How can you find the number of occurrences of a particular character in a string using sql?
Here you go:
declare @string varchar(100)
select @string = 'sfdasadhfasjfdlsajflsadsadsdadsa'
SELECT LEN(@string) - LEN(REPLACE(@string, 'd', '')) AS D_Count
How to count instances of character in SQL Column
In SQL Server:
SELECT LEN(REPLACE(myColumn, 'N', ''))
FROM ...
How do you count the number of occurrences of a certain substring in a SQL varchar?
The first way that comes to mind is to do it indirectly by replacing the comma with an empty string and comparing the lengths
Declare @string varchar(1000)
Set @string = 'a,b,c,d'
select len(@string) - len(replace(@string, ',', ''))
Number of times a particular character appears in a string
There's no direct function for this, but you can do it with a replace:
declare @myvar varchar(20)
set @myvar = 'Hello World'
select len(@myvar) - len(replace(@myvar,'o',''))
Basically this tells you how many chars were removed, and therefore how many instances of it there were.
Extra:
The above can be extended to count the occurences of a multi-char string by dividing by the length of the string being searched for. For example:
declare @myvar varchar(max), @tocount varchar(20)
set @myvar = 'Hello World, Hello World'
set @tocount = 'lo'
select (len(@myvar) - len(replace(@myvar,@tocount,''))) / LEN(@tocount)
Count the number of occurrences of a string in a VARCHAR field?
This should do the trick:
SELECT
title,
description,
ROUND (
(
LENGTH(description)
- LENGTH( REPLACE ( description, "value", "") )
) / LENGTH("value")
) AS count
FROM <table>
Count occurrences of character in a string and Group By with SQL
Try this, even I still don't know what you exactly want to do till now, but try it.
SELECT
book,
chapter,
group_concat(text) as text,
ROUND (
(
LENGTH(group_concat(text))
- LENGTH( REPLACE ( group_concat(text), "hello", "") )
) / LENGTH("hello")
) AS `count`
FROM my_table
GROUP BY chapter, book
How to count the number of occurrences of a character in an Oracle varchar value?
Here you go:
select length('123-345-566') - length(replace('123-345-566','-',null))
from dual;
Technically, if the string you want to check contains only the character you want to count, the above query will return NULL; the following query will give the correct answer in all cases:
select coalesce(length('123-345-566') - length(replace('123-345-566','-',null)), length('123-345-566'), 0)
from dual;
The final 0 in coalesce
catches the case where you're counting in an empty string (i.e. NULL, because length(NULL) = NULL in ORACLE).
Counting the number of occurrences of a substring within a string in PostgreSQL
A common solution is based on this logic: replace the search string with an empty string and divide the difference between old and new length by the length of the search string
(CHAR_LENGTH(name) - CHAR_LENGTH(REPLACE(name, 'substring', '')))
/ CHAR_LENGTH('substring')
Hence:
UPDATE test."user"
SET result =
(CHAR_LENGTH(name) - CHAR_LENGTH(REPLACE(name, 'o', '')))
/ CHAR_LENGTH('o');
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