How to Find Top Three Highest Salary in Emp Table in Oracle

How to find top three highest salary in emp table in oracle?

SELECT  *FROM 
    (
    SELECT *FROM emp 
    ORDER BY Salary desc
    )
WHERE rownum <= 3
ORDER BY Salary ;

Nth max salary in Oracle

try this

select *
  from
  (
    select
        sal
          ,dense_rank() over (order by sal desc) ranking
    from   table
  )
  where ranking = 4 -- Replace 4 with any value of N

How to select the top 3 salaries of the department?

If you added a column Count employees who earn more your table would look like this

+----+-------+--------+--------------+-------------------------------+
| Id | Name  | Sa1ary | DepartmentId | Count employees who earn more |
+----+-------+--------+--------------+-------------------------------+
|  1 | Joe   |  70000 |            1 |    2                          |
|  2 | Henry |  80000 |            2 |    0                          |
|  3 | Sam   |  60000 |            2 |    1                          | 
|  4 | Max   |  90000 |            1 |    0                          |
|  5 | Janet |  69000 |            1 |    3                          |
|  6 | Randy |  85000 |            1 |    1                          |
+----+-------+--------+--------------+-------------------------------+

Then to find the top 3 per dept. your WHERE would be

WHERE `Count employees who earn more` < 3

If you had =3 it would return the only employees that was the 4th highest

Since you don't have that column, that's what this SQL does

(SELECT COUNT(DISTINCT(Salary)) FROM Employee 
       WHERE DepartmentId = E.DepartmentId AND Salary > E.Salary)

If you wanted to produce the table described above you could do the following

SELECT 
      D.Name AS Department, 
      E.Name AS Employee, 
      E.Salary AS Salary,
      Count(E2.Salary) as Count_employees_who_earn_more
FROM Employee E 
INNER JOIN Department D 
ON E.DepartmentId = D.Id 
LEFT JOIN Employee E2 ON 
    e2.DepartmentId = E.DepartmentId
    AND E2.Salary > E.Salary
GROUP BY  D.Name , 
      E.Name , 
      E.Salary 

Demo

ORACLE sql query for getting top 3 salaries rownum greater than

a_horse_with_no_name's answer is a good one,

but just to make you understand why you're 1st query works and your 2nd doesn't:

When you use the subquery, Oracle doesn't magically use the rownum of the subquery, it just gets the data ordered so it gives the rownum accordingly, the first row that matches criteria still gets rownum 1 and so on. This is why your 2nd query still returns no rows.

If you want to limit the starting row, you need to keep the subquery's rownum, ie:

SELECT *
FROM (SELECT * , rownum rn
  FROM (SELECT salary, first_name
          FROM employees
      ORDER BY salary ) )sq
WHERE sq.rn >= 3;

But as a_horse_with_no_name said there are better options ...

EDIT: To make things clearer, look at this query:

with t as (
select 'a' aa, 4 sal from dual
union all
select 'b' aa, 1 sal from dual
union all
select 'c' aa, 5 sal from dual
union all
select 'd' aa, 3 sal from dual
union all
select 'e' aa, 2 sal from dual
order by aa
)
select sub.*, rownum main_rn 
  from (select t.*, rownum sub_rn from t order by sal) sub 
 where rownum < 4

note the difference between the sub rownum and the main rownum, see which one is used for criteria

How to find third or nᵗʰ maximum salary from salary table?

Use ROW_NUMBER(if you want a single) or DENSE_RANK(for all related rows):

WITH CTE AS
(
    SELECT EmpID, EmpName, EmpSalary,
           RN = ROW_NUMBER() OVER (ORDER BY EmpSalary DESC)
    FROM dbo.Salary
)
SELECT EmpID, EmpName, EmpSalary
FROM CTE
WHERE RN = @NthRow

---

Related Topics