Convert Non-Breaking Spaces to Spaces in Ruby

How do I remove a non-breaking space in Ruby

irb(main):001:0> d = "foo\u00A0\bar"
=> "foo \bar"
irb(main):002:0> d.gsub("\u00A0", "")
=> "foo\bar"

Convert non-breaking spaces to spaces in Ruby

For the old versions of ruby (1.8.x), the fixes are the ones described in the question.

This is fixed in the newer versions of ruby 1.9+.

Change all   to normal blank space Ruby

Yes, Your changes aren't working in the first place, as you have used wrong pattern, You are supposed to add an "\" before an special character which in your case is "&".

So try this:

courses = Course.all
courses.each {|course| course.shortname.gsub!(/\ /," ")}

  is same as ASCII code 160, so

courses = Course.all
courses.each {|course| course.shortname.gsub!(160.chr("UTF-8")," ")}

Also while trying i noticed the   is same as "\u00A0" as i got an error as undefined method `html' for "\u00A0":String. I don't know what it is but this might also works,

courses = Course.all
courses.each {|course| course.shortname.gsub!("/\u00a0/", "")}

Converting non-breaking spaces to regular spaces in an encoded Ruby string

Try string.gsub("\u00A0", " ")

How do I split a string on non-traditional white-space?

I suggest using

/[ \u00A0]*(?:[[:space:]&&[^ \u00A0]][ \u00A0]*)+|[[:space:]]{2,}/

See the regex demo.

Although it seems \s can match any Unicode whitespace if the pattern is prepended with (?u), [[:space:]] seems to be a more adopted way to match any Unicode whitespace.

Details:

The pattern has 2 branches that match either...

• [ \u00A0]*(?:[[:space:]&&[^ \u00A0]][ \u00A0]*)+ - a chunk of whitespaces that contain at least 1 non-space/non-nonbreaking space
  
  
  • [ \u00A0]* - zero or more occurrences of a regular or non-breaking spaces
  • (?:[[:space:]&&[^ \u00A0]][ \u00A0]*)+ - one or more occurrences of:
    
    
    • [[:space:]&&[^ \u00A0]] - (a character class subtraction) any whitespace with the exception of a regular/non-breaking whitespace
    • [ \u00A0]* - zero or more regular/non-breaking whitespaces
• | - or
• [[:space:]]{2,} - 2 or more any whitespace symbols

Ruby regexp handling of nbsp

Use Unicode properties (you need to declare a matching source code encoding for this to work):

# encoding=utf-8 
if subject ~= /\p{Z}/
    # subject contains whitespace or other separators

or use POSIX character classes:

if subject ~= /[[:space:]]/

According to the docs, \s will only match [ \t\r\n\f] now and in the future.

How do I replace consecutive occurrences of white space in each element of my array?

Do it with simple gsub not gsub!

words.map do |w|
  #respond_to?(:gsub) if you are not sure that array only from strings
  w.gsub(/(?<=[^\,\.])\s+|\A\s+/, '') if w.respond_to?(:gsub)
end

Because gsub! can return nil if don't change the string and then you try to do gsub! again with nil. That's why you get an undefined method gsub!' for nil:NilClass error.

From gsub! explanation in ruby doc:

Performs the substitutions of String#gsub in place, returning str, or
nil if no substitutions were performed. If no block and no replacement
is given, an enumerator is returned instead.

As mentioned @CarySwoveland in comments \s doesn't handle non-breaking spaces. To handle it you should use [[:space:]] insted of \s.

Ruby 1.9 strip not removing whitespace

I think, there are a lot of "space characters".
You can use something like this:

my_string.gsub("\302\240", ' ').strip

Non-breaking space between lines

How did you use succeed? Where did the space end up?

Did you combine it with the whitespace removal chars ("<" and ">") or try them on their own?

= succeed ' '.html_safe do
  = 'foo'
%a(href='http://example.com')> bar

This produces:

foo <a href='http://example.com'>bar</a>

Is that literally what you want? It is "two lines joined by a non-breaking space with no actual space."

(IMO, HAML is meh for inline content, and just no fun. Nice for layout.)

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