How to calculate cumulative sum?
# replace the second column for the cumsum of the initial second column
data[, 2] <- cumsum(data[, 2])
Vector of cumulative sums in R
Please correct me if I'm misunderstanding, but I believe you simply want this:
I <- cumsum(sqrt(1 - U^2))
It is unclear why you want to use for
loops.
Cumulative sums in R
Try outer
> sum(outer(1:10, 1:5, FUN = function(i,j) i^5/(10+j^i)))
[1] 20845.76
Using tapply and cumsum function for multiple vectors in R
if there are more than one group, wrap it in a list
, but note that tapply
in a summarising function and it can split up when we specify function like cumsum
.
tapply(date_country$n, list(date_country$country, date_country$pangolin_lineage), cumsum))
But, this is much more easier with ave
i.e. if we want to create a new column, avoid the hassle of unlist
etc. by just using ave
ave(date_country$n, date_country$country,
date_country$pangolin_lineage, FUN = cumsum)
#[1] 1 2 3 1 4 1
Cumulative sum in R by group and start over when sum of values in group larger than maximum value
One purrr
approach could be:
cumsum(c(FALSE, diff(accumulate(test, ~ ifelse(.x >= 10, .y, .x + .y))) <= 0))
[1] 0 0 1 1 1 2 2 2 3
R: Cumulative sum if difference over threshold
I would do this with a logical index used for subsetting. It should be true for all elements of x that shall be "cumsumed" and false for the rest.
idx <- x >= day_vec
Now you can use it to compute the cumsum and assign it to the correct elements in x:
x[idx] <- cumsum(x[idx])
x
#[1] 0 0 31 61 0 15 16
How to cumsum the elements of a vector under certain condition in R?
A base R option with Reduce
> Reduce(function(x, y) ifelse(x * y > 0, x + y, y), vector_A, accumulate = TRUE)
[1] 1 2 -1 -2 -3 1 -1 -2 1 -1
or using ave
+ cumsum
> ave(vector_A, cumsum(c(1, diff(sign(vector_A)) != 0)), FUN = cumsum)
[1] 1 2 -1 -2 -3 1 -1 -2 1 -1
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