);
      //rotate
      g.RotateTransform(angle);
      //move image back
      g.TranslateTransform(-(float)b.Width / 2, -(float)b.Height / 2);
      //draw passed in image onto graphics object
      g.DrawImage(b, new Point(0, 0)); 
  }
  return returnBitmap;
}

Rotating a bitmap 90 degrees and saving

I found the answer!

For JPG files, apparently you can just niftily edit the exif data using the following method:

ExifInterface exif = new ExifInterface(myFile.getAbsolutePath());
exif.setAttribute(ExifInterface.TAG_ORIENTATION, "6");
exif.saveAttributes();

Are there any downsides to using this approach? It seems to work pretty well as far as I can determine..

How to Rotate Image 90 degrees

You'd want to use a Gdk.Pixbuf, which uses the GDK+ libraries to manipulate images.

var img = Gdk.Pixbuf.from_file(input);
var rotate_image = img.rotate_simple(90);
rotate_image.save(output, "jpeg");

It's worth noting that Vala is not meant to be directly compatible with C#.

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