Treat Na as Zero Only When Adding a Number

Treat NA as zero only when adding a number

You can define your own function to act as you want

plus <- function(x) {
 if(all(is.na(x))){
   c(x[0],NA)} else {
   sum(x,na.rm = TRUE)}
 }

rbind(dt1, dt2)[,lapply(.SD, plus), by = Name]

R programming - treat NA in a file as 0

Something like this?

sum(arch1, na.rm = T)/length(arch1)

Set NA to 0 in R

You can just use the output of is.na to replace directly with subsetting:

bothbeams.data[is.na(bothbeams.data)] <- 0

Or with a reproducible example:

dfr <- data.frame(x=c(1:3,NA),y=c(NA,4:6))
dfr[is.na(dfr)] <- 0
dfr
  x y
1 1 0
2 2 4
3 3 5
4 0 6

However, be careful using this method on a data frame containing factors that also have missing values:

> d <- data.frame(x = c(NA,2,3),y = c("a",NA,"c"))
> d[is.na(d)] <- 0
Warning message:
In `[<-.factor`(`*tmp*`, thisvar, value = 0) :
  invalid factor level, NA generated

It "works":

> d
  x    y
1 0    a
2 2 <NA>
3 3    c

...but you likely will want to specifically alter only the numeric columns in this case, rather than the whole data frame. See, eg, the answer below using dplyr::mutate_if.

Sum to 0 if vector includes NAs and 0?

The checks in this answer can be extended to

plus <- function(...) {
 if(all(is.na(do.call(c, list(...))))){
   NA} else {
   sum(...,na.rm = TRUE)}
 }
plus(c(NA, 3), 1:5)
# [1] 18

How to Sum NA (text NA) values in excel with numbers by treating NA as 1

By default COUNTIF counts specific cells and returns a number. This gives you the ability to type in D1 (or D2):

=COUNTIF(A3:C3,"NA")+SUM(A3:C3)

Which counts the number of cells that contain "NA" and then adds the sum of the numbers.

You can then drag the formula down to apply the same logic to all rows.

R aggregation with sum function gives the value 0 when it sums NA

all you need is to remove the na.rm=T

  agg2<-  aggregate(y ~ x, data = df, sum, na.action=na.pass)

and this is the result :

> agg2
  x  y
1 a 66
2 b NA
3 c 98

How do I replace NA values with zeros in an R dataframe?

See my comment in @gsk3 answer. A simple example:

> m <- matrix(sample(c(NA, 1:10), 100, replace = TRUE), 10)
> d <- as.data.frame(m)
   V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
1   4  3 NA  3  7  6  6 10  6   5
2   9  8  9  5 10 NA  2  1  7   2
3   1  1  6  3  6 NA  1  4  1   6
4  NA  4 NA  7 10  2 NA  4  1   8
5   1  2  4 NA  2  6  2  6  7   4
6  NA  3 NA NA 10  2  1 10  8   4
7   4  4  9 10  9  8  9  4 10  NA
8   5  8  3  2  1  4  5  9  4   7
9   3  9 10  1  9  9 10  5  3   3
10  4  2  2  5 NA  9  7  2  5   5

> d[is.na(d)] <- 0

> d
   V1 V2 V3 V4 V5 V6 V7 V8 V9 V10
1   4  3  0  3  7  6  6 10  6   5
2   9  8  9  5 10  0  2  1  7   2
3   1  1  6  3  6  0  1  4  1   6
4   0  4  0  7 10  2  0  4  1   8
5   1  2  4  0  2  6  2  6  7   4
6   0  3  0  0 10  2  1 10  8   4
7   4  4  9 10  9  8  9  4 10   0
8   5  8  3  2  1  4  5  9  4   7
9   3  9 10  1  9  9 10  5  3   3
10  4  2  2  5  0  9  7  2  5   5

There's no need to apply apply. =)

EDIT

You should also take a look at norm package. It has a lot of nice features for missing data analysis. =)

Sum of two Columns of Data Frame with NA Values

dat$e <- rowSums(dat[,c("b", "c")], na.rm=TRUE)
dat
#   a  b c d e
# 1 1  2 3 4 5
# 2 5 NA 7 8 7

Replace all 0 values to NA

Replacing all zeroes to NA:

df[df == 0] <- NA

Explanation

1. It is not NULL what you should want to replace zeroes with. As it says in ?'NULL',

NULL represents the null object in R

which is unique and, I guess, can be seen as the most uninformative and empty object.¹ Then it becomes not so surprising that

data.frame(x = c(1, NULL, 2))
#   x
# 1 1
# 2 2

That is, R does not reserve any space for this null object.² Meanwhile, looking at ?'NA' we see that

NA is a logical constant of length 1 which contains a missing value
indicator. NA can be coerced to any other vector type except raw.

Importantly, NA is of length 1 so that R reserves some space for it. E.g.,

data.frame(x = c(1, NA, 2))
#    x
# 1  1
# 2 NA
# 3  2

Also, the data frame structure requires all the columns to have the same number of elements so that there can be no "holes" (i.e., NULL values).

Now you could replace zeroes by NULL in a data frame in the sense of completely removing all the rows containing at least one zero. When using, e.g., var, cov, or cor, that is actually equivalent to first replacing zeroes with NA and setting the value of use as "complete.obs". Typically, however, this is unsatisfactory as it leads to extra information loss.

2. Instead of running some sort of loop, in the solution I use df == 0 vectorization. df == 0 returns (try it) a matrix of the same size as df, with the entries TRUE and FALSE. Further, we are also allowed to pass this matrix to the subsetting [...] (see ?'['). Lastly, while the result of df[df == 0] is perfectly intuitive, it may seem strange that df[df == 0] <- NA gives the desired effect. The assignment operator <- is indeed not always so smart and does not work in this way with some other objects, but it does so with data frames; see ?'<-'.

_{¹ The empty set in the set theory feels somehow related.
² Another similarity with the set theory: the empty set is a subset of every set, but we do not reserve any space for it.}

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