Add Row Number to This T-SQL Query

Add a row number to result set of a SQL query

The typical pattern would be as follows, but you need to actually define how the ordering should be applied (since a table is, by definition, an unordered bag of rows). One way to do that if you don't care about a specific order otherwise is to use the leading key(s) of a covering index, the leading key(s) of the clustered index, or the columns in any group by / order by clauses. In this case I'll assume A is the single-column clustering key for t:

SELECT t.A, t.B, t.C, number = ROW_NUMBER() OVER (ORDER BY t.A)
  FROM dbo.tableZ AS t
  ORDER BY t.A;

If you truly don't care about order, you can generate arbitrary/nondeterministic row numbering using:

ROW_NUMBER() OVER (ORDER BY @@SPID)

-- or for serial plans

ROW_NUMBER() OVER (ORDER BY @@TRANCOUNT)

Little tricks I picked up from Paul White in this article (see "Paul's Solution").

Not sure what the variables in your question are supposed to represent (they don't match).

Add row number to this T-SQL query

Add: ROW_NUMBER() OVER (ORDER BY NumCars)

EDIT:

WITH    t1 AS 
( SELECT DISTINCT
            VehicleSpecs.SubmittedById ,
            COUNT(VehicleSpecs.SubmittedById) AS NumCars ,
            aspnet_Users.UserName
   FROM     VehicleSpecs
            INNER JOIN aspnet_Users ON VehicleSpecs.SubmittedById = aspnet_Users.UserId
   WHERE    ( LEN(VehicleSpecs.SubmittedById) > 0 )
   GROUP BY VehicleSpecs.SubmittedById ,
            aspnet_Users.UserName
)
SELECT  ROW_NUMBER() OVER ( ORDER BY NumCars ), *
FROM    t1
ORDER BY NumCars

Adding Row Number on SQL SELECT

If you are using a programming language, you can keep your SQL simple:

"SELECT username, id, Days FROM Users ORDER BY Days DESC";

Then process the row number using the programming language:

if ($result->num_rows > 0) {
$rowNumber=0;
echo "<table><tr><th>ID</th><th>Name</th><th>Days</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
    $rowNumber++;
    echo "<tr><td>" . $rowNumber "</td><td>" . $row["username"]. "</td><td>" . $row["Days"]. "</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}

How to generate sequential row number in tsql?

There is no need to avoid Analytic Functions if your database supports them e.g ROW_NUMBER()

    SELECT
        ROW_NUMBER() OVER (ORDER BY [<PRIMARYKEY_COLUMN_NAME>]) AS Number
    FROM
        [<TABLE_NAME>]

The syntax is Func([ arguments ]) OVER (analytic_clause) you need to focus on OVER (). This last parentheses make partition(s) of your rows and apply the Func() on these partitions one by one. In above code we have only single set/partition of rows. Therefore the generated sequence is for all the rows.

You can make multiple set of your data and generate sequence number for each one in a single go. For example if you need generate sequence number for all the set of rows those have same categoryId. You just need to add Partition By clause like this (PARTITION BY categoryId ORDER BY [<PRIMARYKEY_COLUMN_NAME>]).

Remember that after FROM you can also use another extra ORDER BY to sort your data differently. But it has no effect on the OVER ()

SQL Server Add row number each group

You can assign groups to adjacent pay types that are the same and then use row_number(). For this purpose, the difference of row numbers is a good way to determine the groups:

select row_number() over (partition by pay_type, seqnum - seqnum_2 order by serial_no) as row_no,
       t.*
from (select t.*,
             row_number() over (order by serial_no) as seqnum,
             row_number() over (partition by pay_type order by serial_no) as seqnum_2
      from t
     ) t;

This type of problem is one example of a gaps-and-islands problem. Why does the difference of row numbers work? I find that the simplest way to understand is to look at the results of the subquery.

Here is a db<>fiddle.

SQL Update with row_number()

With UpdateData  As
(
SELECT RS_NOM,
ROW_NUMBER() OVER (ORDER BY [RS_NOM] DESC) AS RN
FROM DESTINATAIRE_TEMP
)
UPDATE DESTINATAIRE_TEMP SET CODE_DEST = RN
FROM DESTINATAIRE_TEMP
INNER JOIN UpdateData ON DESTINATAIRE_TEMP.RS_NOM = UpdateData.RS_NOM

How to insert a record to table with row number in Transact-SQL?

SQL Server can generate auto-increment numbers for you, using the Identity property.

You can't change an existing column to an identity column (or an identity column to a "regular" column) using an ALTER TABLE statement, but you can drop the existing id column and re-create it as an identity column:

ALTER TABLE [dbo].[sometable]
    DROP COLUMN Id;

ALTER TABLE [dbo].[sometable]
    ADD Id int IDENTITY(1,1);

Please note that identity columns should not have business meaning, as SQL Server only guarantees to automatically generate them. They are not guaranteed to have no gaps, and they are not guaranteed to be unique.

SQL Server will not reuse values that have already been generated, even if the insert statement that generated them failed, but there is a command to reset the identity column so the next time a row is inserted to the database, the identity will start from a new seed. This means that it's possible for an identity column to have duplicate values.

Increase Row Number when ever Product is encountered - T SQL - Single Query (More than one statement not allowed)

It looks like you want a cumulative sum of "product":

select t.*,
       sum(case when val = 'Product' then 1 else 0 end) over (order by id) as rwnum
from t;

Add row number as a new column in SQL Server

Isn't it simply:

Select 
    ROW_NUMBER() OVER (ORDER BY CASE 
                                   WHEN VGID = 165 then 1    
                                   WHEN VGID = 158 then 2 
                                   WHEN VGID = 159 then 3 
                                   WHEN VGID = 157 then 4 
                                   WHEN VGID = 156 then 5 
                                END) AS RowNumber
    , * 
    from T_EMS_VGDM_RULEMST 
    where VGID in (156,157,158,159,165) 
    ORDER BY CASE 
     WHEN VGID = 165 then 1    
     WHEN VGID = 158 then 2 
     WHEN VGID = 159 then 3 
     WHEN VGID = 157 then 4 
     WHEN VGID = 156 then 5 
    END

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