Count Without Group

SQL count without group by

change your last sql like this

select mt.user_id, mt.purchase_id 
from myview mv 
inner join mytable mt 
on mt.user_id=mv.user_id where mv.count >5;

Selecting count without Group By

You should be able to use a windowed function

SELECT  OrderID,
        ContainerType,
        COUNT(ContainerID) OVER (PARTITION BY OrderID, ContainerType) AS ContainerCOUNT,
        ContainerID
FROM    @OrderCoarntainers

COUNT without GROUP BY clause issue

Use this instead:

count(*) over() as allRecordsFound

You can mix window aggregation function in select statement whithout grouping.

How to use Count without Group By?

Join with a subquery that finds the candidates who are in at least two subjects in the 3rd semester.

SELECT t1.Roll, t1.Subject
FROM table AS t1
JOIN (
    SELECT Roll
    FROM table
    WHERE RIGHT(Subject, 1) = '3'
    GROUP BY Roll
    HAVING COUNT(*) > 1
) AS t2 ON t1.Roll = t2.Roll
WHERE t1.Subject = 'CEMG3'

COUNT(*) with and without GROUP BY, no matching rows

An aggregation query that has no group by always returns one row (if it is syntactically correct). The count in such a row would be 0.

An aggregation query with a group by returns one row per group. If there are no groups then there are no rows.

MYSQL - having count(*) without group by

Try something like the following

SELECT C2, counter from 
(SELECT C2, COUNT(*) as counter FROM test.mytable
GROUP BY C2) as aggregation
WHERE counter > 1

Without using group by, you can do something like

SELECT a.* , 
   (SELECT count(*) FROM discount_vouchers b 
    WHERE a.email = b.email AND a.test_id = b.test_id) as count
FROM discount_vouchers a

---

Related Topics