Oracle SQL Pivot Table

Create Pivot view in SQL from a SQL table

A stored function(or procedure) might be created in order to create a SQL for Dynamic Pivoting, and the result set is loaded into a variable of type SYS_REFCURSOR :

CREATE OR REPLACE FUNCTION Get_Categories_RS RETURN SYS_REFCURSOR IS
  v_recordset SYS_REFCURSOR;
  v_sql       VARCHAR2(32767);
  v_cols_1    VARCHAR2(32767);
  v_cols_2    VARCHAR2(32767);  
BEGIN
  SELECT LISTAGG( ''''||"level"||''' AS "'||"level"||'"' , ',' )
          WITHIN GROUP ( ORDER BY "level" DESC )
    INTO v_cols_1
    FROM (
          SELECT DISTINCT "level"
            FROM temp
          );

  SELECT LISTAGG( 'MAX(CASE WHEN category = '''||category||''' THEN "'||"level"||'" END) AS "'||"level"||'_'||category||'"' , ',' )
          WITHIN GROUP ( ORDER BY category, "level" DESC )
    INTO v_cols_2
    FROM (
          SELECT DISTINCT "level", category
            FROM temp
          );

  v_sql :=
  'SELECT "set", '|| v_cols_2 ||'
     FROM
     (
      SELECT *
        FROM temp
       PIVOT
       (
        MAX(value) FOR "level" IN ( '|| v_cols_1 ||' )
       )
      )
      GROUP BY "set"
      ORDER BY "set"'; 

  OPEN v_recordset FOR v_sql;
  RETURN v_recordset;
END;

in which I used two levels of pivoting : the first is within the inner query involving PIVOT Clause, and the second is in the outer query having the conditional aggregation logic. Notice that the order of levels should be in the descending order( Z, Y, X ) within the expected result as conforming to the description.

And then invoke

VAR rc REFCURSOR
EXEC :rc := Get_Categories_RS;
PRINT rc

from SQL Developer's Command Line in order to get the result set

Btw, avoid using reserved keywords such as set and level as in your case. I needed to quote them in order to be able to use.

Pivot in Oracle based on multiple columns

You can definitely use multiple columns within a PIVOT clause, here is an example using your table setup:

SELECT *
FROM demo
PIVOT (MAX(VALUE) FOR (identifier_1, identifier_2) IN ((3000, 23) AS A3000_23, (3000, 24) AS A3000_24,
                                                        (3001, 25) AS A3001_25, (3001, 26) AS A3001_26));

N.B.: Excuse the "A" in the column names, you need to start the identifier with a character, not a number.

Here is a DBFiddle showing the results (LINK)

Obviously you can see how this would quickly grow out-of-hand if you need to list large amounts of PIVOT columns.

Dynamic Pivot in Oracle's SQL

You can't put a non constant string in the IN clause of the pivot clause.

You can use Pivot XML for that.

From documentation:

subquery A subquery is used only in conjunction with the XML keyword.
When you specify a subquery, all values found by the subquery are used
for pivoting

It should look like this:

select xmlserialize(content t.B_XML) from t_aa
pivot xml(
sum(A) for B in(any)
) t;

You can also have a subquery instead of the ANY keyword:

select xmlserialize(content t.B_XML) from t_aa
pivot xml(
sum(A) for B in (select cl from t_bb)
) t;

Here is a sqlfiddle demo

Most efficient (fast) way to create a pivot table in Oracle SQL

Two most obvious options are ... well, pivoting:

SQL> select *
  2  from foo
  3  pivot (
  4    count(st)
  5    for st in ('open' as open, 'wip' as wip, 'closed' as closed)
  6  )
  7  order by ts;

TS               OPEN        WIP     CLOSED
---------- ---------- ---------- ----------
21.08.2022          0          1          2
22.08.2022          0          2          1
23.08.2022          2          1          0

SQL>

or conditional aggregation:

SQL> select ts,
  2    sum(case when st = 'open'   then 1 else 0 end) as open,
  3    sum(case when st = 'wip'    then 1 else 0 end) as wip,
  4    sum(case when st = 'closed' then 1 else 0 end) as closed
  5  from foo
  6  group by ts
  7  order by ts;

TS               OPEN        WIP     CLOSED
---------- ---------- ---------- ----------
21.08.2022          0          1          2
22.08.2022          0          2          1
23.08.2022          2          1          0

SQL>

Is one better or worse than another (or something else), I can't tell - you'd have to do some test on real data.

Use pivot for dynamically changing column headers using sql in oracle

What you can do

SELECT * 
  FROM data  
 PIVOT  
 (
  MAX(value) FOR label IN ('A' AS "A", 'B' AS "B",'C' AS "C",'D' AS "D")
 )
 WHERE ID = 120 AND app_id = 1

as a static pivot statement might be converted to a function which contains two respective parameters

CREATE OR REPLACE FUNCTION Get_Pivoted_Labels( i_id data.id%type, i_app_id data.app_id%type ) 
RETURN SYS_REFCURSOR IS
  v_recordset SYS_REFCURSOR;
  v_sql       VARCHAR2(32767); 
  v_cols      VARCHAR2(32767);  
BEGIN
  SELECT LISTAGG( ''''||label||''' AS "'||label||'"' , ',' )
          WITHIN GROUP ( ORDER BY label ) 
    INTO v_cols
    FROM ( SELECT DISTINCT label 
             FROM data
            WHERE ID = i_id AND app_id = i_app_id );

  v_sql :=
      'SELECT * 
         FROM data
        PIVOT 
        (
          MAX(value) FOR label IN ( '|| v_cols ||' )
        )
       WHERE ID = :id AND app_id = :aid'; 

  OPEN v_recordset FOR v_sql USING i_id, i_app_id;
  RETURN v_recordset;
END;
/

in which an auxiliary query, in which the label columns are distinctly selected, is used to determine the string(v_cols for 'A' AS "A", 'B' AS "B",'C' AS "C",'D' AS "D") to be concatenated to the main SQL string in order to be used within the cursor which returns a value of type SYS_REFCURSOR.

and is invoked by

VAR rc REFCURSOR
VAR v_id NUMBER
VAR v_app_id NUMBER
EXEC :rc := Get_Pivoted_Labels(:v_id,:v_app_id);
PRINT rc

from SQL developer's console.

Demonstration with generated SQL statements

If order of columns in the SELECT list matters, then use the code below in order to create the function

CREATE OR REPLACE FUNCTION Get_Pivoted_Labels( i_id data.id%type, i_app_id data.app_id%type ) 
RETURN SYS_REFCURSOR IS
  v_recordset SYS_REFCURSOR;
  v_sql       VARCHAR2(32767); 
  v_cols_1    VARCHAR2(32767);    
  v_cols_2    VARCHAR2(32767);   
BEGIN
  SELECT LISTAGG( ''''||label||''' AS "'||label||'"' , ',' )
          WITHIN GROUP ( ORDER BY label ),
         LISTAGG( label , ',' )
          WITHIN GROUP ( ORDER BY label )  
    INTO v_cols_1, v_cols_2
    FROM ( SELECT DISTINCT label, value 
             FROM data
            WHERE ID = i_id AND app_id = i_app_id );

  v_sql :=
      'SELECT ID, '|| v_cols_2 ||', app_id
         FROM data
        PIVOT 
        (
          MAX(value) FOR label IN ( '|| v_cols_1 ||' )
        )
       WHERE ID = :id AND app_id = :aid'; 

  OPEN v_recordset FOR v_sql USING i_id, i_app_id;
  RETURN v_recordset;
END;
/

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