Are multiple conditions allowed in a 'for' loop?
The condition
i < p, j < q
is allowed but probably isn't what was intended as it discards the result of the first expression and returns the result of j < q
only. The comma operator evaluates the expression on the left of the comma, discards it then evaluates the expression on the right and returns it.
If you want to test for multiple conditions use the logical AND operator &&
instead
i < p && j < q
multiple conditions Under the 'for' loop
for(int i=0;i>1&&i<4; i++ ) {
^------^ expression
For loops execute until the expression is false, and then stop executing. This expression is immediately false (because 0>1
is false), so it immediately stops executing. It doesn't "wait and see" if the expression becomes true again.
If you only want the loop to execute for i>1&&i<4
:
for(int i = 2; i<4; i++ ) {
Javascript for loop with multiple conditions not working
The second for loop stops the moment its condition evaluates to false. It's not like it skips a false value.
Since the first value in the array in false
, the for loop doesn't run its body once.
Multiple conditions in for-loop
Your break
statement indentation is not correct. The code is always breaking the loop at the first break
.
The code should be like this:
import pandas as pd
z={'speed':[2.2, 2.74, 5.1, 9.1, 0.5]}
data=pd.DataFrame(data=z)
found = 0
for k in range(len(data['speed']) - 1, 0, -1):
if (data['speed'][k]<5 and data['speed'][k-1]<5):
print(k)
found = 1
break
if found == 0:
for k in range(len(data['speed']) - 1, -1, -1):
if data['speed'][k]<5:
print(k)
break
Basic multiple conditions for loop not working
The second condition is evaluated. It is because it is evaluated the loop does not iterate.
The initial value of i
is equal to 1. So the sub-expression i%2 == 0
evaluates to false.
You could use an if statement within the loop like
for (int i = 1; i<=20; i++) {
if ( i % 2 == 0 ) printf("%d\n", i);
}
If you want to place the expression i % 2 == 0
in the condition of the loop then the loop can look for example the following way as it is shown in the demonstrative program
#include <stdio.h>
int main(void)
{
for ( int i = 1; ( i % 2 == 0 ? i : ++i ) <= 20; i++) {
printf("%d\n", i);
}
return 0;
}
The program output is
2
4
6
8
10
12
14
16
18
20
Multiple conditions in a C 'for' loop
The comma operator evaluates all its operands and yields the value of the last one. So basically whichever condition you write first, it will be disregarded, and the second one will be significant only.
for (i = 0; j >= 0, i <= 5; i++)
is thus equivalent with
for (i = 0; i <= 5; i++)
which may or may not be what the author of the code intended, depending on his intents - I hope this is not production code, because if the programmer having written this wanted to express an AND relation between the conditions, then this is incorrect and the &&
operator should have been used instead.
For-In Loops multiple conditions
It would be just as you're saying if you described it out loud:
for i in 0 ..< min(5, products.count) { ... }
That said, I suspect you really mean:
for product in products.prefix(5) { ... }
which is less error-prone than anything that requires subscripting.
It's possible you actually need an integer index (though this is rare), in which case you mean:
for (index, product) in products.enumerate().prefix(5) { ... }
Or you could even get a real index if you wanted with:
for (index, product) in zip(products.indices, products).prefix(5) { ... }
Giving multiple conditions in for loop in Java
You can also use "or" operator,
for( int i = 0 ; i < 100 || someOtherCondition() ; i++ ) {
...
}
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