Comma Delimited SQL String Need to Separated

Comma Delimited SQL string Need to separated

It think the easiest way to do it, will be, dynamic SQL generation:

// assuming select is a SqlCommand
string[] values = "A,B,C,D,E,F".Split(',');
StringBuilder query = new StringBuilder();
query.Append("select * from tbl_test where tbl_test.code in (");
int i = 0;
foreach (string value in values) {
    string paramName = "@p" + i++;
    query.Append(paramName);
    select.Parameters.AddWithValue(paramName, value);
}
query.Append(")");
select.CommandText = query.ToString();

// and then execute the select Command

How to split a comma-separated value to columns

CREATE FUNCTION [dbo].[fn_split_string_to_column] (
    @string NVARCHAR(MAX),
    @delimiter CHAR(1)
    )
RETURNS @out_put TABLE (
    [column_id] INT IDENTITY(1, 1) NOT NULL,
    [value] NVARCHAR(MAX)
    )
AS
BEGIN
    DECLARE @value NVARCHAR(MAX),
        @pos INT = 0,
        @len INT = 0

    SET @string = CASE 
            WHEN RIGHT(@string, 1) != @delimiter
                THEN @string + @delimiter
            ELSE @string
            END

    WHILE CHARINDEX(@delimiter, @string, @pos + 1) > 0
    BEGIN
        SET @len = CHARINDEX(@delimiter, @string, @pos + 1) - @pos
        SET @value = SUBSTRING(@string, @pos, @len)

        INSERT INTO @out_put ([value])
        SELECT LTRIM(RTRIM(@value)) AS [column]

        SET @pos = CHARINDEX(@delimiter, @string, @pos + @len) + 1
    END

    RETURN
END

Turning a Comma Separated string into individual rows

You can use the wonderful recursive functions from SQL Server:

Sample table:

CREATE TABLE Testdata
(
    SomeID INT,
    OtherID INT,
    String VARCHAR(MAX)
);

INSERT Testdata SELECT 1,  9, '18,20,22';
INSERT Testdata SELECT 2,  8, '17,19';
INSERT Testdata SELECT 3,  7, '13,19,20';
INSERT Testdata SELECT 4,  6, '';
INSERT Testdata SELECT 9, 11, '1,2,3,4';

The query

WITH tmp(SomeID, OtherID, DataItem, String) AS
(
    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM Testdata
    UNION all

    SELECT
        SomeID,
        OtherID,
        LEFT(String, CHARINDEX(',', String + ',') - 1),
        STUFF(String, 1, CHARINDEX(',', String + ','), '')
    FROM tmp
    WHERE
        String > ''
)
SELECT
    SomeID,
    OtherID,
    DataItem
FROM tmp
ORDER BY SomeID;
-- OPTION (maxrecursion 0)
-- normally recursion is limited to 100. If you know you have very long
-- strings, uncomment the option

Output

 SomeID | OtherID | DataItem 
--------+---------+----------
 1      | 9       | 18       
 1      | 9       | 20       
 1      | 9       | 22       
 2      | 8       | 17       
 2      | 8       | 19       
 3      | 7       | 13       
 3      | 7       | 19       
 3      | 7       | 20       
 4      | 6       |          
 9      | 11      | 1        
 9      | 11      | 2        
 9      | 11      | 3        
 9      | 11      | 4        

SQL use in query for comma separated string

Just use a subquery:

select *
from mytable
where fruit in (select value from STRING_SPLIT(@MyStr, ','));

In older versions of SQL Server, you can use like:

select *
from mytable
where ',' + @MyStr + ',' like '%,' + fruit + ',%';

Need comma separated value in table in SQL Server 2014

You're part of the way there. The tradition method is using STUFF:

SELECT t.id, t.firstname,
       STUFF((SELECT ', ' + sq.lastname
              FROM #temp sq
              WHERE sq.id = t.id
                AND sq.firstname = t.firstname
              ORDER BY sq.lastname
              FOR XML PATH('')),1,1,'') AS lastname
FROM #temp t
GROUP BY t.id, t.firstname;

There are lots of answers on SO already on how to do this though, but you have shown effort. :)

Comma-delimited string

This is a bit convoluted method.

But it can transform the string in the format of a JSON array.

Then it'll be easier to use JSON functions on it.

The example uses a UDF fnPattern_Split that accepts a pattern to unnest the string.

The source code can be found here

declare @str varchar(max), @js varchar(max);
set @str ='Value1,Value2,"Value3,Value4,Value5",Value6';

;with cte1 as (
select *
from dbo.fnPattern_Split(@str,'"%"') ps
) 
, cte2 as (
  select ordinal as ord1, 0 as ord2, value 
  from cte1 
  where match = 1
  union all
  select c.ordinal, ps.ordinal, quotename(ps.value,'"') as value 
  from cte1 c
  cross apply fnPattern_Split(c.value,',') ps
  where c.match = 0 and ps.match = 0
) 
select @js = '['+string_agg(value, ',')
                 within group (order by ord1, ord2)+']'
from cte2;

print(@js);

select *
from OPENJSON(@js) js;

SELECT
    STUDENTNUMBER
    , STRING_AGG(INSTITUTIONNAME, ', ') AS StringAggList
    , STRING_AGG(INSTITUTIONNAME, ', ') WITHIN GROUP (ORDER BY INSTITUTIONNAME DESC) AS StringAggListDesc
FROM Education E
GROUP BY E.STUDENTNUMBER;

SELECT
    STUFF((SELECT ',' + INSTITUTIONNAME
              FROM EDUCATION EE
              WHERE  EE.STUDENTNUMBER = E.STUDENTNUMBER
              ORDER BY sortOrder
              FOR XML PATH(''), TYPE).value('text()[1]', 'nvarchar(max)')
        , 1, LEN(','), '') AS XmlPathList
FROM EDUCATION E
GROUP BY E.STUDENTNUMBER

-- Variable holding comma separated values
DECLARE @Var VARCHAR(4000);
SET @Var =  '188,189,190,191,192,193,194'

-- Test Target Table
DECLARE @Target_Table TABLE  (First_ID INT,Second_ID INT,Third_ID INT) 

-- Insert statement
INSERT INTO @Target_Table
SELECT 1, CAST(Items AS INT) , 0 
FROM  dbo.Split(@Var, ',')  

-- Test Select
SELECT * FROM  @Target_Table  

╔══════════╦═══════════╦══════════╗
║ First_ID ║ Second_ID ║ Third_ID ║
╠══════════╬═══════════╬══════════╣
║        1 ║       188 ║        0 ║
║        1 ║       189 ║        0 ║
║        1 ║       190 ║        0 ║
║        1 ║       191 ║        0 ║
║        1 ║       192 ║        0 ║
║        1 ║       193 ║        0 ║
║        1 ║       194 ║        0 ║
╚══════════╩═══════════╩══════════╝