SQL - counting rows with specific value
With MySQL, you can use SUM(condition)
:
SELECT id, SUM(value=0) AS n0, SUM(value=1) AS n1, COUNT(*) AS total
FROM mytable
GROUP BY id
See it on sqlfiddle.
SQL count rows where column value contains string
Use a case
expression:
select sum(case when column_name like '%substring%' then 1 else 0 end)
from table_name ;
Or, if that is the only value you want, use filtering and count(*)
:
select count(*)
from table_name
where column_name like '%substring%';
The first is more suitable when you have additional columns in the query.
I should note that the SQL standard has another method of accomplishing this, using filter
:
select count(*) filter (where column_name like '%substring%')
from table_name ;
However, most databases do not support this syntax.
T-SQL Count rows with specific values (Multiple in one query)
SELECT IGrp,
COUNT(CASE WHEN Value1 > 1 THEN 1 ELSE NULL END) AS V1High,
COUNT(CASE WHEN Value2 > 1 THEN 1 ELSE NULL END) AS V2High
FROM Tbl
GROUP BY IGrp
Count records in table and show line number of specific value
Please find the query with the window function:
DECLARE @intPos AS INT = 0;
;WITH RowCountCte AS (
SELECT ID, ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS intPos
FROM tblData
)
SELECT @intPos = intPos FROM RowCountCte WHERE ID = 101;
SELECT COUNT(ID) AS cntRec, @intPos AS intPos
FROM tblData;
Demo on db<>fiddle
How to count rows in a table, where a specific column value is in a list of specified values?
I would suggest using the IN
operator, to write it in a more concise manner:
Count (Calculate) =
CALCULATE (
COUNTROWS ( dCustomers ) ,
dCustomers[customerType] IN {"FR", "DE", "GG"}
)
You can also use COUNTROWS
directly on the filtered table, this looks to be marginally faster from a bit of testing on a random dataset, but please do benchmarking on a case by case basis:
Count (Filter) =
COUNTROWS (
FILTER (
dCustomers ,
dCustomers[customerType] IN {"FR", "DE", "GG"}
)
)
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