Type 'Bundle' Has No Member "Module"

Generating resource_bundle_accessor, Type 'Bundle' has no member 'module'

SPM generates the resource_bundle_accessor only if the corresponding target contains resources as the argument like:

    .target(
        name: "ChenzookKit",
        dependencies: ["Apollo"],
        resources: [.process("Resources")] // <- `copy` or `process` doesn't really matter 
    ),

_{Also, note that it should be a valid resource path.}

AND❗️

The project MUST actaully contains Resources inside the target's Directory!

AND❗️❗️

Don't forget to build (cmd+b) the code to make the .module be created!

Swift Package Manager - Type 'Bundle' has no member “module” error

Besides all errors in the test file, the only issue remains is that module is not an optional. To fix that, just change this:

public let unimodURL = Bundle.module?.url(forResource: "unimod", withExtension: "XML")

to:

public let unimodURL = Bundle.module.url(forResource: "unimod", withExtension: "xml")

---

Update:

If you use .xcodeproj file, you will continue seeing this error. You should consider opening it with the package.swift or import it as a package (instead of converting it to a project)!

by the way, here is the generated file, so you can add it as a development asset when you are working with the xcodeproject:

import class Foundation.Bundle

private class BundleFinder {}

extension Foundation.Bundle {
    /// Returns the resource bundle associated with the current Swift module.
    static var module: Bundle = {
        let bundleName = "BioSwift_BioSwift"

        let candidates = [
            // Bundle should be present here when the package is linked into an App.
            Bundle.main.resourceURL,

            // Bundle should be present here when the package is linked into a framework.
            Bundle(for: BundleFinder.self).resourceURL,

            // For command-line tools.
            Bundle.main.bundleURL,
        ]

        for candidate in candidates {
            let bundlePath = candidate?.appendingPathComponent(bundleName + ".bundle")
            if let bundle = bundlePath.flatMap(Bundle.init(url:)) {
                return bundle
            }
        }
        fatalError("unable to find bundle named BioSwift_BioSwift")
    }()
}

Swift Package Manager with resources compile errors

You missed a , after the target close parentheses:

        .target(
            name: "BioSwift",
            resources: [
               .process("Resources/unimod.xml"),
               .process("Resources/aminoacids.json"),
               .process("Resources/elements.json"),
               .process("Resources/enzymes.json"),
               .process("Resources/functionalgroups.json"),
               .process("Resources/hydropathy.json")
            ]
        ), // Here is the missed `,`

Also, you don't need to add files one by one! Instead, you can add a directory:

.process("Resources")

I get the error: Value of type 'Bundle' has no member 'pathForResources'

You are mixing up Swift 2 and 3 code and even in Swift 2 there is no pathForResources (plural) API.

If you are looking for an URL use the URL related API:

Bundle.main.url(forResource: "Music", withExtension: "mp3")

and the AVAudioPlayer initializer throws

do {
    let url = Bundle.main.url(forResource: "Music", withExtension: "mp3")!
    let backgroundAudio = try AVAudioPlayer(contentsOf: url)
} catch {
    print(error)
}

In this case you can even write

   let url = Bundle.main.url(forResource: "Music", withExtension: "mp3")!
   let backgroundAudio = try! AVAudioPlayer(contentsOf: url)

because the initializer will succeed always (if it does not it's a design error).

Edit:

This is a way to create the audio player with a closure

class ViewController: UIViewController {

    let backgroundAudio : AVAudioPlayer = {
        let url = Bundle.main.url(forResource: "Music", withExtension: "mp3")!
        return try! AVAudioPlayer(contentsOf: url)
    }()

}

and play the sound

let controller = ViewController()
controller.backgroundAudio.play()

---

PS: Do not use NS... classes like NSURL if there is a native Swift counterpart (URL)

---

Related Topics