Format string with trailing zeros removed for x decimal places in Swift
You have to use NumberFormatter:
let formatter = NumberFormatter()
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = 2
print(formatter.string(from: 1.0000)!) // 1
print(formatter.string(from: 1.2345)!) // 1.23
This example will print 1 for the first case and 1.23 for the second; the number of minimum and maximum decimal places can be adjusted as you need.
I Hope that helps you!
Swift - Remove Trailing Zeros From Double
In Swift 4 you can do it like that:
extension Double {
func removeZerosFromEnd() -> String {
let formatter = NumberFormatter()
let number = NSNumber(value: self)
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = 16 //maximum digits in Double after dot (maximum precision)
return String(formatter.string(from: number) ?? "")
}
}
example of use: print (Double("128834.567891000").removeZerosFromEnd())
result: 128834.567891
You can also count how many decimal digits has your string:
import Foundation
extension Double {
func removeZerosFromEnd() -> String {
let formatter = NumberFormatter()
let number = NSNumber(value: self)
formatter.minimumFractionDigits = 0
formatter.maximumFractionDigits = (self.components(separatedBy: ".").last)!.count
return String(formatter.string(from: number) ?? "")
}
}
Swift - How to remove a decimal from a float if the decimal is equal to 0?
Swift 3/4:
var distanceFloat1: Float = 5.0
var distanceFloat2: Float = 5.540
var distanceFloat3: Float = 5.03
extension Float {
var clean: String {
return self.truncatingRemainder(dividingBy: 1) == 0 ? String(format: "%.0f", self) : String(self)
}
}
print("Value \(distanceFloat1.clean)") // 5
print("Value \(distanceFloat2.clean)") // 5.54
print("Value \(distanceFloat3.clean)") // 5.03
Swift 2 (Original answer)
let distanceFloat: Float = (currentUser.distance! as NSString).floatValue
distanceLabel.text = String(format: distanceFloat == floor(distanceFloat) ? “%.0f" : "%.1f", distanceFloat) + "Km"
Or as an extension:
extension Float {
var clean: String {
return self % 1 == 0 ? String(format: "%.0f", self) : String(self)
}
}
Using NSNumberFormatter to generate number with trailing zeros after decimal
As mentioned by Martin R, you can set the minimumFractionDigits
and maximumFractionDigits
to the same number which will enforce that many fraction digits always be displayed. To know how many to display you need to take a substring after the decimal to the end and count its elements. To know whether or not all of the fraction digits are 0's, I created a helper method that converts that substring to a number and if it equals 0 then you know they were all 0's.
Unfortunately you need to convert the string to a localized number using a couple different NSNumberFormatter
s based on the original string number. So if it does contain a decimal and everything after it is a 0 then you need to create a different formatter, convert the string to a number, then convert that number to a string in order to display it respecting the user's locale. Otherwise you can just use your original number formatter.
Formatting decimal places with unknown number
A Float
uses a binary (IEEE 754) representation and cannot represent
all decimal fractions precisely. For example,
let x : Float = 123.456
stores in x
the bytes 42f6e979
, which is approximately 123.45600128173828
. So does x
have 3 or 14 fractional digits?
You can use NSNumberFormatter
if you specify a maximum number
of decimal digits that should be presented:
let fmt = NSNumberFormatter()
fmt.locale = NSLocale(localeIdentifier: "en_US_POSIX")
fmt.maximumFractionDigits = 3
fmt.minimumFractionDigits = 0
println(fmt.stringFromNumber(123)!) // 123
println(fmt.stringFromNumber(123.4)!) // 123.4
println(fmt.stringFromNumber(123.45)!) // 123.45
println(fmt.stringFromNumber(123.456)!) // 123.456
println(fmt.stringFromNumber(123.4567)!) // 123.457
Swift 3/4 update:
let fmt = NumberFormatter()
fmt.locale = Locale(identifier: "en_US_POSIX")
fmt.maximumFractionDigits = 3
fmt.minimumFractionDigits = 0
print(fmt.string(for: 123.456)!) // 123.456
Dynamic trim double
This code will work for removing trailing zeros
let distanceFloat1: Float = 1.10
let distanceFloat2: Float = 0.10101010101
print("Value \(distanceFloat1.clean)")
print("Value \(distanceFloat2.clean)")
extension Float {
var clean: String {
return self.truncatingRemainder(dividingBy: 1) == 0 ? String(format: "%.0f", self) : String(self)
}
}
Output
Value 1.1
Value 1.101010
if you want to remove trailing zeros, also want to remove decimals after x place use
Swift - Remove Trailing Zeros From Double
Leading zeros for Int in Swift
Assuming you want a field length of 2 with leading zeros you'd do this:
import Foundation
for myInt in 1 ... 3 {
print(String(format: "%02d", myInt))
}
output:
01
02
03
This requires import Foundation
so technically it is not a part of the Swift language but a capability provided by the Foundation
framework. Note that both import UIKit
and import Cocoa
include Foundation
so it isn't necessary to import it again if you've already imported Cocoa
or UIKit
.
The format string can specify the format of multiple items. For instance, if you are trying to format 3
hours, 15
minutes and 7
seconds into 03:15:07
you could do it like this:
let hours = 3
let minutes = 15
let seconds = 7
print(String(format: "%02d:%02d:%02d", hours, minutes, seconds))
output:
03:15:07
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