Reversing the order of a string value
Commented inline,
func reverse(_ s: String) -> String {
var str = ""
//.characters gives the character view of the string passed. You can think of it as array of characters.
for character in s.characters {
str = "\(character)" + str
//This will help you understand the logic.
//!+""
//p+!
//l+p! ... goes this way
print ( str)
}
return str
}
print (reverse("!pleH"))
Reverse the order of characters within words with five letters or more
Hy Pawel Niewolak, the issue is with your reverse function.
Depending on your requirements use that:
public static String reverse(String s) {
String[] ori = s.split("");
String[] rev = new String[ori.length];
for (int i = 0; i < rev.length; i++) {
rev[i] = ori[rev.length - i - 1];
}
s = "";
for (String str : rev) {
s += str;
}
return s;
}
}
Reverse a string in Java
You can use this:
new StringBuilder(hi).reverse().toString()
StringBuilder
was added in Java 5. For versions prior to Java 5, the StringBuffer
class can be used instead — it has the same API.
reverse the order of characters in a string
Simple:
var="12345"
copy=${var}
len=${#copy}
for((i=$len-1;i>=0;i--)); do rev="$rev${copy:$i:1}"; done
echo "var: $var, rev: $rev"
Output:
$ bash rev
var: 12345, rev: 54321
Best way to reverse a string
public static string Reverse( string s )
{
char[] charArray = s.ToCharArray();
Array.Reverse(charArray);
return new string(charArray);
}
Reverse a string in Python
Using slicing:
>>> 'hello world'[::-1]
'dlrow olleh'
Slice notation takes the form [start:stop:step]
. In this case, we omit the start
and stop
positions since we want the whole string. We also use step = -1
, which means, "repeatedly step from right to left by 1 character".
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