Why Isn't My Pandas 'Apply' Function Referencing Multiple Columns Working

Why isn't my Pandas 'apply' function referencing multiple columns working?

Seems you forgot the '' of your string.

In [43]: df['Value'] = df.apply(lambda row: my_test(row['a'], row['c']), axis=1)

In [44]: df
Out[44]:
                    a    b         c     Value
          0 -1.674308  foo  0.343801  0.044698
          1 -2.163236  bar -2.046438 -0.116798
          2 -0.199115  foo -0.458050 -0.199115
          3  0.918646  bar -0.007185 -0.001006
          4  1.336830  foo  0.534292  0.268245
          5  0.976844  bar -0.773630 -0.570417

BTW, in my opinion, following way is more elegant:

In [53]: def my_test2(row):
....:     return row['a'] % row['c']
....:     

In [54]: df['Value'] = df.apply(my_test2, axis=1)

Return multiple columns from pandas apply()

You can return a Series from the applied function that contains the new data, preventing the need to iterate three times. Passing axis=1 to the apply function applies the function sizes to each row of the dataframe, returning a series to add to a new dataframe. This series, s, contains the new values, as well as the original data.

def sizes(s):
    s['size_kb'] = locale.format("%.1f", s['size'] / 1024.0, grouping=True) + ' KB'
    s['size_mb'] = locale.format("%.1f", s['size'] / 1024.0 ** 2, grouping=True) + ' MB'
    s['size_gb'] = locale.format("%.1f", s['size'] / 1024.0 ** 3, grouping=True) + ' GB'
    return s

df_test = df_test.append(rows_list)
df_test = df_test.apply(sizes, axis=1)

Apply function with multiple argument to multiple columns to create a new column

Maybe this:

data['lower_bound_a']=data.apply(lambda x: ci_lower_bound(x['won_A'], x['lost_A']),axis=1)
print(data)

Pandas apply function isn't working and without any error

I think you wanted:

df['text'] = df['text'].apply(cleanText)

(if you want just one column "cleaned", apply the function to this column only).

How to apply lambda function on multiple columns using pandas

You're looking for .applymap:

prices[list_of_columns].applymap(lambda x: float(x))

Also, if you're really trying to just convert the values into floats, just use .astype:

prices[list_of_colums] = prices[list_of_columns].astype(float)

When should I (not) want to use pandas apply() in my code?

apply, the Convenience Function you Never Needed

We start by addressing the questions in the OP, one by one.

"If apply is so bad, then why is it in the API?"

DataFrame.apply and Series.apply are convenience functions defined on DataFrame and Series object respectively. apply accepts any user defined function that applies a transformation/aggregation on a DataFrame. apply is effectively a silver bullet that does whatever any existing pandas function cannot do.

Some of the things apply can do:

• Run any user-defined function on a DataFrame or Series
• Apply a function either row-wise (axis=1) or column-wise (axis=0) on a DataFrame
• Perform index alignment while applying the function
• Perform aggregation with user-defined functions (however, we usually prefer agg or transform in these cases)
• Perform element-wise transformations
• Broadcast aggregated results to original rows (see the result_type argument).
• Accept positional/keyword arguments to pass to the user-defined functions.

...Among others. For more information, see Row or Column-wise Function Application in the documentation.

So, with all these features, why is apply bad? It is because apply is slow. Pandas makes no assumptions about the nature of your function, and so iteratively applies your function to each row/column as necessary. Additionally, handling all of the situations above means apply incurs some major overhead at each iteration. Further, apply consumes a lot more memory, which is a challenge for memory bounded applications.

There are very few situations where apply is appropriate to use (more on that below). If you're not sure whether you should be using apply, you probably shouldn't.

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Let's address the next question.

"How and when should I make my code apply-free?"

To rephrase, here are some common situations where you will want to get rid of any calls to apply.

Numeric Data

If you're working with numeric data, there is likely already a vectorized cython function that does exactly what you're trying to do (if not, please either ask a question on Stack Overflow or open a feature request on GitHub).

Contrast the performance of apply for a simple addition operation.

df = pd.DataFrame({"A": [9, 4, 2, 1], "B": [12, 7, 5, 4]})
df

   A   B
0  9  12
1  4   7
2  2   5
3  1   4

<!- ->

df.apply(np.sum)

A    16
B    28
dtype: int64

df.sum()

A    16
B    28
dtype: int64

Performance wise, there's no comparison, the cythonized equivalent is much faster. There's no need for a graph, because the difference is obvious even for toy data.

%timeit df.apply(np.sum)
%timeit df.sum()
2.22 ms ± 41.2 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
471 µs ± 8.16 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)

Even if you enable passing raw arrays with the raw argument, it's still twice as slow.

%timeit df.apply(np.sum, raw=True)
840 µs ± 691 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

Another example:

df.apply(lambda x: x.max() - x.min())

A    8
B    8
dtype: int64

df.max() - df.min()

A    8
B    8
dtype: int64

%timeit df.apply(lambda x: x.max() - x.min())
%timeit df.max() - df.min()

2.43 ms ± 450 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
1.23 ms ± 14.7 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)

In general, seek out vectorized alternatives if possible.

---

String/Regex

Pandas provides "vectorized" string functions in most situations, but there are rare cases where those functions do not... "apply", so to speak.

A common problem is to check whether a value in a column is present in another column of the same row.

df = pd.DataFrame({
    'Name': ['mickey', 'donald', 'minnie'],
    'Title': ['wonderland', "welcome to donald's castle", 'Minnie mouse clubhouse'],
    'Value': [20, 10, 86]})
df

     Name  Value                       Title
0  mickey     20                  wonderland
1  donald     10  welcome to donald's castle
2  minnie     86      Minnie mouse clubhouse

This should return the row second and third row, since "donald" and "minnie" are present in their respective "Title" columns.

Using apply, this would be done using

df.apply(lambda x: x['Name'].lower() in x['Title'].lower(), axis=1)

0    False
1     True
2     True
dtype: bool
 
df[df.apply(lambda x: x['Name'].lower() in x['Title'].lower(), axis=1)]

     Name                       Title  Value
1  donald  welcome to donald's castle     10
2  minnie      Minnie mouse clubhouse     86

However, a better solution exists using list comprehensions.

df[[y.lower() in x.lower() for x, y in zip(df['Title'], df['Name'])]]

     Name                       Title  Value
1  donald  welcome to donald's castle     10
2  minnie      Minnie mouse clubhouse     86

<!- ->

%timeit df[df.apply(lambda x: x['Name'].lower() in x['Title'].lower(), axis=1)]
%timeit df[[y.lower() in x.lower() for x, y in zip(df['Title'], df['Name'])]]

2.85 ms ± 38.4 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
788 µs ± 16.4 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)

The thing to note here is that iterative routines happen to be faster than apply, because of the lower overhead. If you need to handle NaNs and invalid dtypes, you can build on this using a custom function you can then call with arguments inside the list comprehension.

For more information on when list comprehensions should be considered a good option, see my writeup: Are for-loops in pandas really bad? When should I care?.

Note

Date and datetime operations also have vectorized versions. So, for example, you should prefer pd.to_datetime(df['date']), over,
say, df['date'].apply(pd.to_datetime).

Read more at the
docs.

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A Common Pitfall: Exploding Columns of Lists

s = pd.Series([[1, 2]] * 3)
s

0    [1, 2]
1    [1, 2]
2    [1, 2]
dtype: object

People are tempted to use apply(pd.Series). This is horrible in terms of performance.

s.apply(pd.Series)

   0  1
0  1  2
1  1  2
2  1  2

A better option is to listify the column and pass it to pd.DataFrame.

pd.DataFrame(s.tolist())

   0  1
0  1  2
1  1  2
2  1  2

<!- ->

%timeit s.apply(pd.Series)
%timeit pd.DataFrame(s.tolist())

2.65 ms ± 294 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
816 µs ± 40.5 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)

---

---

Lastly,

"Are there any situations where apply is good?"

Apply is a convenience function, so there are situations where the overhead is negligible enough to forgive. It really depends on how many times the function is called.

Functions that are Vectorized for Series, but not DataFrames

What if you want to apply a string operation on multiple columns? What if you want to convert multiple columns to datetime? These functions are vectorized for Series only, so they must be applied over each column that you want to convert/operate on.

df = pd.DataFrame(
         pd.date_range('2018-12-31','2019-01-31', freq='2D').date.astype(str).reshape(-1, 2), 
         columns=['date1', 'date2'])
df

       date1      date2
0 2018-12-31 2019-01-02
1 2019-01-04 2019-01-06
2 2019-01-08 2019-01-10
3 2019-01-12 2019-01-14
4 2019-01-16 2019-01-18
5 2019-01-20 2019-01-22
6 2019-01-24 2019-01-26
7 2019-01-28 2019-01-30

df.dtypes

date1    object
date2    object
dtype: object
    

This is an admissible case for apply:

df.apply(pd.to_datetime, errors='coerce').dtypes

date1    datetime64[ns]
date2    datetime64[ns]
dtype: object

Note that it would also make sense to stack, or just use an explicit loop. All these options are slightly faster than using apply, but the difference is small enough to forgive.

%timeit df.apply(pd.to_datetime, errors='coerce')
%timeit pd.to_datetime(df.stack(), errors='coerce').unstack()
%timeit pd.concat([pd.to_datetime(df[c], errors='coerce') for c in df], axis=1)
%timeit for c in df.columns: df[c] = pd.to_datetime(df[c], errors='coerce')

5.49 ms ± 247 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
3.94 ms ± 48.1 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
3.16 ms ± 216 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
2.41 ms ± 1.71 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

You can make a similar case for other operations such as string operations, or conversion to category.

u = df.apply(lambda x: x.str.contains(...))
v = df.apply(lambda x: x.astype(category))

v/s

u = pd.concat([df[c].str.contains(...) for c in df], axis=1)
v = df.copy()
for c in df:
    v[c] = df[c].astype(category)

And so on...

---

Converting Series to str: astype versus apply

This seems like an idiosyncrasy of the API. Using apply to convert integers in a Series to string is comparable (and sometimes faster) than using astype.

The graph was plotted using the perfplot library.

import perfplot

perfplot.show(
    setup=lambda n: pd.Series(np.random.randint(0, n, n)),
    kernels=[
        lambda s: s.astype(str),
        lambda s: s.apply(str)
    ],
    labels=['astype', 'apply'],
    n_range=[2**k for k in range(1, 20)],
    xlabel='N',
    logx=True,
    logy=True,
    equality_check=lambda x, y: (x == y).all())

With floats, I see the astype is consistently as fast as, or slightly faster than apply. So this has to do with the fact that the data in the test is integer type.

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GroupBy operations with chained transformations

GroupBy.apply has not been discussed until now, but GroupBy.apply is also an iterative convenience function to handle anything that the existing GroupBy functions do not.

One common requirement is to perform a GroupBy and then two prime operations such as a "lagged cumsum":

df = pd.DataFrame({"A": list('aabcccddee'), "B": [12, 7, 5, 4, 5, 4, 3, 2, 1, 10]})
df

   A   B
0  a  12
1  a   7
2  b   5
3  c   4
4  c   5
5  c   4
6  d   3
7  d   2
8  e   1
9  e  10

<!- ->

You'd need two successive groupby calls here:

df.groupby('A').B.cumsum().groupby(df.A).shift()
 
0     NaN
1    12.0
2     NaN
3     NaN
4     4.0
5     9.0
6     NaN
7     3.0
8     NaN
9     1.0
Name: B, dtype: float64

Using apply, you can shorten this to a a single call.

df.groupby('A').B.apply(lambda x: x.cumsum().shift())

0     NaN
1    12.0
2     NaN
3     NaN
4     4.0
5     9.0
6     NaN
7     3.0
8     NaN
9     1.0
Name: B, dtype: float64

It is very hard to quantify the performance because it depends on the data. But in general, apply is an acceptable solution if the goal is to reduce a groupby call (because groupby is also quite expensive).

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Other Caveats

Aside from the caveats mentioned above, it is also worth mentioning that apply operates on the first row (or column) twice. This is done to determine whether the function has any side effects. If not, apply may be able to use a fast-path for evaluating the result, else it falls back to a slow implementation.

df = pd.DataFrame({
    'A': [1, 2],
    'B': ['x', 'y']
})

def func(x):
    print(x['A'])
    return x

df.apply(func, axis=1)

# 1
# 1
# 2
   A  B
0  1  x
1  2  y

This behaviour is also seen in GroupBy.apply on pandas versions <0.25 (it was fixed for 0.25, see here for more information.)

Applying a function to two columns of pandas dataframe to get two new columns

You can return a list from your function:

d = pandas.DataFrame({
    "A": [1, 2, 3, 4, 5],
    "B": [8, 88, 0, -8, -88]
})

def foo(row):
    return [row["A"]+row["B"], row["A"]-row["B"]]

>>> d.apply(foo, axis=1)
    A   B
0   9  -7
1  90 -86
2   3   3
3  -4  12
4 -83  93

You can also return a Series. This lets you specify the column names of the return value:

def foo(row):
    return pandas.Series({"X": row["A"]+row["B"], "Y": row["A"]-row["B"]})

>>> d.apply(foo, axis=1)
    X   Y
0   9  -7
1  90 -86
2   3   3
3  -4  12
4 -83  93

Apply a function to modify multiple columns with if else logic

What you try to do is not very consistent with Pandas philosophy. Also, apply is a very inefficient function. You probably should use Numpy where:

import numpy as np
df['comment'] = np.where(df['address'] == 'NY',
                  'call tomorrow', 'Dont call')
df['selection_status'] = np.where(df['address'] == 'NY',
                           'interview scheduled', 'application rejected')

Or boolean indexing:

df.loc[df['address'] == 'NY', ['comment', 'selection_status']] \
         = 'call tomorrow', 'interview scheduled'
df.loc[df['address'] != 'NY', ['comment', 'selection_status']] \
         = 'Dont call', 'application rejected'

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