How to Get Last Data for Each Id/Date

How to select the last record of each ID

You can use a window function called ROW_NUMBER.Here is a solution for you given below. I have also made a demo query in db-fiddle for you. Please check link Demo Code in DB-Fiddle

WITH CTE AS
(SELECT product, user_id,
       ROW_NUMBER() OVER(PARTITION BY user_id order by product desc)
       as RN
FROM Mytable)
SELECT product, user_id FROM CTE WHERE RN=1 ;

Select last record of each month for each ID

With ROW_NUMBER() window function:

SELECT ID, date, data
FROM (
  SELECT *,
    ROW_NUMBER() OVER (PARTITION BY ID, strftime('%Y%m', date) ORDER BY date DESC) rn
  FROM myTable 
)
WHERE rn = 1

Get most recent date for each id

select ID, Max(Date) as Date 
from yourtable
group by ID

how do I query sql for a latest record date for each user

select t.username, t.date, t.value
from MyTable t
inner join (
    select username, max(date) as MaxDate
    from MyTable
    group by username
) tm on t.username = tm.username and t.date = tm.MaxDate

select rows in sql with latest date for each ID repeated multiple times

This question has been asked before. Please see this question.

Using the accepted answer and adapting it to your problem you get:

SELECT tt.*
FROM myTable tt
INNER JOIN
    (SELECT ID, MAX(Date) AS MaxDateTime
    FROM myTable
    GROUP BY ID) groupedtt 
ON tt.ID = groupedtt.ID 
AND tt.Date = groupedtt.MaxDateTime

How to get last data for each id/date?

You can do this pretty easily using data.table syntax...

#  Load package
require( data.table )

#  Turn 'data.frame' into 'data.table'
dt <- data.table( df )

#  Make dates from date/time
dt[ , Date:= as.Date( Tpt_DateTime ) ]

#  Get last row of each group
dt[ , .SD[.N] ,  by = c("Tpt_ID" , "Date") ]
#   Tpt_ID       Date        Tpt_DateTime Value
#1:      1 2013-01-01 2013-01-01 11:17:21    21
#2:      2 2013-01-01 2013-01-01 07:18:32     5
#3:      3 2013-01-01 2013-01-01 08:00:02     1
#4:      1 2013-01-02 2013-01-02 07:10:11    15
#5:      2 2013-02-02 2013-02-02 12:18:32     8
#6:      3 2013-02-03 2013-02-03 14:00:02     3

• First we turn your data-time data into a date with Date :=
as.Date( Tpt_DateTime )

• Then we use .SD to get a subset of X's data for each group. .N contains the number of row for each group, so .SD[.N] gives us the last row for each group.

• Lastly, the by=c("Tpt_ID" , "Date") defines the groups.

Find the first AND last date that an ID occured in dataset SQL

Simply do a GROUP BY. Use MIN() and MAX() to get first and last date.

select OrderID,
       MIN(SnapShotDate) as FirstDateOccuring,
       MAX(SnapShotDate) as LastDateOccuring 
from tablename
group by OrderID

Postgresql extract last row for each id

The most efficient way is to use Postgres' distinct on operator

select distinct on (id) id, date, another_info
from the_table
order by id, date desc;

If you want a solution that works across databases (but is less efficient) you can use a window function:

select id, date, another_info
from (
  select id, date, another_info, 
         row_number() over (partition by id order by date desc) as rn
  from the_table
) t
where rn = 1
order by id;

The solution with a window function is in most cases faster than using a sub-query.

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