Assign a Value, If a Number Is in Between Two Numbers

R - assigning test (in ifelse) to be between two numbers for generating a dummy variable

Try %in%

data$light <- ifelse(data$cigs %in% c(1:5), 1, 0)

Or equivalently

data$light <- ifelse(data$cigs >=1& data$cigs <=5, 1, 0)

Check if a variable is between two numbers with Java

I see some errors in your code.

Your probably meant the mathematical term

90 <= angle <= 180, meaning angle in range 90-180.

if (angle >= 90 && angle <= 180) {

// do action
}

Assigning a value if between two variables, across data frames in R

If I understand correctly (and assuming that regions lower and upper bounds exhaust the range of values you need to classify and are exclusive), then this should be an analogous example

library(dplyr)
library(purrr)

set.seed(1)
x = tibble(value=abs(rnorm(10, 0, 5)))
bounds = tibble(lower = c(0:6), upper = c(1:6, Inf), class = letters[1:7])

x$class <- bounds[map_int(x$value, function(z) {which(map_lgl(seq_len(nrow(bounds)), ~between(z, bounds$lower[.x], bounds$upper[.x])  ))}),3]
x
#> # A tibble: 10 x 2
#>    value class$class
#>    <dbl> <chr>      
#>  1 3.13  d          
#>  2 0.918 a          
#>  3 4.18  e          
#>  4 7.98  g          
#>  5 1.65  b          
#>  6 4.10  e          
#>  7 2.44  c          
#>  8 3.69  d          
#>  9 2.88  c          
#> 10 1.53  b

Created on 2019-11-24 by the reprex package (v0.3.0)

How to check if a number is between two values?

Tests whether windowsize is greater than 500 and lesser than 600 meaning that neither values 500 or 600 itself will result in the condition becoming true.

if (windowsize > 500 && windowsize < 600) {
  // ...
}

Objective-C: How to check a number is between two values

Unless your compiler is broken there is nothing wrong with that code. There is probably something wrong with x

As Sascha stated in the comments make sure that x is not an NSNumber. The reason for this is if x is an NSNumber then the value stored in it is a pointer which value would likely be much higher than 100 (0x4FBC60 for example) and you would want to compare against the -(int)intValue.

Other things to consider are comparing against the right data. While implicit number conversions work well you may want to use the same literal comparison as your data type.

unsigned long long x = 51ull;
if(x > 50ull && x < 100ull)
{

}

Determine whether integer is between two other integers

if 10000 <= number <= 30000:
    pass

For details, see the docs.

How can I assign a number to X, if X is in a range of numbers?

Come to think of it, you can do this without any looping at all, still assuming the ranges you provided.

Thanks to @TedHopp for my math error fix!

const values = [26, 35, 12, 28, 7, 29];

var x = 55;

x = x ? (values[Math.ceil(x/10)-1] || x) : values[0];

console.log(x);

How to elegantly check if a number is within a range?

There are a lot of options:

int x = 30;
if (Enumerable.Range(1,100).Contains(x))  //true

And indeed basic if more elegantly can be written with reversing order in the first check:

if (1 <= x && x <= 100)   //true

Also, check out this SO post for regex options.

Notes:

• LINQ solution is strictly for style points - since Contains iterates over all items its complexity is O(range_size) and not O(1) normally expected from a range check.
  
  More generic version for other ranges (notice that second argument is count, not end):

  if (Enumerable.Range(start, end - start + 1).Contains(x)
  

• There is temptation to write if solution without && like 1 <= x <= 100 - that look really elegant, but in C# leads to a syntax error "Operator '<=' cannot be applied to operands of type 'bool' and 'int'"

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