Formatting Numbers in Swift 3

Swift NumberFormatter formatting all values to 3 decimal places?

Link: https://stackoverflow.com/a/27571946/6655075 .

This solved my problem. As I had 3 values displaying, each from a different array, I would end up formatting all 3 whereas I only wanted to format 1 array.

   extension Double {
        static let twoFractionDigits: NumberFormatter = {
            let formatter = NumberFormatter()
            formatter.numberStyle = .decimal
            formatter.minimumFractionDigits = 2
            formatter.maximumFractionDigits = 2
            return formatter
        }()
        var formatted: String {
            return Double.twoFractionDigits.string(for: self) ?? ""
        }
    }

I removed

var formattedPrice = numberFormatter.string(from: NSNumber(value:coinPriceDouble!))

And simply used

self.coinPriceLbl.text = "\(coinTitleText!): \(Cryptocoin.instance.fiatSymbol)\(coinPriceDouble!.formatted)"

Edit: As Dávid Pásztor mentioned, I only want to add the comma separator to the values which need it while still maintaining the precision of each value down to the last decimal value.

Precision String Format Specifier In Swift

My best solution so far, following from David's response:

import Foundation

extension Int {
    func format(f: String) -> String {
        return String(format: "%\(f)d", self)
    }
}

extension Double {
    func format(f: String) -> String {
        return String(format: "%\(f)f", self)
    }
}

let someInt = 4, someIntFormat = "03"
println("The integer number \(someInt) formatted with \"\(someIntFormat)\" looks like \(someInt.format(someIntFormat))")
// The integer number 4 formatted with "03" looks like 004

let someDouble = 3.14159265359, someDoubleFormat = ".3"
println("The floating point number \(someDouble) formatted with \"\(someDoubleFormat)\" looks like \(someDouble.format(someDoubleFormat))")
// The floating point number 3.14159265359 formatted with ".3" looks like 3.142

I think this is the most Swift-like solution, tying the formatting operations directly to the data type. It may well be that there is a built-in library of formatting operations somewhere, or maybe it will be released soon. Keep in mind that the language is still in beta.

Swift number formatting

You can construct a string with a c-like formatting using this constructor:

String(format: String, arguments:[CVarArgType])

Sample usage:

var x = 10

println(String(format: "%04d", arguments: [x])) // This will print "0010"

If you're going to use it a lot, and want a more compact form, you can implement an extension like this:

extension String {
    func format(arguments: [CVarArgType]) -> String {
        return String(format: self, arguments: arguments)
    }
}

allowing to simplify its usage as in this example:

"%d apples cost $%03.2f".format([4, 4 * 0.33])

How to format a Double into Currency - Swift 3

You can use this string initializer if you want to force the currency to $:

String(format: "Tip Amount: $%.02f", tipAmount)

If you want it to be fully dependent on the locale settings of the device, you should use a NumberFormatter. This will take into account the number of decimal places for the currency as well as positioning the currency symbol correctly. E.g. the double value 2.4 will return "2,40 €" for the es_ES locale and "¥ 2" for the jp_JP locale.

let formatter = NumberFormatter()
formatter.locale = Locale.current // Change this to another locale if you want to force a specific locale, otherwise this is redundant as the current locale is the default already
formatter.numberStyle = .currency
if let formattedTipAmount = formatter.string(from: tipAmount as NSNumber) {
    tipAmountLabel.text = "Tip Amount: \(formattedTipAmount)"
}

Large decimal number formatting using NumberFormatter in Swift

You could create a Decimal explicitly to work around the mentioned bug

let formatter = NumberFormatter()
formatter.numberStyle = .decimal
if let decimalNumber = Decimal(string: "123456789123456789123"), let str = formatter.string(from:decimalNumber as NSNumber) {
    print(decimalNumber)
    print(str)
}