How to Get Today's Date in Ruby 1.9.3

How to get today's date in Ruby 1.9.3?

Did you require 'date' ?

> require 'date'
 => true
> Date.today
 => #<Date: 2013-03-12 ((2456364j,0s,0n),+0s,2299161j)>

Get today's date in Jekyll with Liquid markup

It didn't work for me either. It appears you've hit a current bug in the Ruby 1.9.3 support. There is a pull request that fixes the bug, but it's not incorporated yet. A workaround is listed, perhaps it will work for you:

{{ site.time | date: '%y' }}

Differences in date string parsing between Ruby 1.9.3 and Ruby 1.8.7

Would it be an option for you to use Time.strptime("01/28/2012", "%m/%d/%Y") in place of Time.parse? That way you have better control over how Ruby is going to parse the date.

If not there are gems: (e.g. ruby-american_date) to make the Ruby 1.9 Time.parse behave like Ruby 1.8.7, but only use it if it's absolutely necessary.

1.9.3-p0 :002 > Time.parse '01/28/2012'
ArgumentError: argument out of range

1.9.3-p0 :003 > require 'american_date'
1.9.3-p0 :004 > Time.parse '01/28/2012'
 => 2012-01-28 00:00:00 +0000 

How do I get a range or array for every minute in a day in Ruby 1.9.3?

This might get you started:

0.upto((60 * 24) - 1).each { |m| puts "%02d:%02d:00" % [m / 60, m % 60] }

Ruby find next Thursday (or any day of the week)

DateTime.now.next_week.next_day(3)

As @Nils Riedemann pointed out:

Keep in mind that it will not get the next thursday, but the thursday
of the next week. eg. If tomorrow was thursday, it won't return
tomorrow, but next week's thursdays.

Here is an excerpt of some code I've written recently which handles the missing case.

require 'date'

module DateTimeMixin

  def next_week
    self + (7 - self.wday)
  end

  def next_wday (n)
    n > self.wday ? self + (n - self.wday) : self.next_week.next_day(n)
  end

end

# Example

ruby-1.9.3-p194 :001 > x = DateTime.now.extend(DateTimeMixin)
 => #<DateTime: 2012-10-19T15:46:57-05:00 ... > 

ruby-1.9.3-p194 :002 > x.next_week
 => #<DateTime: 2012-10-21T15:46:57-05:00 ... > 

ruby-1.9.3-p194 :003 > x.next_wday(4)
 => #<DateTime: 2012-10-25T15:46:57-05:00 ... > 

ruby DateTime parsing from 'mm/dd/yyyy' format

require 'date'
my_date = Date.strptime("12/22/2011", "%m/%d/%Y")

How can I create a new Date instance in Ruby

According to Date documentation:

require 'date'

Date.new(2001,2,25)           #=> #<Date: 2001-02-25 
Date.jd(2451966)             #=> #<Date: 2001-02-25 
Date.ordinal(2001,56)        #=> #<Date: 2001-02-25 
Date.commercial(2001,8,7)    #=> #<Date: 2001-02-25 
Date.parse('2001-02-25')     #=> #<Date: 2001-02-25 
Date.strptime('25-02-2001', '%d-%m-%Y') #=> #<Date: 2001-02-25 
Time.new(2001,2,25).to_date   #=> #<Date: 2001-02-25 

Name of this month (Date.today.month as name)

Date::MONTHNAMES[Date.today.month] would give you "January". (You may need to require 'date' first).

How to know if today's date is in a date range?

Use ===

Actually, there is an operator that will do this. Make a Range and compare Time objects to it using the === operator.

start   = Time.now.to_i

range   = start..(start + 2)
inside  = start + 1
outside = start + 3        # ok, now...

range === inside  # true
range === outside # false

1.9.3p125 :014 > d = Date.parse "Mon, 03 Dec 2012"
 => Mon, 03 Dec 2012 
1.9.3p125 :015 > Date.commercial d.cwyear, d.cweek, 4
 => Thu, 06 Dec 2012 
1.9.3p125 :016 >