How to define an array of functions in C
I have a struct that contains a declaration like this one:
No you don't. That's a syntax error. You're looking for:
void (*functions[256])();
Which is an array of function pointers. Note, however, that void func()
isn't a "function that takes no arguments and returns nothing." It is a function that takes unspecified numbers or types of arguments and returns nothing. If you want "no arguments" you need this:
void (*functions[256])(void);
In C++, void func()
does mean "takes no arguments," which causes some confusion (especially since the functionality C specifies for void func()
is of dubious value.)
Either way, you should typedef
your function pointer. It'll make the code infinitely easier to understand, and you'll only have one chance (at the typedef
) to get the syntax wrong:
typedef void (*func_type)(void);
// ...
func_type functions[256];
Anyway, you can't assign to an array, but you can initialize an array and copy the data:
static func_type functions[256] = { /* initializer */ };
memcpy(mystruct.functions, functions, sizeof(functions));
Javascript Array of Functions
var array_of_functions = [
first_function,
second_function,
third_function,
forth_function
]
and then when you want to execute a given function in the array:
array_of_functions[0]('a string');
How to declare an array of functions?
Strictly speaking you may not declare an array of functions. You may declare an array of function pointers.
It seems you mean
int (*funcs[10])(int, int);
Another way is to introduce a using declaration (or a typedef declaration) like for example
using FP = int( * )( int, int );
FP funcs[10];
or
using FUNC = int ( int, int );
FUNC * funcs[10];
Julia - generate an array of functions programmatically
When you use fill
with f
it sets expected type for the elements of f_array
to f
, in the code below I am switching to abstract type to make it possible to have any function in the array
# create simple function just to initialize
f(x)=x
# initialize array of functions
N = 3
f_array = Array{Function}(undef, N);
f_array[1] = f;
# now we update each function
for i in 2:N
f_array[i] = x -> 3 * f_array[i-1](x)
end
print(f_array[3](2))
which produces a value of 18
How to create an array of functions in C#?
It seems to me that your for
loops could be expressed like this instead:
// For Game 1
result1 = string.Join("-", StoreGame1.Select(item => item.Text));
// For Game 2
result2 = string.Join("-", StoreGame2.Select(item => item.Text));
// For Game 3
result3 = string.Join("-", StoreGame3.Select(item => item.Text));
Wouldn't that work just as well for you?
Why can't I declare an array of functions in Java?
You could try this:
public static void testFunction() {
Map<String, Function<Book, String>> mapToFunctions = new HashMap<>();
Function<Book, String> myFunction = x -> new String(x.getTitle());
mapToFunctions.put("firstfunction", myFunction);
for (Function<Book, String> f : mapToFunctions.values()) {
System.out.println(f.apply(new Book("my title")));
}
}
UPDATE:
Using Set<Function<Book, String>>
it would be something like:
package com.victor.main;
import java.util.HashSet;
import java.util.Set;
import java.util.function.Function;
public class FunctionalTest {
public static void testFunction() {
Set<Function<Book, String>> mapToFunctions = new HashSet<>();
Function<Book, String> myFunction = x -> new String(x.getTitle());
mapToFunctions.add(myFunction);
for (Function<Book, String> f : mapToFunctions) {
System.out.println(f.apply(new Book("my title")));
}
}
public static void main(String[] args) {
testFunction();
}
}
How can I create an array of functions?
It's definitely possible, just initialize the array as:
var pending = Array<(Void -> Void)>()
or even a fancier
var pending = Array<()->()>()
or
var pending: [(Void->Void)] = []
or
var pending: [(()->())] = []
or
var penguins: [<(") <(")] = [] // kidding
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