Sql - How to Find The Highest Number in a Column

SQL - How to find the highest number in a column?

You can do

SELECT MAX(ID) FROM Customers;

Find highest value in a column in SQL Server

A correlated subquery usually has good performance:

select t.*
from t
where t.version = (select MAX(t2.version) from t t2 where t2.projectname = t.projectname);

In particular, you want an index on (projectname, version) for optimal performance.

How can I SELECT rows with MAX(Column value), PARTITION by another column in MYSQL?

You are so close! All you need to do is select BOTH the home and its max date time, then join back to the topten table on BOTH fields:

SELECT tt.*
FROM topten tt
INNER JOIN
    (SELECT home, MAX(datetime) AS MaxDateTime
    FROM topten
    GROUP BY home) groupedtt 
ON tt.home = groupedtt.home 
AND tt.datetime = groupedtt.MaxDateTime

Query to find nᵗʰ max value of a column

You could sort the column into descending format and then just obtain the value from the nth row.

EDIT::

Updated as per comment request. WARNING completely untested!

SELECT DOB FROM (SELECT DOB FROM USERS ORDER BY DOB DESC) WHERE ROWID = 6

Something like the above should work for Oracle ... you might have to get the syntax right first!

What is the simplest SQL Query to find the second largest value?

SELECT MAX( col )
  FROM table
 WHERE col < ( SELECT MAX( col )
                 FROM table )

SQL select only rows with max value on a column

At first glance...

All you need is a GROUP BY clause with the MAX aggregate function:

SELECT id, MAX(rev)
FROM YourTable
GROUP BY id

It's never that simple, is it?

I just noticed you need the content column as well.

This is a very common question in SQL: find the whole data for the row with some max value in a column per some group identifier. I heard that a lot during my career. Actually, it was one the questions I answered in my current job's technical interview.

It is, actually, so common that Stack Overflow community has created a single tag just to deal with questions like that: greatest-n-per-group.

Basically, you have two approaches to solve that problem:

Joining with simple group-identifier, max-value-in-group Sub-query

In this approach, you first find the group-identifier, max-value-in-group (already solved above) in a sub-query. Then you join your table to the sub-query with equality on both group-identifier and max-value-in-group:

SELECT a.id, a.rev, a.contents
FROM YourTable a
INNER JOIN (
    SELECT id, MAX(rev) rev
    FROM YourTable
    GROUP BY id
) b ON a.id = b.id AND a.rev = b.rev

Left Joining with self, tweaking join conditions and filters

In this approach, you left join the table with itself. Equality goes in the group-identifier. Then, 2 smart moves:

1. The second join condition is having left side value less than right value
2. When you do step 1, the row(s) that actually have the max value will have NULL in the right side (it's a LEFT JOIN, remember?). Then, we filter the joined result, showing only the rows where the right side is NULL.

So you end up with:

SELECT a.*
FROM YourTable a
LEFT OUTER JOIN YourTable b
    ON a.id = b.id AND a.rev < b.rev
WHERE b.id IS NULL;

Conclusion

Both approaches bring the exact same result.

If you have two rows with max-value-in-group for group-identifier, both rows will be in the result in both approaches.

Both approaches are SQL ANSI compatible, thus, will work with your favorite RDBMS, regardless of its "flavor".

Both approaches are also performance friendly, however your mileage may vary (RDBMS, DB Structure, Indexes, etc.). So when you pick one approach over the other, benchmark. And make sure you pick the one which make most of sense to you.

SQL : get Min and Max value in one column

I Finally figured out a simple code for what i wanted.

select emp_name, salary
from employees
where salary = (select max(salary) from employees)
union all
select emp_name, salary
from employees
where salary = (select min(salary) from employees);

I didn't know about Union.
Thank you all for your contribution

How to Identify the column with the max value per row

You can do this with case logic. Assuming none of the values are NULL:

select t.*,
       (case greatest(x, y)
            when x then 'x'
            when y then 'y'
        end) 
from t;

select max value from a string column in SQL

Since you are maxing a string it is sorting alphabetically where C is larger than AAA and 9 is larger than 10. Remove the letters and cast it as an int then get the max. Given that it will always be Ord-### we can remove the Ord- and cast the remainder as an INT.

SELECT
    MAX(CAST(SUBSTRING(OrderNo,5,LEN(OrderNo)-4) AS INT))
FROM OrderSummary
WHERE OrderNo LIKE 'Ord-%'

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