Calculating difference between two timestamps in Oracle in milliseconds
When you subtract two variables of type TIMESTAMP
, you get an INTERVAL DAY TO SECOND
which includes a number of milliseconds and/or microseconds depending on the platform. If the database is running on Windows, systimestamp
will generally have milliseconds. If the database is running on Unix, systimestamp
will generally have microseconds.
1 select systimestamp - to_timestamp( '2012-07-23', 'yyyy-mm-dd' )
2* from dual
SQL> /
SYSTIMESTAMP-TO_TIMESTAMP('2012-07-23','YYYY-MM-DD')
---------------------------------------------------------------------------
+000000000 14:51:04.339000000
You can use the EXTRACT
function to extract the individual elements of an INTERVAL DAY TO SECOND
SQL> ed
Wrote file afiedt.buf
1 select extract( day from diff ) days,
2 extract( hour from diff ) hours,
3 extract( minute from diff ) minutes,
4 extract( second from diff ) seconds
5 from (select systimestamp - to_timestamp( '2012-07-23', 'yyyy-mm-dd' ) diff
6* from dual)
SQL> /
DAYS HOURS MINUTES SECONDS
---------- ---------- ---------- ----------
0 14 55 37.936
You can then convert each of those components into milliseconds and add them up
SQL> ed
Wrote file afiedt.buf
1 select extract( day from diff )*24*60*60*1000 +
2 extract( hour from diff )*60*60*1000 +
3 extract( minute from diff )*60*1000 +
4 round(extract( second from diff )*1000) total_milliseconds
5 from (select systimestamp - to_timestamp( '2012-07-23', 'yyyy-mm-dd' ) diff
6* from dual)
SQL> /
TOTAL_MILLISECONDS
------------------
53831842
Normally, however, it is more useful to have either the INTERVAL DAY TO SECOND
representation or to have separate columns for hours, minutes, seconds, etc. rather than computing the total number of milliseconds between two TIMESTAMP
values.
Average Timestamp oracle with milliseconds
You may use EXTRACT
to get AVG
seconds.
SELECT AVG (EXTRACT (SECOND FROM (sva.endTime - sva.startTime)))
AS avg_seconds
FROM SVATable sva;
Difference Between Timestamps in Milliseconds in Oracle
select
extract(second from systimestamp - doj) * 1000
from
test1;
get the date difference in milliseconds in oracle
SELECT ((extract(DAY FROM time2-time1)*24*60*60)+
(extract(HOUR FROM time2-time1)*60*60)+
(extract(MINUTE FROM time2-time1)*60)+
extract(SECOND FROM time2-time1)) *1000
as millisecs FROM dual;
can be done using above approach
Difference between 2 times in sec in Pl/SQL
As difference of two DATE
datatype values in Oracle represents number of days between them, you have to multiply it by 24 (as there are 24 hours in a day) and 60 (as there are 60 minutes in an hour) and 60 (as there are 60 seconds in a minute).
So:
(setting date format, just to know what is what; you don't have to do that)
SQL> alter session set nls_date_format = 'dd.mm.yyyy hh24:mi:ss';
Session altered.
I presume your value is stored as a string (according to date format you posted; though, it is wrong - minutes are MI
, not MM
) so first convert it to a DATE
datatype value, and then do the calculation:
SQL> select sysdate now,
2 (sysdate - to_date('20220614090500', 'yyyymmddhh24miss')) * 24 * 60 * 60 seconds
3 from dual;
NOW SECONDS
------------------- ----------
14.06.2022 09:09:54 294
SQL>
ORACLE sql hours between two timestamps format
Just use a subquery to extract the hours from the expression
SELECT extract( hour from x) hours FROM
(SELECT (date1 - date2)x FROM B)
Time difference between two timestamps in Apex 5.1
Subtracting two date values in Oracle results in number of DAYS. Therefore, you'd have to do some math in order to get hours (or minutes). Here's an example:
SQL> col diff_days format 90D00000
SQL> col diff_hours format 90D00000
SQL> col diff_minutes format 90D00000
SQL>
SQL> with test as (select to_date('29.12.2017 16:05', 'dd.mm.yyyy hh24:mi') d_order,
2 to_date('29.12.2017 16:39', 'dd.mm.yyyy hh24:mi') d_now
3 from dual)
4 select
5 d_now - d_order diff_days,
6 (d_now - d_order) * 24 diff_hours,
7 (d_now - d_Order) * (24 * 60) diff_minutes
8 from test;
DIFF_DAYS DIFF_HOURS DIFF_MINUTES
--------- ---------- ------------
0,02361 0,56667 34,00000
SQL>
You'd do similarly: D_NOW would be SYSDATE, while D_ORDER would be a value stored in a(n ORDERS) table.
How to find elapsed time in milliseconds by compare two timestamps in java
Get your updated timestamp as a date-time object from the database. Add two minutes to obtain the timeout time. Compare to the current time.
ResultSet rs = yourPreparedStatement.executeQuery();
if (rs.next()) {
OffsetDateTime odt = rs.getObject("your_db_column", OffsetDateTime.class);
OffsetDateTime currentTime = OffsetDateTime.now(odt.getOffset());
OffsetDateTime timeoutOdt = odt.plus(TIMEOUT);
if (currentTime.isAfter(timeoutOdt)) {
System.out.println("Timed out");
}
else {
System.out.println("Not timed out yet");
}
}
I have assumed a TIMEOUT
constant of type Duration
. That's flexible in that it will allow you to define the timeout in minutes or milliseconds or which unit you prefer. For example:
private static final String CONFIGUTRED_TIMEOUT = "PT2M"; // get from configuration
private static final Duration TIMEOUT = Duration.parse(CONFIGUTRED_TIMEOUT);
The configured timeout of PT2M
may look funny. Read as a period of time of 2 minutes. The format is ISO 8601. You may alternatively use for example Duration.ofMinutes(2)
or Duration.ofMillis(120_000)
.
If the datatype in your Oracle database is timestamp with time zone
, which is recommended, you should be able to retrieve it as an OffsetDateTime
as shown. You may also try ZonedDateTime
or Instant
. If the column in the database hasn't got any time zone, retrieve as LocalDateTime
and convert to the proper time zone using its atZone
method.
The date and time classes you tried to use, Date
, DateFormat
, SimpleDateFormat
, TimeZone
and Timestamp
, are all poorly designed and all long outdated. Avoid using those.
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