SQL Comma-Separated Row with Group by Clause

SQL Server : GROUP BY clause to get comma-separated values

try this:

SELECT ReportId, Email = 
STUFF((SELECT ', ' + Email
FROM your_table b
WHERE b.ReportId = a.ReportId
FOR XML PATH('')), 1, 2, '')
FROM your_table a
GROUP BY ReportId


SQL fiddle demo

SQL comma-separated row with Group By clause

You want to use FOR XML PATH construct:

SELECT ACCOUNT, 
unit,
SUM(state_fee),
Stuff((SELECT ', ' + code
FROM tblmta t2
WHERE t2.ACCOUNT = t1.ACCOUNT
AND t2.unit = t1.unit
AND t2.id = '123'
FOR XML PATH('')), 1, 2, '') [Codes]
FROM tblmta t1
WHERE t1.id = '123'
GROUP BY ACCOUNT,
unit

See other examples here:

  • SQL same unit between two tables needs order numbers in 1 cell
  • SQL Query to get aggregated result in comma seperators along with group by column in SQL Server

Group By clause with comma-separated values

You were almost there, all you need is an INNER JOIN onto the Chef table inside your STUFF statement and then you simply swap out ChefId with Name.

SELECT Dish, ChefId = 
STUFF((SELECT ', ' + c1.Name
FROM Specialty s1
INNER JOIN Chef c1
ON s1.ChefId = c1.Id
WHERE s1.Dish = s2.Dish
FOR XML PATH('')), 1, 2, '')
FROM Specialty s2
GROUP BY Dish

I have a working SQL Fiddle example here: http://www.sqlfiddle.com/#!6/9b7d5/6

Group by with comma-separated values and excluding the value from the previous column value

This can be done using For XML Path("), TYPE as follows:

SELECT S.id, S.Fname, S.Lname, S.Lid, 
STUFF((SELECT Concat(',',Lid) FROM StudentLecturer WHERE id=S.id And Lid<>S.Lid
FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)'),1,1,'') AS [Concat Values]
FROM StudentLecturer As S

with using String_Agg function for SQL Server 2017 (14.x) and later versions.

SELECT S.id, S.Fname, S.Lname, S.Lid, 
STRING_AGG(S_1.Lid, ',') WITHIN GROUP (ORDER BY S_1.Lid) AS [Concat Values]
FROM StudentLecturer AS S LEFT JOIN StudentLecturer AS S_1 ON (S.id=S_1.id AND
S.Lid<>S_1.Lid)
GROUP BY S.id, S.Fname, S.Lname, S.Lid
ORDER BY S.Fname, S.Lname, S.Lid

How to view a column values in comma separated string with group by clause using SQL query?

You can use the STUFF() as shown below. Just replace cte with your original query. Another way is to create a temp table with your current result and replace that cte with the temp table newly created.

SELECT DoNum
, CardCode
, CardName
, SipCode
, SlpName
, STUFF((SELECT DISTINCT ',' + CONVERT(VARCHAR,U_Product_Type)
FROM [cte] t1
WHERE (DoNum = cte.DoNum
and CardCode = t1.CardCode
and CardName = t1.CardName
and SipCode = t1.SipCode
and SlpName = t1.SlpName)
FOR XML PATH ('')), 1, 2, '') AS U_Product_Type
,sum(LineTotal) as LineTotal
,sum(dwpnt) as dwpnt
FROM cte
group by DoNum
, CardCode
, CardName
, SipCode
, SlpName

Live Demo

SQL Server : query for comma separated with group by

For older version of SQL Server i would use FOR XML clause with STUFF() :

SELECT c.CountryId, c.CountryName,
STUFF( (SELECT DISTINCT ' ,'+ct.CityName
FROM City ct
WHERE ct.CountryId = c.CountryId
FOR XML PATH ('')
), 1, 1, ''
) AS CitiesNames
FROM Country c;

You can use STRING_AGG() for newer version (SQL Server 2017). However, DISTINCT is redundant inside STUFF() if you don't have a duplicate cities. So, you can remove it.

For better performance you need index Country (CountryId) include CountryName, CityName.

SQL Server - join rows into comma separated list

You are missing the condition inside the sub query.

SELECT t2.Id, STUFF((SELECT ',' + CAST(VALUE AS varchar) FROM @MyTable t1  where t1.Id =t2.ID FOR XML PATH('')), 1 ,1, '') AS ValueList
FROM @MyTable t2
GROUP BY t2.Id

Demo

How to select row/s from an other table using a comma-separated value from the first table?


SELECT t1.subject, GROUP_CONCAT(t2.subject)
FROM faculty t1
JOIN subjects t2 ON FIND_IN_SET(t2.code, t1.subject)
GROUP BY t1.subject;

https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=3e40ab353ff1e0a1cde678225fa63ed2



Related Topics



Leave a reply



Submit